R TS e ch)
"""" COw_ Uagpn Yl §
. 7 AC
. ¢ 0 : )
Iz i > jnj*_:‘;{}—““iw
- — — 50(1\) 2
) i Fo ne S ’ Vwmm: 35103
20 mm T
— Oam g,
J\.OT‘G\BVA . - = i D8
d_gr_—flifl; ———— Q0mm - 600
(W 2w
| e T
_V.?jF_x_ ZOi ¢ bl % Sfi(’ R— k: A/
L-P-s0(g2)=50h@ +albed)-0
=P - 60000 =0 . = =
P- - coomo N () S e LA
Ac E
= [« 60000“'(600.19_-_3) hig v
“”F:fl‘_. 40 KN 240" (200 -10%)
SFxzo . - -0.0005130m
i LT N
"Px’«\lO(\o:‘\N:O EER
TEs
(1 e ABL P=>a . 24|4ie
-p1£d \
P =- 40 (\ 0?\V
iy AN
Expres\d\
fo_afeq O roq - _ yoli03)-(400
: ! Ll
e
: \0’3\1
3.4 07" - (200-10 gl
Ao - L (on - 3.M x\Q_“ o
\‘
- 0.000284Mm -
I 0. 0003LE4JM "
L A A y ABC 3\:'0003
2 —-6.2;\‘6 ) aae--
, s Raveuak Qe Y
L
i 4-1. The copper shall is subjected 1o t : N [,
B shown. Determine the displacen ent of end heA withaxial r loads
I to end D. The diameters of mh‘ w;n"‘n"“:‘ m‘ 3 th .t‘:pic:g S Wen Cens % \\\\ > \\5\ :
=z dygc = 2in..and dgyy = 1 in. Take Ey = “*(l“‘)":n. 3in, - |
= ® o : éAB: d1in b ind fMo &2
L5 P AV O » &Qg: 2w
\ \ d :
- e S0 i, e 75 in. —ok 60in — Q= i\“
k. VG
L Prob. 4-1 AE
- s
— : :
= LC)‘S_. eind e welacanent & <o %Q%fl‘B\'\ and Hren add ol i
i? : (:'\“A 5/4/0
= @ GK $ @ = @ -1 le
= Gho { e Boce’ G
i Pao
A 2Fx-0 SFx=0
4 zFx:O ‘6l§p+l*l*(366 =9 ‘A;PCQ
i 6K p 4 pAO:O pQ)c,-, 2 Yap Feo Kie
Go - Grie >
3 - P 2(38) 6’ PL _ (Al
el ool o 8.
[-A TAE C ILBVl
(2} (g 102
(0818
— ol y 7 = - )T LB I oY
@ At B 043
46 Ae L((e)loP [ § - 2080072 A -
-3 ? 6C Jepz 4Mx\0 " \n
)= 23S0 in
1%
—\.\‘
: S,\Bk Lot Sco 21163 x\0 \nl
\S)A-—»O - ZfS
"""" COw_ Uagpn Yl §
. 7 AC
. ¢ 0 : )
Iz i > jnj*_:‘;{}—““iw
- — — 50(1\) 2
) i Fo ne S ’ Vwmm: 35103
20 mm T
— Oam g,
J\.OT‘G\BVA . - = i D8
d_gr_—flifl; ———— Q0mm - 600
(W 2w
| e T
_V.?jF_x_ ZOi ¢ bl % Sfi(’ R— k: A/
L-P-s0(g2)=50h@ +albed)-0
=P - 60000 =0 . = =
P- - coomo N () S e LA
Ac E
= [« 60000“'(600.19_-_3) hig v
“”F:fl‘_. 40 KN 240" (200 -10%)
SFxzo . - -0.0005130m
i LT N
"Px’«\lO(\o:‘\N:O EER
TEs
(1 e ABL P=>a . 24|4ie
-p1£d \
P =- 40 (\ 0?\V
iy AN
Expres\d\
fo_afeq O roq - _ yoli03)-(400
: ! Ll
e
: \0’3\1
3.4 07" - (200-10 gl
Ao - L (on - 3.M x\Q_“ o
\‘
- 0.000284Mm -
I 0. 0003LE4JM "
L A A y ABC 3\:'0003
2 —-6.2;\‘6 ) aae--
, s Raveuak Qe Y
L
i 4-1. The copper shall is subjected 1o t : N [,
B shown. Determine the displacen ent of end heA withaxial r loads
I to end D. The diameters of mh‘ w;n"‘n"“:‘ m‘ 3 th .t‘:pic:g S Wen Cens % \\\\ > \\5\ :
=z dygc = 2in..and dgyy = 1 in. Take Ey = “*(l“‘)":n. 3in, - |
= ® o : éAB: d1in b ind fMo &2
L5 P AV O » &Qg: 2w
\ \ d :
- e S0 i, e 75 in. —ok 60in — Q= i\“
k. VG
L Prob. 4-1 AE
- s
— : :
= LC)‘S_. eind e welacanent & <o %Q%fl‘B\'\ and Hren add ol i
i? : (:'\“A 5/4/0
= @ GK $ @ = @ -1 le
= Gho { e Boce’ G
i Pao
A 2Fx-0 SFx=0
4 zFx:O ‘6l§p+l*l*(366 =9 ‘A;PCQ
i 6K p 4 pAO:O pQ)c,-, 2 Yap Feo Kie
Go - Grie >
3 - P 2(38) 6’ PL _ (Al
el ool o 8.
[-A TAE C ILBVl
(2} (g 102
(0818
— ol y 7 = - )T LB I oY
@ At B 043
46 Ae L((e)loP [ § - 2080072 A -
-3 ? 6C Jepz 4Mx\0 " \n
)= 23S0 in
1%
—\.\‘
: S,\Bk Lot Sco 21163 x\0 \nl
\S)A-—»O - ZfS
