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Exam (elaborations)

Chem 103 Module 1 to 6 Exam & Final Exam Portage learning (Latest 2025 / 2026) Most Comprehensive Qs & Ans - to Pass the Exam, 100% Verified

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Chem 103 Module 1 to 6 Exam & Final Exam Portage learning (Latest 2025 / 2026) Most Comprehensive Qs & Ans - to Pass the Exam, 100% Verified

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1

,Pay it forward.
mt mt




MODULE 1 EXAM mt mt




Question 1 mt



Click this link to access the Periodic Table. This may be helpful
mt mt mt mt mt mt mt mt mt mt mt




throughout the exam.
mt mt mt




1. Convert 845.3 to exponential form and explain your answer.
mt mt mt mt mt mt mt m t




2. Convert 3.21 x 10-5 to ordinary form and explain your answer.
mt mt mt
m t
mt mt mt mt mt mt




1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places
mt mt mt mt mt mt mt mt mt mt mt mt



= 8.453 x 102
mt mt mt




2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5
mt mt mt
m t
mt mt mt mt mt mt mt mt mt



places = 0.0000321 mt mt




Question 2 mt




mt Click this link to access the Periodic Table. This may be helpful
mt mt mt mt mt mt mt mt mt mt mt



mt throughout the exam. mt mt




Using the following information, do the conversions shown below, showing all
mt mt mt mt mt mt mt mt mt mt



work:
mt




1 ft = 12 inches
mt mt mt mt 1 pound = 16 oz
mt mt mt mt 1 gallon = 4 quarts
mt mt mt mt




1 mile = 5280 feet
mt mt mt mt 1 ton = 2000 pounds
mt mt mt mt 1 quart = 2 pints
mt mt mt mt




kilo (= 1000) mt mt milli (= 1/1000) mt mt
centi (= mt



1/100)
mt deci (= 1/10)
mt mt mt




1. 24.6 grams = ? kg mt mt mt mt




2. 6.3 ft = ? inches
mt mt mt mt

,1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg
mt mt mt mt mt mt mt mt mt mt




2. 6.3 ft x 12 in / 1 ft = 75.6 inches
mt mt mt mt mt mt mt mt mt mt




please always use the correct units in your final answer
mt mt mt mt mt mt mt mt mt




Question 3 mt

, 3


Click this link to access the Periodic Table. This may be helpful
mt mt mt mt mt mt mt mt mt mt mt



throughout the exam.
mt mt mt




Do the conversions shown below, showing all work:
mt mt mt mt mt mt mt




1. 28oC = ? oK mt mt mt




2. 158oF = ? oC mt mt mt




3. 343oK = ? oF mt mt mt




1. 28oC + 273 = 301 oK mt mt mt mt mt
o
C → oK (make larger)
mt mt mt mt



+273
2. 158oF - 32 ÷ 1.8 = 70 oC mt mt mt mt mt mt mt
o
F → oC (make smaller)
mt mt mt mt



-32 ÷1.8 mt




3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF
mt mt mt mt mt mt mt mt mt mt mt mt
o
K → oC → oF
mt mt mt mt




Question 4 mt




mt Click this link to access the Periodic Table. This may be helpful
mt mt mt mt mt mt mt mt mt mt mt



mt throughout the exam. mt mt




Be sure to show the correct number of significant figures in each calculation.
mt mt mt mt mt mt mt mt mt mt mt mt




1. Show the calculation of the mass of a 18.6 ml sample of freon
mt mt mt mt mt mt mt mt mt mt mt mt



with density of 1.49 g/ml
mt mt mt mt mt




2. Show the calculation of the density of crude oil if 26.3 g occupies
mt mt mt mt mt mt mt mt mt mt mt mt



30.5 ml.
mt mt




1. M = D x V = 1.49 x 18.6 = 27.7 g
mt mt mt mt mt mt mt mt mt mt mt



2. D = M / V = 26..5 = 0.862 g/ml
mt mt mt mt mt mt mt mt mt mt mt




Question 5 mt




mt Click this link to access the Periodic Table. This may be helpful
mt mt mt mt mt mt mt mt mt mt mt



mt throughout the exam. mt mt




1. 3.0600 contains ? significant figures.
mt mt mt mt




2. 0.0151 contains ? significant figures.
mt mt mt mt

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