Biochemistry with complete Questions and 100%
correct answers 2025
Glycolysis is the name given to a metabolic pathway occurring in many different cell types. It consists of
11 enzymatic steps that convert glucose to lactic acid. Glycolysis is an example of:
A) aerobic metabolism.
B) anabolic metabolism.
C) a net reductive process.
D) fermentation.
E) oxidative phosphorylation. Correct AnswersD
The conversion of 1 mol of fructose 1,6-bisphosphate to 2 mol of pyruvate by the glycolytic pathway
results in a net formation of:
A) 1 mol of NAD+ and 2 mol of ATP.
B) 1 mol of NADH and 1 mol of ATP.
C) 2 mol of NAD+ and 4 mol of ATP.
D) 2 mol of NADH and 2 mol of ATP.
E) 2 mol of NADH and 4 mol of ATP. Correct AnswersE
When a mixture of glucose 6-phosphate and fructose 6-phosphate is incubated with the enzyme
phosphohexose isomerase, the final mixture contains twice as much glucose 6-phosphate as fructose 6-
phosphate. Which one of the following statements is most nearly correct, when applied to the reaction
below (R = 8.315 J/mol·K and T = 298 K)?
Glucose 6-phosphate ↔ fructose 6-phosphate
A) G'° is +1.7 kJ/mol.
, B) G'° is -1.7 kJ/mol.
C) G'° is incalculably large and negative.
D) G'° is incalculably large and positive.
E) G'° is zero. Correct AnswersA
In glycolysis, fructose 1,6-bisphosphate is converted to two products with a standard free-energy change
(G'°) of 23.8 kJ/mol. Under what conditions (encountered in a normal cell) will the free-energy change
(G) be negative, enabling the reaction to proceed to the right?
A) If the concentrations of the two products are high relative to that of fructose 1,6-bisphosphate.
B) The reaction will not go to the right spontaneously under any conditions because the G'° is positive.
C) Under standard conditions, enough energy is released to drive the reaction to the right.
D) When there is a high concentration of fructose 1,6-bisphosphate relative to the concentration of
products.
E) When there is a high concentration of products relative to the concentration of fructose 1,6-
bisphosphate. Correct AnswersD
Glucose labeled with 14C in C-1 and C-6 gives rise in glycolysis to pyruvate labeled in:
A) A and C.
B) all three carbons.
C) its carbonyl carbon.
D) its carboxyl carbon.
E) its methyl carbon. Correct AnswersE
If glucose labeled with 14C at C-2 were metabolized in the liver, the first radioactive pyruvate formed
would be labeled in:
A) all three carbons.
B) both A and C.