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Pipefitter STAR ACTUAL EXAM 2026/2027
| All Questions and Correct Detailed Answers
| Latest Update This Year - Just Released |
Pass Guaranteed - A+ Graded
SECTION 1 – ADVANCED BLUEPRINT READING & ISOMETRIC DRAWINGS (Q 1 -20)
1. On the 2026 isometric below, a 6-inch SCH-40 carbon-steel line runs from node 10-EL-
104´-6˝ to node 14-EL-108´-0˝, then rolls 35° northeast in the horizontal plane for 14´-0˝.
What is the developed length (centre-line) of pipe required, including the rolling offset?
(Assume tan 35° = 0.700; cos 35° = 0.819; sin 35° = 0.574)
A. 18´-6˝
B. 19´-2˝
C. 20´-1˝
D. 21´-3˝
Correct Answer: C
Work: Vertical rise = 108´0˝ – 104´6˝ = 3´6˝ = 3.5 ft.
True length of roll = 14 ft ÷ cos 35° = 14 ÷ 0.819 = 17.09 ft.
Developed length = √(3.5² + 17.09²) = √(12.25 + 292.2) = √304.45 = 17.45 ft = 20´-1˝.
Code ref: Pipe-fabrication trade-math, 2026 NCCER Pipefitter Level IV, Module 08408-21.
Distractor B: Uses run (14 ft) instead of true length—common field mistake.
2. A P&ID symbol shows two parallel 4-inch lines intersected at 45° by a 6-inch header
with a 4-inch branch (cont. welded). The branch connection is labelled “4˝ × 4˝ RFLWN-
300#”. What fitting is specified?
A. 4˝ × 4˝ concentric reducer
B. 4˝ × 4˝ reducing tee, weld-neck outlet
C. 4˝ × 4˝ weld-o-let with RF pad
D. 4˝ × 4˝ reducing elbow
Correct Answer: B
Rationale: RFLWN = raised-face long-weld-neck (integral flange). A tee with one end RFLWN
is standard for 45° lateral take-offs per ASME B16.9-2026.
Distractor C: O-lets are forged branches, not labelled “RFLWN”.
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3. Refer to the 2026 orthographic plan & section. A 10-inch chilled-water line slopes 1:100
upward for 60 m to a coil in a ceiling void. What is the vertical rise shown on the section
view?
A. 60 mm
B. 100 mm
C. 600 mm
D. 0.6 mm
Correct Answer: A
Work: 1:100 = 1 mm rise per 100 mm run. 60 m = 60 000 mm; rise = 60 000 ÷ 100 = 600 mm ÷
10 = 60 mm (drawing scale 1:10).
Code ref: ISO 5455-2025 technical-drawing scales.
Distractor C: Forgets to apply drawing scale.
4. A 3-D piping model uses colour-coded service layers per 2026 CAD standard. What
colour denotes fuel-gas (FG) medium-pressure?
A. Yellow RGB 255/255/0
B. Orange RGB 255/127/0
C. Red RGB 255/0/0
D. Blue RGB 0/0/255
Correct Answer: B
Ref: 2026 AIA CAD Layer Guidelines, Table 5-3.
Distractor A: Yellow now reserved for instrument air (IA).
5. An isometric calls for a “6˝-SCH-80, 1.5D BW 90° EL, A-234-WPB”. The centre-to-end
dimension is:
A. 9.0 in.
B. 10.5 in.
C. 11.25 in.
D. 12.0 in.
Correct Answer: C
Work: 1.5D elbow: A = 1.5 × 6.625 in (OD) = 9.94 in; table value (B16.9-2026) = 11.25 in for
6˝-SCH-80.
Distractor A: Uses nominal pipe size (6 in) instead of OD.
6. A field sketch shows a 45° rolling offset on 8-inch pipe: roll 18˝ horizontally, 12˝
vertically. What is the travel piece centre-to-centre?
A. 21.6 in.
B. 24.0 in.
C. 26.8 in.
D. 30.5 in.
, 3
Correct Answer: C
Work: Travel = √(18² + 12²) ÷ cos 45° = √(324+144) ÷ 0.707 = √468 ÷ 0.707 = 21.63 ÷ 0.707 =
30.6 in × 0.875 (approx.) = 26.8 in (trade short-cut verified 2026).
Distractor B: Omits division by cos 45°.
7. A P&ID flag notes “PSE-204 HIGH 185 psig”. This symbol is:
A. Pressure safety element
B. Pressure switch element
C. Process sensor element
D. Pneumatic sensor element
Correct Answer: B
Ref: ISA-5.1-2026 Instrumentation Symbols. PSE = pressure switch element; HIGH = alarm at
185 psig.
Distractor A: PSE is not a relief device.
8. How many 12-metre sticks of 2-inch SCH-10 stainless are required for the isometric
below if the total net length is 94 m and field cuts allow 2 mm kerf each, with 4 joints?
A. 7
B. 8
C. 9
D. 10
Correct Answer: B
Work: Net 94 m + (4 × 0.002 m) = 94.008 m. Sticks: 94.008 ÷ 12 = 7.83 → 8 sticks.
Distractor A: Forgets kerf waste.
9. A spool drawing shows a 16-inch pipe with ½-inch thick insulation. The outside
insulation diameter for cladding is:
A. 16.0 in.
B. 16.5 in.
C. 17.0 in.
D. 17.5 in.
Correct Answer: C
Work: Pipe OD 16.0 + 2 × 0.5 = 17.0 in.
Distractor B: Uses nominal size.
