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Exam (elaborations)
AVIA 305 Test Prep UPDATED Exam Questions and CORRECT Answers
AVIA 305 Test Prep UPDATED Exam 
Questions and CORRECT Answers 
An airplane is towing a glider to altitude. The tow rope is 20° below the horizontal and has a 
tension force of 300 lb exerted on it by the airplane. Find the horizontal drag of the glider and 
the amount of lift that the rope is providing to the glider. Sin 20° = 0.342; cos 20 °= 0.940. - 
CORRECT ANSWER- Drag: 
Cos 20° = D/T (Rearrange) D = Cos 20° X Tension
Exam (elaborations)
AVIA 305 Test Prep || with 100% Accurate Solutions.
An airplane is towing a glider to altitude. The tow rope is 20° below the horizontal and has a tension force of 300 lb exerted on it by the airplane. Find the horizontal drag of the glider and the amount of lift that the rope is providing to the glider. Sin 20° = 0.342; cos 20 °= 0.940. correct answers Drag: 
 
Cos 20° = D/T (Rearrange) D = Cos 20° X Tension 
 
D = 0.940 X 300lbs 
 
D = 282lbs 
 
Lift: 
 
Sin 20° = L/T (Rearrange) Lift = Sin 20° X Tension 
 
Lift = 0.342 X 300 lbs 
 
Lift...
Exam (elaborations)
AVIA 305 Key PASSED Exam Questions and CORRECT Answers
The difference between the CL curves for straight-wing aircraft is that 
a) the swept wing aircraft has a lower value of CL (max) 
b) the straight wing aircraft does not fly at as high an AOA for CL (max) 
c) the swept wing aircraft does not have an abrupt loss of lift at CL (max) 
d) all of the above d) all of the above 
Low speed stall will start at the wing's trailing edge 
a) where C1/C2 is a minimum 
b) where C1/C2 is a maximum 
c) at the root for a swept wing 
d) at the wingtip for a st...
Exam (elaborations)
AVIA 305 Certification Exam Questions and CORRECT Answers
An airplane is towing a glider to altitude. The tow rope is 20° below the horizontal and has a 
tension force of 300 lb exerted on it by the airplane. Find the horizontal drag of the glider and 
the amount of lift that the rope is providing to the glider. Sin 20° = 0.342; cos 20 °= 
0.940.Drag: 
Cos 20° = D/T (Rearrange) D = Cos 20° X Tension 
D = 0.940 X 300lbs 
D = 282lbs 
Lift: 
Sin 20° = L/T (Rearrange) Lift = Sin 20° X Tension 
Lift = 0.342 X 300 lbs
Exam (elaborations)
AVIA 305 UPDATED Exam Questions and CORRECT Answers
The equation Ta = Q (V2 - V1) shows thatyou can get more thrust from a jet engine by 
using water injection. 
you can get more thrust from a jet engine by decreasing the exhaust pipe area. 
Q in Ta = Q (V2 - V1) is the mass flow (slugs/sec). The mass flow depends onthe cross‐ 
sectional area of the turbojet engine inlet. 
the engine inlet velocity. 
the density of the air at the same point.
Exam (elaborations)
AVIA 305 Final Exam Questions and Answers Latest Update 2024/2025 | Graded A+.
AVIA 305 Final Exam Questions and Answers Latest Update 2024/2025 | Graded A+. A Normal shock wave will have what effect on velocity and Mach number? 
Selected 
Answer: Decrease to subsonic 
• Question 2 
2.5 out of 2.5 points 
The Airplane Flying Handbook describes Medium Turns (20 to 45 of bank) as 
those in which the angle of bank remains nearly constant. This type of turn 
demonstrates 
Selected 
Answer: 
Neutral lateral stability 
• Question 3 
2.5 out of 2.5 points 
If an aircraft that...
Exam (elaborations)
AVIA 305 Final Exam Questions and Answers Latest Update 2024/2025 | Graded A+
AVIA 305 Final Exam Questions and Answers Latest Update 2024/2025 | Graded A+. A Normal shock wave will have what effect on velocity and Mach number? 
Selected 
Answer: Decrease to subsonic 
• Question 2 
2.5 out of 2.5 points 
The Airplane Flying Handbook describes Medium Turns (20 to 45 of bank) as 
those in which the angle of bank remains nearly constant. This type of turn 
demonstrates 
Selected 
Answer: 
Neutral lateral stability 
• Question 3 
2.5 out of 2.5 points 
If an aircraft that...
Exam (elaborations)
AVIA 305 Key PASSED Exam Questions and CORRECT Answers
The difference between the CL curves for straight-wing aircraft is that 
a) the swept wing aircraft has a lower value of CL (max) 
b) the straight wing aircraft does not fly at as high an AOA for CL (max) 
c) the swept wing aircraft does not have an abrupt loss of lift at CL (max) 
d) all of the above d) all of the above
Exam (elaborations)
AVIA 305 UPDATED Exam Questions and CORRECT Answers
The equation Ta = Q (V2 - V1) shows thatyou can get more thrust from a jet engine by 
using water injection. 
you can get more thrust from a jet engine by decreasing the exhaust pipe area. 
Q in Ta = Q (V2 - V1) is the mass flow (slugs/sec). The mass flow depends onthe cross‐ 
sectional area of the turbojet engine inlet. 
the engine inlet velocity. 
the density of the air at the same point.
Exam (elaborations)
AVIA 305 Certification Exam Questions and CORRECT Answers
An airplane is towing a glider to altitude. The tow rope is 20° below the horizontal and has a 
tension force of 300 lb exerted on it by the airplane. Find the horizontal drag of the glider and 
the amount of lift that the rope is providing to the glider. Sin 20° = 0.342; cos 20 °= 
0.940.Drag: 
Cos 20° = D/T (Rearrange) D = Cos 20° X Tension 
D = 0.940 X 300lbs 
D = 282lbs 
Lift: 
Sin 20° = L/T (Rearrange) Lift = Sin 20° X Tension 
Lift = 0.342 X 300 lbs
Exam (elaborations)
AVIA 305 Quiz- Maneuvering Performance Answers 2023
AVIA 305 Quiz- Maneuvering Performance Answers 2023 
AVIA 305 Quiz- Maneuvering Performance Answers 2023
Exam (elaborations)
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AVIA 305 Quiz 3 with pictures