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Solution Manual – Finite Mathematics & Its Applications, 13th Edition (Chapters 1–12 Complete, 2024 Update) – Larry J. Goldstein

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This is the Latest Updated (2024) Solution Manual for Finite Mathematics & Its Applications, 13th Edition by Larry J. Goldstein. What’s included: Complete, step-by-step solutions for Chapters 1–12 Fully worked-out answers to all textbook problems and exercises Accurate, detailed explanations for improved understanding Perfect for homework, assignments, quizzes, midterms, and finals Serves as a study guide to master finite mathematics concepts and applications Unlike a test bank (which provides exam-style practice questions), this solution manual delivers worked-out solutions, making it the perfect companion to the textbook. This resource is essential for students in mathematics, business, economics, and applied sciences, and is also valuable for anyone preparing for college-level math exams and professional assessments. Simplify complex problems, study smarter, and ace your math exams with this 2024 solution guide! Perfect Pair: Use this Solution Manual together with the Test Bank for complete learning and exam preparation.

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Institution
Finite Mathematics & Its Applications
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Finite Mathematics & Its Applications











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Institution
Finite Mathematics & Its Applications
Course
Finite Mathematics & Its Applications

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Uploaded on
October 8, 2025
Number of pages
710
Written in
2025/2026
Type
Exam (elaborations)
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SOLUTION MANUAL |




Finite Mathematics & Its Applications
| | | |




13th Edition by Larry J. Goldstein,
| | | | |




Chapters 1 - 12, Complete
| | | |

, Contents
Chapter 1: Linear Equations and Straight Lines
| | | | | 1–1

Chapter 2: Matrices
| 2–1

Chapter 3: Linear Programming, A Geometric Approach
| | | | | 3–1

Chapter 4: The Simplex Method
| | | 4–1

Chapter 5: Sets and Counting
| | | 5–1

Chapter 6: Probability
| 6–1

Chapter 7: Probability and Statistics
| | | 7–1

Chapter 8: Markov Processes
| | 8–1

Chapter 9: The Theory of Games
| | | | 9–1

Chapter 10: The Mathematics of Finance
| | | | 10–1

Chapter 11: Logic
| 11–1

Chapter 12: Difference Equations and Mathematical Models
| | | | | 12–1

, Chapter 1 |



Exercises |1.1 5
6. | Left |1, |down |

2
1. Right |2, |up |3 y
y



(2, |3)
x
x
( )
–1, | – |52|




7. | Left |20, |up |40
2. Left |1, |up |4 y
y

(–20, |40)
(–1, |4)
x
x




8. | Right |25, |up |30
3. | Down |2 y
y


(25, |30)
x
x
(0, |–2)




9. Point |Q |is |2 |units |to |the |left |and |2 |units |up |or
4. Right |2
y (—2,|2).

10. Point |P |is |3 |units |to |the |right |and |2 |units |down |or
(3,—2).
x
(2, |0) 1|
11. —2(1) |+ | (3) |=|—2 |+1|= |—1so | yes | the | point | is
3
on |the |line.

5. Left |2, |up |1 1|
y 12. —2(2) |+ | (6) |= |—1 |is | false, | so | no | the | point | is | not
3
on |the |line

(–2, |1)
x



Copyright |© |2023 |Pearson |Education, |Inc. 1-1

, Chapter |1: |Linear |Equations |and |Straight |Lines ISM: |Finite |Math


1| 24. | 0 |= |5
13 —2x |+ | y | = |—1 | Substitute | the | x | and | y no |solution
3
. x-intercept: |none
coordinates |of |the |point |into |the |equation:
|When |x |= |0, |y |=
f 1 | ıh| f h
' ,|3 →|—2 ' 1 ı +|1|(3)|=|—1|→|—1+1|=|—1 | is |5|y-intercept: |(0,
y' ı '
|5)
ı
| 2 | | |J y|2J 3
a |false |statement. |So |no |the |point |is |not 25. |When |y |= |0, |x |=
|on |the|line. |7 |x-intercept: |(7,

|0)|0 |= |7
f 1h f1 h
14 —2 ' ı + ' ı (—1) |=|—1 | is |true |so |yes |the |point |is no |solution
.
'y3 ıJ | | |'y3 ıJ y-intercept: |none
on |the |line. 26. | 0 |= |–8x
15. | m |= |5, |b |= |8 x |= |0
x-intercept: |(0, |0)
16. | m |= |–2 |and |b |= |–6 y |= |–8(0)
y |= |0
17. | y |= |0x |+ |3; |m |= |0, |b y-intercept: |(0, |0)
|= |3



2| 2| 1|
y |= | x|+|0; | m |= | , | b |= |0 27 0 |= | x |–|1
18 3
3 3 .
. x |= |3
19. | 14x|+|7|y |=|21 x-intercept: |(3, |0)
1|
7|y |=|—14x |+|21 y | = | (0) |–|1
3
y | =|—2x |+|3
y |= |–1
y-intercept: |(0, |–1)
20 x|— |y | =|3 y
. —y | =|—x |+|3
y | = |x|—|3
(3, |0)
21. | | | 3x |=|5 x
5 (0, |–1)
x |= |
3
1 2
28. When |x |= |0, |y |= |0.
22 – x |+ y | =|10
. 2 3 When |x |= |1, |y |= |2.
2| 1| y
y | = | x |+10
3 2
3|
y | = | x |+15 (1, |2)
4 x
(0, |0)

23. 0 |=|—4x |+|8
4x | = |8
x |= |2
x-intercept: |(2, |0)
y |= |–4(0) |+ |8
y |= |8

1-2 Copyright |© |2023 |Pearson |Education, |Inc.
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