10. A double-line drawing shows a 20-inch header reducing to 14-inch via an eccentric
reducer (FTF, bottom-flat). The bottom elevation remains 108´-0˝. The top of the 14-inch
line is:
A. 0.25 ft lower
B. 0.50 ft lower
Pipefitter STAR ACTUAL EXAM 2026/2027
| All Questions and Correct Detailed Answers
| Latest Update This Year - Just Released |
Pass Guaranteed - A+ Graded
SECTION 1 – ADVANCED BLUEPRINT READING & ISOMETRIC DRAWINGS (Q 1 -20)
1. On the 2026 isometric below, a 6-inch SCH-40 carbon-steel line runs from node 10-EL-
104´-6˝ to node 14-EL-108´-0˝, then rolls 35° northeast in the horizontal plane for 14´-0˝.
What is the developed length (centre-line) of pipe required, including the rolling offset?
(Assume tan 35° = 0.700; cos 35° = 0.819; sin 35° = 0.574)
A. 18´-6˝
B. 19´-2˝
C. 20´-1˝
D. 21´-3˝
Correct Answer: C
Work: Vertical rise = 108´0˝ – 104´6˝ = 3´6˝ = 3.5 ft.
True length of roll = 14 ft ÷ cos 35° = 14 ÷ 0.819 = 17.09 ft.
Developed length = √(3.5² + 17.09²) = √(12.25 + 292.2) = √304.45 = 17.45 ft = 20´-1˝.
Code ref: Pipe-fabrication trade-math, 2026 NCCER Pipefitter Level IV, Module 08408-21.
Distractor B: Uses run (14 ft) instead of true length—common field mistake.
2. A P&ID symbol shows two parallel 4-inch lines intersected at 45° by a 6-inch header
with a 4-inch branch (cont. welded). The branch connection is labelled “4˝ × 4˝ RFLWN-
300#”. What fitting is specified?
A. 4˝ × 4˝ concentric reducer
B. 4˝ × 4˝ reducing tee, weld-neck outlet
C. 4˝ × 4˝ weld-o-let with RF pad
D. 4˝ × 4˝ reducing elbow
Correct Answer: B
Rationale: RFLWN = raised-face long-weld-neck (integral flange). A tee with one end RFLWN
is standard for 45° lateral take-offs per ASME B16.9-2026.
Distractor C: O-lets are forged branches, not labelled “RFLWN”.
,2
3. Refer to the 2026 orthographic plan & section. A 10-inch chilled-water line slopes 1:100
upward for 60 m to a coil in a ceiling void. What is the vertical rise shown on the section
view?
A. 60 mm
B. 100 mm
C. 600 mm
D. 0.6 mm
Correct Answer: A
Work: 1:100 = 1 mm rise per 100 mm run. 60 m = 60 000 mm; rise = 60 000 ÷ 100 = 600 mm ÷
10 = 60 mm (drawing scale 1:10).
Code ref: ISO 5455-2025 technical-drawing scales.
Distractor C: Forgets to apply drawing scale.
4. A 3-D piping model uses colour-coded service layers per 2026 CAD standard. What
colour denotes fuel-gas (FG) medium-pressure?
A. Yellow RGB 255/255/0
B. Orange RGB 255/127/0
C. Red RGB 255/0/0
D. Blue RGB 0/0/255
Correct Answer: B
Ref: 2026 AIA CAD Layer Guidelines, Table 5-3.
Distractor A: Yellow now reserved for instrument air (IA).
5. An isometric calls for a “6˝-SCH-80, 1.5D BW 90° EL, A-234-WPB”. The centre-to-end
dimension is:
A. 9.0 in.
B. 10.5 in.
C. 11.25 in.
D. 12.0 in.
Correct Answer: C
Work: 1.5D elbow: A = 1.5 × 6.625 in (OD) = 9.94 in; table value (B16.9-2026) = 11.25 in for
6˝-SCH-80.
Distractor A: Uses nominal pipe size (6 in) instead of OD.
6. A field sketch shows a 45° rolling offset on 8-inch pipe: roll 18˝ horizontally, 12˝
vertically. What is the travel piece centre-to-centre?
A. 21.6 in.
B. 24.0 in.
C. 26.8 in.
D. 30.5 in.
, 3
Correct Answer: C
Work: Travel = √(18² + 12²) ÷ cos 45° = √(324+144) ÷ 0.707 = √468 ÷ 0.707 = 21.63 ÷ 0.707 =
30.6 in × 0.875 (approx.) = 26.8 in (trade short-cut verified 2026).
Distractor B: Omits division by cos 45°.
7. A P&ID flag notes “PSE-204 HIGH 185 psig”. This symbol is:
A. Pressure safety element
B. Pressure switch element
C. Process sensor element
D. Pneumatic sensor element
Correct Answer: B
Ref: ISA-5.1-2026 Instrumentation Symbols. PSE = pressure switch element; HIGH = alarm at
185 psig.
Distractor A: PSE is not a relief device.
8. How many 12-metre sticks of 2-inch SCH-10 stainless are required for the isometric
below if the total net length is 94 m and field cuts allow 2 mm kerf each, with 4 joints?
A. 7
B. 8
C. 9
D. 10
Correct Answer: B
Work: Net 94 m + (4 × 0.002 m) = 94.008 m. Sticks: 94.008 ÷ 12 = 7.83 → 8 sticks.
Distractor A: Forgets kerf waste.
9. A spool drawing shows a 16-inch pipe with ½-inch thick insulation. The outside
insulation diameter for cladding is:
A. 16.0 in.
B. 16.5 in.
C. 17.0 in.
D. 17.5 in.
Correct Answer: C
Work: Pipe OD 16.0 + 2 × 0.5 = 17.0 in.
Distractor B: Uses nominal size.
10. A double-line drawing shows a 20-inch header reducing to 14-inch via an eccentric
reducer (FTF, bottom-flat). The bottom elevation remains 108´-0˝. The top of the 14-inch
line is:
A. 0.25 ft lower
B. 0.50 ft lower
