1|Page
zl zl zl zl zl
www.PlusBay.Plus
,chapter 1: Arithmetic Needed for Dosage
zl zl zl zl zl
MULTIPLE CHOICE zl
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15 oz. W
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
hat portion of the water remained?
zl zl zl zl zl
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A z l
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (25 oz
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividing 10 oz (re
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
maining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To reduce fractions, find
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the largest number that can be divided evenly into the numerator and the denominator
zl zl zl zl zl zl zl zl zl zl zl zl zl
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of 2/5.
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1
zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integrat
zl zl zl zl zl zl zl zl zl
ed Process: Teaching/Learning
zl zl
Objective: 1, 2 zl zl
2. A patient/client was prescribed 240 W
zl mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 100 zl zl zl zl zl zl zl zl zl zl zl zl
mL. What portion of the Ensure remained?
zl zl zl zl zl zl
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B z l
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available quantit
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
y (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a fraction by di
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
viding 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided by 240 = 7/12. To r
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
educe fractions, find the largest number that can be divided evenly into the numerator and the denominat
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
or (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240 can be reduced to its lowest t
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
erms of 7/12. zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1
zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integrat
zl zl zl zl zl zl zl zl zl
ed Process: Teaching/Learning
zl zl
Objective: 1, 2 zl zl
2|Page
zl zl zl zl zl
www.PlusBay.Plus
,3. A patient/client consumed
zl oz. of coffee, 2/3 oz. of ice cream, and zl z l z l zl zl zl zl zl zl zl zl z l
oz. of beef broth. What is the total number of ounces consumed that should be documented for the patie
z l zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
nt/client?
a. 3 3/4 zl
b. 4 5/12 zl
c. 4 2/3 zl
d. 4 4/9 zl
ANS: B z l
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by multipl
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ying the whole number by the denominator and then adding that total to the numerator. For the coffee, 4
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
2 = 8 + 1 = 9/4; for the beef broth, 2 1
zl zl zl zl zl zl zl zl zl zl zl zl zl
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find the l
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
east common denominator (LCD). For 2, 3, and 4, the LCD =
zl zl zl zl zl zl zl zl zl zl zl
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then mu
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ltiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee), 8/12 (i
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ce cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added together an
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
d the fraction is reduced to the lowest terms.
zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Analyze zl zl
Difficulty: Difficult zl
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
zl zl zl zl zl zl zl zl zl
grated Process: Communication and Documentation Objective: 1,
zl zl zl zl zl zl zl
2
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the nurse document as consumed?
zl zl zl zl
WWW.TBSM.WS
a. 360
b. 420
c. 510
d. 600
ANS: B z l
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of millili
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ters consumed, multiply 180 7/3 (
zl zl zl zl zl zl
). When a mixed number is present, change it to an improper fraction by multiplying the whole number by
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the denominator and then adding that total to
zl zl zl zl zl zl zl zl
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Analyze zl zl
Difficulty: Difficult zl
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
zl zl zl zl zl zl zl zl zl
grated Process: Communication and Documentation Objective: 1,
zl zl zl zl zl zl zl
2
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were ga
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ined since admission? zl zl
a. 0.78
b. 0.88
3|Page zl zl zl zl zl
www.PlusBay.Plus
, c. 1.88
d. 1.98
ANS: C z l
Feedback: To estimate the amount of kilograms gained, subtract weight on admission (48.52) from curr
zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ent weight (50.4 kg) = 1.88 kg (weight gained). To subtract decimals, decimals are stacked lined up. Start
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ing at the far right of the stack, the numbers are subtracted. In the answer, make sure the decimal point li
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
nes up exactly with the points above it.
zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Physiological Adaptation Co
zl zl zl zl zl zl
gnitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 10, Decimals Integrat
zl zl zl zl zl
ed Process: Nursing Process Objective: 3
zl zl zl zl zl
,5
zl
6. A patient/client's sodium intake for one meal was 0.004 g and 0.152 g. How many grams, to the ne
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
arest hundredths, of sodium were consumed?
zl zl zl zl zl
a. 0.15
b. 0.156
c. 0.16
d. 0.166
ANS: C z l
Feedback: To add decimals, stack vertically, making sure that all of the decimal points exactly line up. St
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
arting at the far right of the stack, add each vertical column of numbers. In the answer, make sure the deci
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
mal point lines up exactly with the points above it. To round off a decimal, the final number is
dropped. Add 0.004 g + 0.152 g = 0W. 1W
5 6Wg.(Tt hBo uSs M
a n.d tWh sSp l a c e ) to determine the total number of grams
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the client consumed. When the final number (6) is 5 or greater, drop that number and increase the adjace
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
nt number (5) by 1. When you want a number rounded off to the nearest hundredth, look at the number in
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the thousandth place and follow the rounding off rule. Therefore, 0.156 = 0.16 g.
zl zl zl zl zl zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Physiological Adaptation Co
zl zl zl zl zl zl
gnitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 10, Decimals Integrat
zl zl zl zl zl
ed Process: Teaching/Learning Objectiv
zl zl zl
e: 3, 5, 6
zl zl zl
7. A patient/client reports drinking 30% of a 16-
zl zl zl zl zl zl zl
oz bottle of orange juice. How many ounces did the patient/client drink?
zl zl zl zl zl zl zl zl zl zl zl
a. 0.18
b. 3.2
c. 4.8
d. 5.3 zl
ANS: C z l
4|Page zl zl zl zl zl
www.PlusBay.Plus
zl zl zl zl zl
www.PlusBay.Plus
,chapter 1: Arithmetic Needed for Dosage
zl zl zl zl zl
MULTIPLE CHOICE zl
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15 oz. W
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
hat portion of the water remained?
zl zl zl zl zl
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A z l
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (25 oz
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividing 10 oz (re
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
maining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To reduce fractions, find
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the largest number that can be divided evenly into the numerator and the denominator
zl zl zl zl zl zl zl zl zl zl zl zl zl
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of 2/5.
