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MATH 110: Algebra Module 1 (Class Notes)

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Module 1: Class Notes Detailed drawings, examples, and explanations of Module 1. Basic algebra summaries. The purpose is to help study and provide extra notes and assistance in class.

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Module 1 3 .

Solving Equations :




An equation is an
equivalence between two mathematical expressions
"
involving numbers represented by the equal sign" ,
=



Example : 5+ 3 = 8 24 3 72 .
=
3x + 2: 8 , 9t 3+ + 3 , etc
=
,
.
,




A solution is an value of "X" for which the equation holds true.


Example Verify that
: X= 2 is a solution to 3x + 2 =
.
8

set x=2
:

3(2) + 2 =
8 > 4+ z - = 8/

Example :
what about the solution of X +2= x + 3 ) = X+ 2


so value of "X" Works
any


How to solve an equation?

We need two principles.

1) Distributive Law
ex let a b
, c be number
·
,

a(b +x) = a -
b + a .
c =
(b + c)a
Example :
1(x+5) =
2x + 7 5 . :
2x + 10



2) Equivalence Law

If a +b = c
,
then +C = b+C ,




If a=b
,
the a -c = b -
c .




Example : X-2 = 8 > X - -
1+ 2 = 8 + 2 -> X =
10 .




2x = 4 -
> 5 .
2x =
t .
4 > X
- =
2 .




Solve the following.

a) 3x 4t 3x 6-2 >
3 =
+ 2 =
+ 2 -2 =
- - X

, b) z(x 3) - =
14
>
x=3 = = X 10
-
= .




2

Two equations ax = b and ex =d
.

are said to be equivalent if they have the same solutions.


Example :
We have X goats . We see 8 paws and y horns.

write equation.

2x =4 4x 8 =



horns legs

Example :
Check if they are equivalent
.



a) 3x 21 = and X +4 :
11



: X+ T

X = 11 -
4 = 7 - X =
7 v


b) 12-X 3 = and 2x = 20

V
-
1)-
X =
3 -




12) X =
20/2 = 10
X= d
# X = 18


not equivalent

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Uploaded on
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Number of pages
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Written in
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Type
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Professor(s)
Maico freitas
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