with Answers 2026
Create a solution that accepts three integer inputs representing the number of times an employee
travels to a job site. Output the total distance traveled to two decimal places given the following miles
per employee commute to the job site. Output the total distance traveled to two decimal places given
the following miles per employee commute to the job site:
Employee A: 15.62 miles
Employee B: 41.85 miles
Employee C: 32.67 miles
The solution output should be in the format
Distance: total_miles_traveled - ANSWER ✔✨---commute = {
'Employee A': 15.62,
'Employee B': 41.85,
'Employee C': 32.67
}
travels = {
'Employee A': int(input()),
'Employee B': int(input()),
'Employee C': int(input())
}
t_d_t = sum(commute[employee]*travels[employee] for employee in travels)
print(f'Distance: {t_d_t:.2f} miles')
, Create a Python solution to the following task. Ensure that the solution produces output in exactly the
same format shown in the sample(s) below, including capitalization and whitespace.
Task:
Create a solution that accepts an integer input representing any number of ounces. Output the
converted total number of tons, pounds, and remaining ounces based on the input ounces value. There
are 16 ounces in a pound and 2,000 pounds in a ton.
The solution output should be in the format
Tons: value_1 Pounds: value_2 Ounces: value_3 - ANSWER ✔✨---opp = 16
top = 2000
ounces = int(input())
tons = ounces // (opp * top)
ro = ounces % (opp * top)
pounds = ro // opp
ro %= opp
print(f'Tons: {tons}')
print(f'Pounds: {pounds}')
print(f'Ounces: {ro}')
Create a solution that accepts an integer input representing the index value for any any of the five
elements in the following list:
various_data_types = [516, 112.49, True, "meow", ("Western", "Governors", "University"), {"apple": 1,
"pear": 5}]
Using the built-in function type() and getting its name by using the .name attribute, output data type
(e.g., int", "float", "bool", "str") based on the input index value of the list element.
The solution output should be in the format
Element index_value: data_type - ANSWER ✔✨---I_V = int(input())
if -1 <= I_V < len(various_data_types):