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Math Assignment Unit 3 Study Guide | Complete Practice Problems & Solutions | Math Exam Prep

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Prepare for your Math Assignment Unit 3 with this comprehensive study guide, featuring practice problems and verified solutions. This resource covers all key topics from Unit 3, including algebraic expressions, equations, functions, polynomials, and graphing techniques. Designed for students tackling their Unit 3 math assignments or exams, this guide will help reinforce key concepts and ensure you're fully prepared for your next assessment.

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Uploaded on
January 4, 2026
Number of pages
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Written in
2025/2026
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PA




Math Assignment Unit 3



Data Structures

College Algebra

Math 1201

1st December, 2025

, Task 1: Quadratic Functions (Bungee Jumper) PA

Given: The height of the jumper is modeled by the function:

h(t) = −0.5t² + v₀t + h₀

Where:

● v₀ = 0 m/sec (initial velocity)
● h₀ = 210 meters (initial height)



Substituting these values, the specific function for this scenario is:

h(t) = -0.5t² + 210

(i) Mathematical Understanding

(a) Domain and Range
● Domain: The domain represents the valid time (t) values for the jump. The time starts at t
= 0 and ends when the jumper hits the water (height h = 0).

Solving for h(t) = 0:

−0.5t² + 210 = 0

0.5t² = 210

t² = 420

t = √420 ≈ 20.49 seconds

Answer: The domain is [0, 20.49]. Physically, this represents the duration of the fall from
the bridge until touching the river.

● Range: The range represents the vertical height (h). The maximum height is the start
point (210 m), and the minimum is the river surface (0 m). Answer: The range is [0, 210].
Physically, this represents the vertical space in which the jump occurs.

(b) Vertex of the Function For a quadratic function ax² + bx + c, the t-coordinate of the vertex is
found at t = −b / 2a. Here, a = −0.5 and b = 0.

t = −(−0.5) = 0

Substitute t = 0 into the equation to find h:

h(0) = −0.5(0)² + 210 = 210

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