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Chem 103:module 4 exam With CorreCt aCtual Questions and CorreCtly Well defined ansWers latest already Graded a+ 2025 – 2026

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Chem 103:module 4 exam With CorreCt aCtual Questions and CorreCtly Well defined ansWers latest already Graded a+ 2025 – 2026

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Chem 103:module 4
Course
Chem 103:module 4

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Chem 103:module 4 exam With CorreCt aCtual Questions and
CorreCtly Well defined ansWers latest already Graded a+
2025 – 2026




Combustion analysis can be used to - CORRECT ANSWER-identify an unknown hydrocarbon
because the identity of the products are known to be CO2 and H2O.



Empirical formulas are derived from experimentally measured element masses by - CORRECT
ANSWER---Deriving the number of moles of each element from its mass

--Dividing each element's molar amount by the smallest molar amount to yield subscripts for a
tentative empirical formula

--Multiplying all coefficients by an integer, if necessary, to ensure that the smallest whole-
number ratio of subscripts is obtained



Empirical formula - CORRECT ANSWER-a formula with the lowest whole-number ratio of
elements in a compound

Avogadro's number - CORRECT ANSWER-6.022 x 10^23 atoms = 1 mole



1 u = ___ g - CORRECT ANSWER-1.661 x 10 ^-24 g



formula mass - CORRECT ANSWER-the sum of the average atomic masses of each atom
represented in the chemical formula and is expressed in atomic mass units.

--The formula mass of a covalent compound is also called the molecular mass.

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Chem 103:module 4

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