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Samenvatting Metabolisme hoofdstuk 6: Globine familie

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Samenvatting van het vak metabolisme, hoofdstuk 6: "Globine familie", 2e bachelor biomedische wetenschappen, gegeven door Andy Wullaert

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Uploaded on
September 24, 2025
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Written in
2022/2023
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Hoofdstuk 6: De globine familie

Aëroob systeem: nood aan zuurstoftransport en -opslag  zuurstof moet alle cellen bereiken
(bloedbaan)

Nood aan sensoren  te veel of te weinig O2 signaleren:

 Hyperoxia vb. hyperventilatie
 Normoxia = normaal = 21% O2
 Hypoxia en ischemie vb. bergklimmers
Ischemie = tekort aan zuurstof en nutriënten door occlusie van bloedvat -> hartinfarct (hart)
of beroerte (hersenen)
Reperfusie of reoxygenatie = korte periode van herstel waar je opeens veel meer zuurstof
hebt -> schade door reactieve zuurstof species (ROS) of reactieve stikstof species (RNS)

Hemoglobine

- In rode bloedcellen
- Functie = zuurstoftransport
- Tetrameer: 4 globine eenheden met elk 8 alfa-helices en heemgroep
- Zuurstof bindt coöperatief aan hemoglobine
- Hb + nO2  Hb(O2)n met KA = [Hb(O2)n] / [Hb][O2]n = 1 / KB
n
pO2
- Y= n n = hill coefficient = maat van coöperativiteit
K B + pO 2
n = 1: niet coöperatief vb. Mb
n > 1: positief coöperatief vb. Hb
Y pO 2n
 Uitwerken naar functie waarbij we n kunnen bepalen: = =>
1−Y KB
Y
log =n . log pO 2−log Kb = hill vergelijking
1−Y
- Sigmoïdale curve
- Hill grafiek:



Evenwichtsreactie is niet meer
in evenwicht



Myoglobine

- In spiercellen
- Functie = zuurstofopslag
- 8 alfa-helices + heemgroep
- Monomeer: kan 1 molecule O2 binden: MbO2 = oxymyoglobine
- Mb + O2  MbO2 met KA = [MbO2] / [Mb][O2] = 1/KB
[MbO 2]
- Fractie Mb in oxy vorm: Y = => Y in functie van [O2] (.pO2) => Y =
[ Mb ] +[ MbO 2]
[O 2] pO 2 pO 2
=> Y = => Y =
Kd +[O 2] Kd + pO2 p 50 . pO 2
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