surname names
Number Number
Morning (Time: 1 hour 30 minutes) Paper
B � �
Advanced Subsidiary
PAPER 1: Core Cellular Biology and Microbiology
Instructions
• Use black ink or ball-point pen.
centre number and candidate number.
Answer the questions in the spaces provided
– there may be more space than you need.
Information
• The total mark for this paper is 80.
– use this as a guide as to how much time to spend on each question.
In question(s) marked with an asterisk (*), marks will be awarded for your ability to
structure your answer logically, showing how the points that you make are
related or follow on from each other where appropriate.
Advice
• Read each question carefully before you start to answer it.
• Check your answers if you have time at the end.
Turn over
, Some questions must be answered with a cross in a box . If you change your mind about an
answer, put a line through the box and then mark your new answer with a cross .
1 Some carbohydrates are composed of three monosaccharides. These are
called trisaccharides.
Raffinose is a trisaccharide composed of glucose, galactose and fructose.
(a) Complete the diagram to show the structure of an alpha glucose molecule.
(2)
CH2OH
C O
H
C C
C C
(b) Name the bond that joins monosaccharides together.
(1)
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... .. . . ......................
(c) The three monosaccharides present in raffinose each have a molecular mass
of 180.
The relative atomic mass of the element hydrogen is 1 and the relative atomic
mass of the element oxygen is 16.
Calculate the molecular mass of raffinose.
(1)
Answer ....... .... .... .... .... .... .... ..... .... .... .... .... .... .... ..
(Total for Question 1 = 4 marks)
2
■■■■
,2 During the S phase of the cell cycle, DNA is synthesised by
semi-conservative replication.
The diagram shows part of a DNA molecule.
bases J and K
bases L and M
bond E
bond D bond F
(a) (i) Name the base pairs labelled J and K, L and M.
(2)
J and K . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . . .
L and M . . .. . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . ..... .... .... .... .... .... .... ..... .... .... .... .... .... .... .... .... .... .... .... ..... .... .... .... .... .... .... .... .... .... . ..... .
(1) Name the bonds labelled D, E and F.
(2)
Bond D . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . . .. . . . . .. . . . . .. . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .
Bond E . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . . .. . . . . .. . . . . . . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . ..
Bond F . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . .. . . . . .. . . . . . . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . ..
3
■■■■ Turn over
, (2) Part of a DNA molecule consists of 840 bases. Of these, 136 are base J.
Calculate the percentage of bases that are M in this DNA molecule.
Give your answer to two decimal places.
(1)
Answer ................................ %
(b) State what is meant by the term semi‑conservative replication.
(1)
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... .. . . ......................
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. .. . ... ... ... ... ... ... ... ... ... . ......................
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. . ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... . ......................
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... . ......................
(Total for Question 2 = 6 marks)
4
■■■■
Number Number
Morning (Time: 1 hour 30 minutes) Paper
B � �
Advanced Subsidiary
PAPER 1: Core Cellular Biology and Microbiology
Instructions
• Use black ink or ball-point pen.
centre number and candidate number.
Answer the questions in the spaces provided
– there may be more space than you need.
Information
• The total mark for this paper is 80.
– use this as a guide as to how much time to spend on each question.
In question(s) marked with an asterisk (*), marks will be awarded for your ability to
structure your answer logically, showing how the points that you make are
related or follow on from each other where appropriate.
Advice
• Read each question carefully before you start to answer it.
• Check your answers if you have time at the end.
Turn over
, Some questions must be answered with a cross in a box . If you change your mind about an
answer, put a line through the box and then mark your new answer with a cross .
1 Some carbohydrates are composed of three monosaccharides. These are
called trisaccharides.
Raffinose is a trisaccharide composed of glucose, galactose and fructose.
(a) Complete the diagram to show the structure of an alpha glucose molecule.
(2)
CH2OH
C O
H
C C
C C
(b) Name the bond that joins monosaccharides together.
(1)
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... .. . . ......................
(c) The three monosaccharides present in raffinose each have a molecular mass
of 180.
The relative atomic mass of the element hydrogen is 1 and the relative atomic
mass of the element oxygen is 16.
Calculate the molecular mass of raffinose.
(1)
Answer ....... .... .... .... .... .... .... ..... .... .... .... .... .... .... ..
(Total for Question 1 = 4 marks)
2
■■■■
,2 During the S phase of the cell cycle, DNA is synthesised by
semi-conservative replication.
The diagram shows part of a DNA molecule.
bases J and K
bases L and M
bond E
bond D bond F
(a) (i) Name the base pairs labelled J and K, L and M.
(2)
J and K . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . . .
L and M . . .. . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . . .. . ..... .... .... .... .... .... .... ..... .... .... .... .... .... .... .... .... .... .... .... ..... .... .... .... .... .... .... .... .... .... . ..... .
(1) Name the bonds labelled D, E and F.
(2)
Bond D . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . . .. . . . . .. . . . . .. . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .
Bond E . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . . . .. . . . . .. . . . . . . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . ..
Bond F . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . .. . . . . .. . . . . . . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . . .. . . . .. . . . . .. . . ..
3
■■■■ Turn over
, (2) Part of a DNA molecule consists of 840 bases. Of these, 136 are base J.
Calculate the percentage of bases that are M in this DNA molecule.
Give your answer to two decimal places.
(1)
Answer ................................ %
(b) State what is meant by the term semi‑conservative replication.
(1)
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... .. . . ......................
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. .. . ... ... ... ... ... ... ... ... ... . ......................
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. . ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... . ......................
.... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... ... .. . . ... ... .... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... .. ... ... ... ... ... ... ... ... ... ... . ......................
(Total for Question 2 = 6 marks)
4
■■■■
