1 | Page
NICET LEVEL 1 - WATER BASED LAYOUT
ACTUAL EXAM QUESTIONS AND
ANSWERS
Toggle hangers shall be permitted only for the support of pipe
__________ inches or smaller in size under ceilings of hollow
tile or metal lath and plaster. - correct answer- 1 2/2 in. (ref.
NFPA 13 2016 Sec. 9.2.1.1.2.
While conducting a flow test, the chosen hydrant should be
______ - correct answer- As close to the property where the
sprinkler system is being installed. (Ref, NFPA 13 Sec.
A.24.2.2. or NFPA 291)
What formula is used to determine the discharge coefficiant
relating pressure and flow rate? - correct answer- K = Q /
(Square root of P)
What best describes a tree system? - correct answer- Cross
mains and the branch lines are not tied together, providing only
one path of water flow.
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Factors that define Occupancy Group Hazard 2 include: -
correct answer- Quantity and combustibility of contents are
moderate to high.
Stockpiles of contents with moderate rates of heat release do
not exceed 12 ft and stockpiles with high heat release do not
exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the
installation of underground piping? - correct answer- NFPA 13
& 24 (Both in Chapter 10)
Which of the following should you inspect on an extension cord
before each use? - correct answer- The grounding prong & the
insulation for nicks, cuts, or damage
________ indicates a mandatory req. according to NFPA
definitions. - correct answer- Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
, 3 | Page
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How
many feet of 1 1/2 in. pipe will produce the same friction loss? -
correct answer- Assume this is Schedule 40 pipe, C = 120. Use
the Hazen-Williams formula to calculate the friction loss for the
1 ¼ in. pipe and the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
NICET LEVEL 1 - WATER BASED LAYOUT
ACTUAL EXAM QUESTIONS AND
ANSWERS
Toggle hangers shall be permitted only for the support of pipe
__________ inches or smaller in size under ceilings of hollow
tile or metal lath and plaster. - correct answer- 1 2/2 in. (ref.
NFPA 13 2016 Sec. 9.2.1.1.2.
While conducting a flow test, the chosen hydrant should be
______ - correct answer- As close to the property where the
sprinkler system is being installed. (Ref, NFPA 13 Sec.
A.24.2.2. or NFPA 291)
What formula is used to determine the discharge coefficiant
relating pressure and flow rate? - correct answer- K = Q /
(Square root of P)
What best describes a tree system? - correct answer- Cross
mains and the branch lines are not tied together, providing only
one path of water flow.
,2 | Page
Factors that define Occupancy Group Hazard 2 include: -
correct answer- Quantity and combustibility of contents are
moderate to high.
Stockpiles of contents with moderate rates of heat release do
not exceed 12 ft and stockpiles with high heat release do not
exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the
installation of underground piping? - correct answer- NFPA 13
& 24 (Both in Chapter 10)
Which of the following should you inspect on an extension cord
before each use? - correct answer- The grounding prong & the
insulation for nicks, cuts, or damage
________ indicates a mandatory req. according to NFPA
definitions. - correct answer- Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
, 3 | Page
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How
many feet of 1 1/2 in. pipe will produce the same friction loss? -
correct answer- Assume this is Schedule 40 pipe, C = 120. Use
the Hazen-Williams formula to calculate the friction loss for the
1 ¼ in. pipe and the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
