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AFOQT Math Knowledge UPDATED Exam Questions and CORRECT Answers

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AFOQT Math Knowledge UPDATED Exam Questions and CORRECT Answers

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Uploaded on
September 14, 2025
Number of pages
9
Written in
2025/2026
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Exam (elaborations)
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AFOQT Math Knowledge UPDATED Exam
Questions and CORRECT Answers
Slope-Intercept Form of a line - CORRECT ANSWER - y=mx+b



Terms of a line - CORRECT ANSWER - slope=m
b=y-intercept


Slope - CORRECT ANSWER - (y₂- y₁) / (x₂- x₁)
Rise over run
the steepness of a line on a graph, equal to its vertical change divided by its horizontal change


Standard form of a line - CORRECT ANSWER - Ax+By=C



x-intercept of a line - CORRECT ANSWER - C/A



y-intercept of a line - CORRECT ANSWER - C/B



Distance formula - CORRECT ANSWER - d = √[( x₂ - x₁)² + (y₂ - y₁)²]



Midpoint formula - CORRECT ANSWER - (x₁+x₂)/2, (y₁+y₂)/2



Parabola - CORRECT ANSWER - The U-shaped graph of a quadratic function



Zero/root of a quadratic - CORRECT ANSWER - X-intercepts of the parabola



Standard form of Quadratic Equation - CORRECT ANSWER - ax² + bx + c = 0, where

, a, b, and c are real numbers and
a ≠ 0.


Standard form of quadratic equation:

Axis of symmetry - CORRECT ANSWER - x=-b/2a



Standard form of quadratic equation: Vertex - CORRECT ANSWER - (-b/2a, f(-b/2a))



Vertex form of quadratic equation - CORRECT ANSWER - y = a(x - h)² + k; vertex is
(h,k), where "h" is always the opposite of what it appears to be in the ( )'s.,


Vertex form of quadratic equation:

Vertex - CORRECT ANSWER - (h,k)


Vertex form of quadratic equation:

Axis of symmetry - CORRECT ANSWER - x=h



Convert standard form to vertex form (quadratic equation) - CORRECT ANSWER -
Complete the square
1. Move c to the left side of equation
2. Divide entire equation by a
3. Take half of the coefficient of x, square that number, and then add the result to both sides of
the equation
4. Convert the right side of the equation to a perfect binomial squared, (x+m)^2
5. Isolate y to put the equation in proper vertex form


Quadratic formula - CORRECT ANSWER - x = -b ± √(b² - 4ac)/2a

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