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Exam (elaborations)

NURS 5315 Final EXAM WITH ANSWERS

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NURS 5315 Final EXAM WITH ANSWERS












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Uploaded on
October 22, 2025
Number of pages
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Written in
2025/2026
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NURS 5315 Final EXAM WITH ANSWERS |\ |\ |\ |\ |\




A patient in respiratory distress and is breathing 33 breaths per
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


minute. Which ABG value is consistent with the clinical scenario?
|\ |\ |\ |\ |\ |\ |\ |\ |\




PCO2 15 |\




pH 7.30 |\




pH 7.45 |\




O2 sat 100% |\ |\




A patient who is breathing 33 breaths per minute is
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


hyperventilating and blowing off CO2; therefore the PCO2 level |\ |\ |\ |\ |\ |\ |\ |\ |\


will be low. The patient will most likely experience a respiratory
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


alkalosis and the two pH values provided are not consistent with
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


this diagnosis. |\




A patient has a sodium level of 115 mEq/L and is disoriented and
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lethargic. Which pathological process best explains this patient's
|\ |\ |\ |\ |\ |\ |\ |\ |\


symptoms?
a. The action potential has become hyperpolarized.
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b. Water has shifted into the neurons and caused them to swell.
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\




c. Water has shifted into the vascular space and dehydrated the
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neurons.
d. The action potential has become hypopolarized.
|\ |\ |\ |\ |\ |\




b. The cause of neurologic symptoms associated with a sodium
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


imbalance is directly related to fluid shifting into or out of the
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


neurons of the brain. With a serum sodium of 115 mEq/L, water
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\

,shifts into the neurons and causes them to swell. Hypernatremia
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


causes water to shift out of the cell into the intravascular space
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


and causes the neurons to become dehydrated. An alteration in
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


the action potential is not seen with sodium imbalances.
|\ |\ |\ |\ |\ |\ |\ |\




A patient experiencing dehydration should be monitored for
|\ |\ |\ |\ |\ |\ |\ |\


which electrolyte imbalance? |\ |\




a. Hyperkalemia
|\




b. Hypocalcemia
|\




c. Hypercalcemia
|\




d. Hyponatermia
|\




a. Serum osmolality is increased during times of dehydration. An
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


elevated serum osmolality will pull potassium into the
|\ |\ |\ |\ |\ |\ |\ |\


intravascular space from the intracellular space and cause a rise |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


in serum potassium.
|\ |\




A married couple presents to your office for genetic counseling.
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


The husband has an autosomal recessive disease and his wife
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


has a heterozygous genotype for the disease. They ask you,
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


What is the chance that our baby will have the disease? Which of
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


the following answers is correct?
|\ |\ |\ |\ |\




25%
50%
75%
100%

,A chromosome is a package of material located inside the cell
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


nucleus which is made of proteins and a single molecule of DNA.
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


There are 23 pairs of chromosomes in each human cell for a total
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


of 46 chromosomes. Chromosomes are separated into two
|\ |\ |\ |\ |\ |\ |\ |\ |\


identical sets during mitosis or meiosis. This provides a set of
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


chromosomes to each daughter cell which results from cell |\ |\ |\ |\ |\ |\ |\ |\ |\


division. This process is responsible for the transfer of genetic
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


information to the daughter cells. The first 22 pairs of |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


chromosomes are known as autosomes. The 23rd pair of |\ |\ |\ |\ |\ |\ |\ |\ |\


chromosomes is the pair which contains the genetic information |\ |\ |\ |\ |\ |\ |\ |\ |\


for gender. This pair contains the genetic information which
|\ |\ |\ |\ |\ |\ |\ |\ |\


delineates between the male and female genders. Females have |\ |\ |\ |\ |\ |\ |\ |\ |\


two X chromosomes (XX) and males have an XY chromosome
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


pair. Autosomal chromosomes are said to be autologous. This
|\ |\ |\ |\ |\ |\ |\ |\ |\


