WGU C959 UNIT 1 DISCRETE MATH EXAM 2025/2026 | VERIFIED QUESTIONS AND ACCURATE ANSWERS WITH EXPLANATIONS || 100% GUARANTEED PASS <UPDATED VERSION>

WGU C959 UNIT 1 DISCRETE MATH EXAM
2025/2026 | VERIFIED QUESTIONS AND
ACCURATE ANSWERS WITH EXPLANATIONS
|| 100% GUARANTEED PASS <UPDATED
VERSION>

WGU C959 - Discrete Mathematics I: Unit 1 Exam Prep

Topics Covered: Propositional Logic, Set Theory, Functions, and Basic Number Theory

Question 1:
Which of the following is the converse of the conditional statement: "If a number is divisible by
10, then it is divisible by 5"?
A) If a number is divisible by 5, then it is divisible by 10.
B) If a number is not divisible by 10, then it is not divisible by 5.
C) If a number is not divisible by 5, then it is not divisible by 10.
D) A number is divisible by 10 if and only if it is divisible by 5.

Answer:
A) If a number is divisible by 5, then it is divisible by 10.

Explanation:
The converse of a conditional statement "If P, then Q" is "If Q, then P". Here, P is "a number is
divisible by 10" and Q is "it is divisible by 5". Therefore, the converse is "If a number is divisible
by 5, then it is divisible by 10". Option B is the inverse, Option C is the contrapositive, and
Option D is a biconditional statement.



Question 2:
Let the universal set U be all integers from 1 to 10. Let A = {2, 4, 6, 8, 10} and B = {3, 6, 9}. What
is the set A ∩ Bᶜ (A intersect B complement)?
A) {1, 3, 5, 7, 9}
B) {2, 4, 8, 10}
C) {6}
D) {1, 5, 7}

, Answer:
B) {2, 4, 8, 10}

Explanation:
First, find Bᶜ, which is all elements in U that are not in B. U = {1,2,3,4,5,6,7,8,9,10}. B = {3,6,9}, so
Bᶜ = {1,2,4,5,7,8,10}. Now, find the intersection of A and Bᶜ: A ∩ Bᶜ = {2,4,6,8,10} ∩
{1,2,4,5,7,8,10} = {2, 4, 8, 10}. Note that 6 is in A but not in Bᶜ, so it is excluded from the
intersection.



Question 3:
What is the truth value of the following compound proposition if p is true, q is false, and r is
true?
(p ∨ ¬q) → (q ∧ r)
A) True
B) False

Answer:
B) False

Explanation:
Evaluate step-by-step:

1. p is T, q is F, so ¬q is T. Therefore, (p ∨ ¬q) is (T ∨ T) = T.

2. q is F, r is T, so (q ∧ r) is (F ∧ T) = F.

3. The implication (T → F) is False. An implication is false only when the hypothesis is true
and the conclusion is false, which is exactly the case here.



Question 4:
Consider the function f: ℝ → ℝ defined by f(x) = x². What is the best description of this
function?
A) It is injective (one-to-one) but not surjective (onto).
B) It is surjective (onto) but not injective (one-to-one).
C) It is both injective and surjective (bijective).
D) It is neither injective nor surjective.

Answer:
D) It is neither injective nor surjective.