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A-Level OCR 2025 Chemistry A Paper 3

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A-Level OCR 2025 Chemistry A Paper 3

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Uploaded on
December 10, 2025
Number of pages
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Written in
2025/2026
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A-Level OCR 2025 Chemistry A Paper 3


Friday 20 June 2025 – Morning

A Level Chemistry A

H432/03 Unified chemistry


Time allowed: 1 hour 30 minutes

1
Turn over

, 2
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© OCR 2025

, 3
1 This question is about spectra.

(a) The mass spectrum for Br2 has peaks at m/z values of 79, 81, 158, 160 and 162.
The peaks at m/z 79 and 81 have virtually the same relative abundance.

(i) Complete the table to show the number of protons, neutrons and electrons in the particles that
cause the peaks at m/z 79 and 81.

Number of Number of Number of
m/z
protons neutrons electrons

79

81

[2]

(ii) Explain why there are peaks with m/z values of 158, 160 and 162 and predict their relative
abundances.

Explanation ......................................................................................................................................

..........................................................................................................................................................

..........................................................................................................................................................

..........................................................................................................................................................

Relative abundances .......................................................................................................................

..........................................................................................................................................................

..........................................................................................................................................................
[3]

(b) This question looks at proton NMR spectra of dibromoalkanes.

Predict the following.

Compound Number of peaks CH2 splitting pattern(s)

BrCH2CH2Br

BrCH2CH2CH2Br

[3]




© OCR 2025 Turn over

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