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SOLUTION MANUAL – Finite Mathematics & Its Applications (13th Edition) | Larry Goldstein, David Schneider & Martha Siegel | Latest Update 2026 | Complete Step-by-Step Solutions | Homework & Exam Prep

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This comprehensive Solution Manual for Finite Mathematics & Its Applications (13th Edition) by Larry Goldstein, David Schneider, and Martha Siegel provides fully worked, step-by-step solutions to every exercise and problem in the textbook. Designed for students in mathematics, business, economics, data analysis, social sciences, and applied fields, this manual explains concepts clearly and shows exactly how to solve each problem using correct methods and formulas from the textbook. It covers essential finite math topics such as linear equations, matrices, systems of equations, linear programming, probability, sets, logic, finance, counting methods, and statistics. What’s Included ️ Detailed, step-by-step solutions for the entire 13th Edition ️ Clear explanations for complex finite math concepts ️ Verified answers for all chapters and practice problems ️ Updated for 2026 coursework and exam preparation ️ Ideal for homework, quizzes, midterms, and finals ️ Great for self-study and improving problem-solving skills Why Students Choose This Solution Manual Saves time on difficult math problems Makes abstract concepts easy to understand Boosts grades in assignments and tests Perfect for applied mathematics and business math courses This is the most complete and reliable solution manual for Finite Mathematics & Its Applications (13th Edition). Perfect for students who want to master finite math and improve their exam performance.

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Finite Mathematics & Its Applications 13th Edition
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Institution
Finite Mathematics & Its Applications 13th Edition
Course
Finite Mathematics & Its Applications 13th Edition

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Uploaded on
December 8, 2025
Number of pages
825
Written in
2025/2026
Type
Exam (elaborations)
Contains
Questions & answers

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SOLUTION MANUAL
Finite Mathematics & Its Applications
13th Edition by Larry J. Goldstein,
Chapters 1 - 12, Complete

, Contents
Chapter 1: Linear Equations and Straight Lines 1–1
Chapter 2: Matrices 2–1

Chapter 3: Linear Programming, A Geometric Approach 3–1

Chapter 4: The Simplex Method 4–1

Chapter 5: Sets and Counting 5–1

Chapter 6: Probability 6–1

Chapter 7: Probability and Statistics 7–1

Chapter 8: Markov Processes 8–1

Chapter 9: The Theory of Games 9–1

Chapter 10: The Mathematics of Finance 10–1

Chapter 11: Logic 11–1

Chapter 12: Difference Equations and Mathematical Models 12–1

, Chapter 1
Exercises 1.1 5
6. Left 1, down
2
1. Right 2, up 3 y
y


(2, 3)
x
x
( )
–1, – 52




7. Left 20, up 40
2. Left 1, up 4 y
y

(–20, 40)
(–1, 4)
x
x




8. Right 25, up 30
3. Down 2 y
y


(25, 30)
x
x
(0, –2)




9. Point Q is 2 units to the left and 2 units up or
4. Right 2
y (—2, 2).

10. Point P is 3 units to the right and 2 units down or
(3,—2).
x
(2, 0) 1
11. —2(1) + (3) = —2 +1 = —1so yes the point is
3
on the line.

5. Left 2, up 1 1
y 12. —2(2) + (6) = —1 is false, so no the point is not
3
on the line

(–2, 1)
x



Copyright © 2023 Pearson Education, Inc. 1-1

, Chapter 1: Linear Equations and Straight Lines ISM: Finite Math


1 24. 0 = 5
13 —2x + y = —1 Substitute the x and y no solution
3
. x-intercept: none
coordinates of the point into the equation:
f 1 hı f h When x = 0, y = 5
' , 3 → —2 ' 1 ı + 1 (3) = —1 → —1+1 = —1 is y-intercept: (0, 5)
y' ı 'y ıJ
2 J 2 3
a false statement. So no the point is not on 25. When y = 0, x = 7
theline. x-intercept: (7, 0)
f 1h f1 h 0=7
14 —2 ' ı + ' ı (—1) = —1 is true so yes the point is no solution
.
'y3 ıJ 'y3 ıJ y-intercept: none
on the line. 26. 0 = –8x
15. m = 5, b = 8 x=0
x-intercept: (0, 0)
16. m = –2 and b = –6 y = –8(0)
y=0
17. y = 0x + 3; m = 0, b = 3 y-intercept: (0, 0)

2 2 1
y = x + 0; m = , b = 0 27 0 = x –1
18 3
3 3 .
. x=3
19. 14x + 7 y = 21 x-intercept: (3, 0)
1
7 y = —14x + 21 y = (0) – 1
3
y = —2x + 3
y = –1
y-intercept: (0, –1)
20 x—y =3 y
. —y = —x + 3
y = x —3
(3, 0)
21. 3x = 5 x
5 (0, –1)
x=
3
1 2
28. When x = 0, y = 0.
22 – x+ y = 10
. 2 3 When x = 1, y = 2.
2 1 y
y= x +10
3 2
3
y = x +15 (1, 2)
4 x
(0, 0)

23. 0 = —4x + 8
4x = 8
x=2
x-intercept: (2, 0)
y = –4(0) + 8
y=8
y-intercept: (0, 8)


1-2 Copyright © 2023 Pearson Education, Inc.
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