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Solutions Manual – Digital Signal Processing using MATLAB (3rd Edition, 2017)

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INSTANT PDF DOWNLOAD — Comprehensive Solutions Manual for Digital Signal Processing using MATLAB (3rd Edition, 2017) by Robert J. Schilling and Sandra L. Harris. Covers all 9 chapters with step-by-step MATLAB-based solutions for convolution, sampling, DFT/FFT, z-transforms, digital filters, and system analysis. Designed for engineering students and instructors in DSP, communications, and control systems. Digital Signal Processing, DSP Solutions, MATLAB, Robert Schilling, Sandra Harris, Signal Analysis, Sampling, Convolution, Discrete Fourier Transform, FFT, Z Transform, Digital Filters, Systems Analysis, Filter Design, Communication Systems, Engineering Math, MATLAB Examples, Electrical Engineering, Control Systems, Applied DSP, Frequency Response, Signal Processing Textbook

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ALL 9 CHAPTERS COVERED




SOLUTIONS MANUAL

, Contents
Chapter 1 1

Chapter 2 57

Chapter 3 155

Chapter 4 274

Chapter 5 384

Chapter 6 467

Chapter 7 572

Chapter 8 675

Chapter 9 765

, Chapter 1
1.1 Suppose the input to an amplifier is xa (t) = sin(2πF0 t) and the steady-state output is


ya (t) = 100 sin(2πF0 t + φ1 ) − 2 sin(4πF0 t + φ2 ) + cos(6πF0 t + φ3 )



(a) Is the amplifier a linear system or is it a nonlinear system?
(b) What is the gain of the amplifier?
(c) Find the average power of the output signal.
(d) What is the total harmonic distortion of the amplifier?


Solution


(a) The amplifier is nonlinear because the steady-state output contains harmonics.
(b) From (1.1.2), the amplifier gain is K = 100.
(c) From (1.2.4), the output power is


d20 1 2
d1 + d+ 22 + d23

Py = +
4 2
= .5(1002 + 22 + 1)
= 5002.5

(d) From (1.2.5)


100(Py − d21 /2)
THD =
Py
100(5002.5 − 5000)
=
5002.5
= .05%




© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.

1

, √
1.2 Consider the following signum function that returns the sign of its argument.


 1 , t>0

sgn(t) = 0 , t=0
−1 , t < 0




(a) Using Appendix 1, find the magnitude spectrum
(b) Find the phase spectrum


Solution


(a) From Table A2 in Appendix 1


1
Xa (f ) =
jπf


Thus the magnitude spectrum is


Aa (f ) = |Xa(f )|
1
=
|jπf |
1
=
π|f |


(b) The phase spectrum is


φa (f ) = 6 Xa (f )
= −6 jπf
π 
= −sgn(f )
2




© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.

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