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Exam (elaborations)

Finite Mathematics & Its Applications – Larry J. Goldstein, 13th Edition, Complete Solution Manual (Chapters 1–12)

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This document contains the complete solution manual for Finite Mathematics & Its Applications, 13th edition, by Larry J. Goldstein. It provides step-by-step solutions to all exercises and problems from chapters 1 through 12. The material is comprehensive and follows the textbook structure, making it an excellent resource for practicing problem-solving, preparing for exams, and mastering key mathematical applications.

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Number of pages
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Written in
2025/2026
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SOLUTION MANUAL
Finite Mathematics & Its Applications
13th Edition by Larry J. Goldstein,
Chapters 1 - 12, Complete

, Contents
Chapter 1: Linear Equations and Straight Lines
md md md md md 1–1
Chapter 2: Matrices
md 2–1

Chapter 3: Linear Programming, A Geometric Approach
md md md md md 3–1

Chapter 4: The Simplex Method
md md md 4–1

Chapter 5: Sets and Counting
md md md 5–1

Chapter 6: Probability
md 6–1

Chapter 7: Probability and Statistics
md md md 7–1

Chapter 8: Markov Processes
md md 8–1

Chapter 9: The Theory of Games
md md md md 9–1

Chapter 10: The Mathematics of Finance
md md md md 10–1

Chapter 11: Logic
md 11–1

Chapter 12: Difference Equations and Mathematical Models
md md md md md 12–1

, Chapter 1
md




Exercises 1.1 5
md



6. Left 1, down
m d md md m d




2
1. Right 2, up 3 md md md

y
y


(2, 3)
md




x
x
( –1, – 52 m d dm
)
dm




7. Left 20, up 40
2. Left 1, up 4
m d md md md




md md md

y
y

(–20, 40)
(–1, 4)
md



md




x
x




8. Right 25, up 30
3. Down 2
m d md md md




m d md

y
y


(25, 30) md




x
x
(0, –2) md




9. Point Q is 2 units to the left and 2 units up or
4. Right 2
md md md md md md md md md md md md




md




y (—2,2). m
d




10. Point P is 3 units to the right and 2 units down or
md md md md md md md md md md md md




(3,—2).
x
(2, 0)
md



1
11. —2(1)+ (3) =—2+1=—1so yes the point is
md




m
d m
d md m
d m
d m
d m
d m d m d m d m d




3
on the line. md md




5. Left 2, up 1 1
12. —2(2)+ (6) =—1is false, so no the point is not
md

md md md


m
d md md m
d m
d m d m d m d m d m d m d m d




y
3
on the line md md




(–2, 1) md




x



Copyright © 2023 Pearson Education, Inc.
md md md md md 1-1

, Chapter 1: Linear Equations and Straight Lines md md md md md md ISM: Finite Math
md md




1 24. 0 = 5
m d md md




—2x + y =—1 Substitute the x and y
m d




13 md md m d m
d m d m d m d m d m d



no solution
3
md




. x-
coordinates of the point into the equation:
intercept: none
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f 1 hı f h
' ,3 →—2 ' 1 ı +1(3)=—1→—1+1=—1 is
md md


m
d
m
d m
d




When x = 0, y = 5y-
y' ı ' ı
m
d m
d m
d m
d m
d m
d m
d m
d m d
m
d
md md md md md md m
d




intercept: (0, 5)
m d




md md




2 J y2J 3 md md
m d m
d




a false statement. So no the point is not on thel
md md md md md md md md md md m
d
25. When y = 0, x = 7x-
md md md md md md md m
d




ine. intercept: (7, 0)0 md md m
d md




f 1h f1h =7 md




14 —2 ' ı + ' ı (—1) =—1 is true so yes the point is no solution
.
m
d m
d m d md md md md md md
md




'y3 ıJ 'y3 ıJ y-intercept: none md




mdmd md




on the line. md md


26. 0 = –8x
m d md md




15. m = 5, b = 8 m d md md md md md
x=0 md md




x-intercept: (0, 0) md md




16. m = –2 and b = –6
m d md md md md md md
y = –8(0) md md




y=0 md md




17. y = 0x + 3; m = 0, b = 3
m d md md md md md md md md md md
y-intercept: (0, 0) md md




2 2 1
0 = x –1
m d




y = x+0; m = , b =0 27
md m
d

md m d md m
d




18 md md m
d m
d m d m
d md m d md m
d




3
3 3 .
. x=3 md md




19. 14x+7y =21 x-intercept: (3, 0) md md




1
m d m
d m
d m
d md m
d




y = (0) –1
md




7y =—14x+21 m
d md m
d m
d m
d
m d m d md m
d




3
y =—2x +3
y = –1
m d m
d md m
d




md md




y-intercept: (0, –1) md md




20 x— y =3 m
d md m d m
d
y
. —y =—x+3 m d m
d m
d m
d




y = x— 3 m d md m
d m
d




(3, 0) x
21. 3x =5
md




mdmdm d md m
d




5 (0, –1)
x=
md




md md




3
1 2
28. When x = 0, y = 0.
– x+ y =10
md md md md md md




22 2
m
d




3
m d m
d




When x = 1, y = 2.
. md md md md md md




2 1 y
y = x +10
m d m d




m d m d md




3 2
3
y = x +15
m d




m d m d md

(1, 2) md




4 x
(0, 0) md




23. 0 =—4x +8 md m
d md m
d




4x = 8 m d md




x =2 md md




x-intercept: (2, 0) md md




y = –4(0) + 8
md md md md




y=8 md md




y-intercept: (0, 8) md md




1-2 Copyright © 2023 Pearson Education, Inc. md md md md md
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