means they do not carry genetic information pertaining to
|\ |\ |\ |\ |\ |\ |\ |\ |\


gender. Autosomal genetic diseases are carried on the first 22
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


pairs of chromosomes. Sex-linked diseases are only carried on
|\ |\ |\ |\ |\ |\ |\ |\ |\


the 23rd pair of chromosomes. The autosomal chromosomes are
|\ |\ |\ |\ |\ |\ |\ |\ |\


nearly identical to one another and are considered homologous
|\ |\ |\ |\ |\ |\ |\ |\ |\


to one another. Each autosomal chromosome in a pair carries
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


identical genes. These two genes are known as alleles. The
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alleles occupy the same site on each partner of the chromosome
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


pair and code for the same genetic trait or physiologic function.
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


Alleles can be dominant or recessive. One allele may be
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


dominant and the other recessive, or they both may be dominant|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


or both recessive. The dominant alleles' genetic code will always
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


manifest in the individual's phenotype. The information in the
|\ |\ |\ |\ |\ |\ |\ |\ |\


recessive allele is typically not expressed in the phenotype |\ |\ |\ |\ |\ |\ |\ |\ |\


unless both alleles are recessive. For the purpose of clarity in
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


use, the dominant gene is assigned a capital letter and the
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


recessive gene is assigned a lower case letter. Any letter is okay
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


to use but make sure you use the same letter for the genotype -
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


for example, "Bb or aa." The term homozygous refers to a pair of
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


alleles which are either both dominant or recessive. For example,
|\ |\ |\ |\ |\ |\ |\ |\ |\

, "BB or bb" are said to be homozygous because the alleles are
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


either both dominant or recessive. An allele pair in which one is
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


dominant and one is recessive is said to be heterozygous. In |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


autosomal recessive disorders both alleles on the chromosome |\ |\ |\ |\ |\ |\ |\ |\


are affected by the genetic aberration. If only one recessive gene
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


is affected by the genetic aberration then the person is said to
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


be a carrier and will not have the phenotypic expression of the
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


disease. The healthy, recessive allele will compensate for the
|\ |\ |\ |\ |\ |\ |\ |\ |\


allele which is affected by the genetic aberration. The carrier can
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


pass the trait but does not have the genetic disease. In an
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


autosomal dominant disorder the dominant gene is the only gene |\ |\ |\ |\ |\ |\ |\ |\ |\


that has to be affected by the genetic aberration in order to
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


have the phenotypic expression of the disease. A healthy
|\ |\ |\ |\ |\ |\ |\ |\ |\


recessive allele cannot compensate for a diseased dominant |\ |\ |\ |\ |\ |\ |\ |\


allele. In order to answer this question one must understand the
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


above information and draw a Punnett Square.
|\ |\ |\ |\ |\ |\




The husband has an autosomal recessive disease which means
|\ |\ |\ |\ |\ |\ |\ |\ |\


his genotype must be aa. The wife has a heterozygous genotype
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


for the disease which means her genotype is Aa. The capital A
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


reflects a healthy gene so she is merely a carrier and does not
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


express the disease phenotype. The father's genotype is written
|\ |\ |\ |\ |\ |\ |\ |\ |\


across the top line and the mother's genotype is written in the
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


boxes to the left. The four boxes in the middle are the possible
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


genotypes of their offspring. Each box represents a 25% chance |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


for the offspring to have that particular genotype. The question
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\


asks you to determine the chances the offspring will have the
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


autosomal recessive disease or in other words, express the |\ |\ |\ |\ |\ |\ |\ |\ |\


phenotype for the disease. The genotype which will result in the |\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


disease is "aa." Therefore, there is a 50% chance that their
|\ |\ |\ |\ |\ |\ |\ |\ |\ |\ |\


offspring will have the autosomal recessive disease. |\ |\ |\ |\ |\ |\

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