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1
zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integrat
zl zl zl zl zl zl zl zl zl
ed Process: Teaching/Learning
zl zl
Objective: 1, 2 zl zl
2. A patient/client was prescribed 240 W
zl mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 100 zl zl zl zl zl zl zl zl zl zl zl zl
mL. What portion of the Ensure remained?
zl zl zl zl zl zl
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B z l
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available quantit
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
y (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a fraction by di
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
viding 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided by 240 = 7/12. To r
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
educe fractions, find the largest number that can be divided evenly into the numerator and the denominat
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
or (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240 can be reduced to its lowest t
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
erms of 7/12. zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1
zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integrat
zl zl zl zl zl zl zl zl zl
ed Process: Teaching/Learning
zl zl
Objective: 1, 2 zl zl
2|Page
zl zl zl zl zl
www.PlusBay.Plus
,3. A patient/client consumed
zl oz. of coffee, 2/3 oz. of ice cream, and zl z l z l zl zl zl zl zl zl zl zl z l
oz. of beef broth. What is the total number of ounces consumed that should be documented for the patie
z l zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
nt/client?
a. 3 3/4 zl
b. 4 5/12 zl
c. 4 2/3 zl
d. 4 4/9 zl
ANS: B z l
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by multipl
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ying the whole number by the denominator and then adding that total to the numerator. For the coffee, 4
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
2 = 8 + 1 = 9/4; for the beef broth, 2 1
zl zl zl zl zl zl zl zl zl zl zl zl zl
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find the l
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
east common denominator (LCD). For 2, 3, and 4, the LCD =
zl zl zl zl zl zl zl zl zl zl zl
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then mu
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ltiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee), 8/12 (i
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ce cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added together an
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
d the fraction is reduced to the lowest terms.
zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Analyze zl zl
Difficulty: Difficult zl
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
zl zl zl zl zl zl zl zl zl
grated Process: Communication and Documentation Objective: 1,
zl zl zl zl zl zl zl
2
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the nurse document as consumed?
zl zl zl zl
WWW.TBSM.WS
a. 360
b. 420
c. 510
d. 600
ANS: B z l
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of millili
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ters consumed, multiply 180 7/3 (
zl zl zl zl zl zl
). When a mixed number is present, change it to an improper fraction by multiplying the whole number by
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the denominator and then adding that total to
zl zl zl zl zl zl zl zl
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
zl zl zl zl zl zl zl zl
nitive Level: Analyze zl zl
Difficulty: Difficult zl
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
zl zl zl zl zl zl zl zl zl
grated Process: Communication and Documentation Objective: 1,
zl zl zl zl zl zl zl
2
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were ga
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ined since admission? zl zl
a. 0.78
b. 0.88
3|Page zl zl zl zl zl
www.PlusBay.Plus
, c. 1.88
d. 1.98
ANS: C z l
Feedback: To estimate the amount of kilograms gained, subtract weight on admission (48.52) from curr
zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ent weight (50.4 kg) = 1.88 kg (weight gained). To subtract decimals, decimals are stacked lined up. Start
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
ing at the far right of the stack, the numbers are subtracted. In the answer, make sure the decimal point li
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
nes up exactly with the points above it.
zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Physiological Adaptation Co
zl zl zl zl zl zl
gnitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 10, Decimals Integrat
zl zl zl zl zl
ed Process: Nursing Process Objective: 3
zl zl zl zl zl
,5
zl
6. A patient/client's sodium intake for one meal was 0.004 g and 0.152 g. How many grams, to the ne
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
arest hundredths, of sodium were consumed?
zl zl zl zl zl
a. 0.15
b. 0.156
c. 0.16
d. 0.166
ANS: C z l
Feedback: To add decimals, stack vertically, making sure that all of the decimal points exactly line up. St
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
arting at the far right of the stack, add each vertical column of numbers. In the answer, make sure the deci
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
mal point lines up exactly with the points above it. To round off a decimal, the final number is
dropped. Add 0.004 g + 0.152 g = 0W. 1W
5 6Wg.(Tt hBo uSs M
a n.d tWh sSp l a c e ) to determine the total number of grams
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the client consumed. When the final number (6) is 5 or greater, drop that number and increase the adjace
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
nt number (5) by 1. When you want a number rounded off to the nearest hundredth, look at the number in
zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl zl
the thousandth place and follow the rounding off rule. Therefore, 0.156 = 0.16 g.
zl zl zl zl zl zl zl zl zl zl zl zl zl
Format: Multiple Choice Chapte zl zl zl
r: 1 zl
Client Needs: Physiological Integrity: Physiological Adaptation Co
zl zl zl zl zl zl
gnitive Level: Apply zl zl
Difficulty: Moderate zl
Page and Header: 10, Decimals Integrat
zl zl zl zl zl
ed Process: Teaching/Learning Objectiv
zl zl zl
e: 3, 5, 6
zl zl zl
7. A patient/client reports drinking 30% of a 16-
zl zl zl zl zl zl zl
oz bottle of orange juice. How many ounces did the patient/client drink?
zl zl zl zl zl zl zl zl zl zl zl
a. 0.18
b. 3.2
c. 4.8
d. 5.3 zl
ANS: C z l
4|Page zl zl zl zl zl
www.PlusBay.Plus
