2025 Pearson Edexcel GCE A Level In Chemistry (9CH0) Paper 02: Advanced Organic and Physical Chemistry ACTUAL QUESTION PAPER AND MARKING SCHEME (MERGED)

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Paper


Chemistry 🟐 🟐


Advanced
PAPER 2: Advanced Organic and Physical Chemistry

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Instructions
Use black ink or ball‑point pen.
If pencil is used for diagrams/sketches/graphs it must be dark (HB or B).
Fill in the boxes at the top of this page with your name,
centre number and candidate number.


• Answer the questions in the spaces provided
– there may be more space than you need.

Information
The total mark for this paper is 90.
The marks for each question are shown in brackets
– use this as a guide as to how much time to spend on each question.
For the question marked with an asterisk (*), marks will be awarded for your ability
to structure your answer logically, showing how the points that you make are related
or follow on from each other where appropriate.
A Periodic Table is printed on the back cover of this paper.

Advice
Read
Show each question
all your carefully
working before you
in calculations andstart to answer
include it.
units where appropriate.

• Check your answers if you have time at the end. Turn over

,
, Answer ALL questions.

Some questions must be answered with a cross in a box . If you change your mind about an
answer, put a line through the box and then mark your new answer with a cross .

1 This question is about mass spectrometry.
(a) Which molecule would not give a molecular ion peak with m/z = 74?
(1)
A C2H5COOH
B CHOCOOH

C CH2(OH)COOH
D CH3COOCH3


(b) The fragmentation pattern in a mass spectrum can be used to distinguish
between structural isomers.
Which m/z peak would be present in the mass spectrum of propanal, CH3CH2CHO,
but not in the mass spectrum of propanone, CH3COCH3?
(1)
A 15

B 29

C 43

D 59
(Total for Question 1 = 2 marks)




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, 2 Intermolecular forces affect the physical properties of compounds.
(a) Which of these isomers, with the formula C8H18, will have the
lowest boiling temperature?
(1)
A (CH3)2CHCH2C(CH3)3

B (CH3)2CHCH2CH(CH3)CH2CH3
C CH3CH2CH2C(CH3)2CH2CH3

D CH3CH2CH2CH2CH2CH2CH2CH3


(b) Pentan‑1‑ol and hexane have the same number of electrons but pentan‑1‑ol is
much less volatile than hexane.
Explain this difference in volatility.
(2)

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(c) Iodine is a solid at room temperature but on gentle heating it vaporises.

What bonds or forces are being broken?
(1)
A covalent bonds

B ionic bonds
C London forces

D permanent dipole‑dipole forces




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