PORTAGE LEARNING CHEMISTRY 103 FINAL EXAM STUDY GUIDE[MODULE 1-6
EXAM] 2025|26 LATEST UPDATE
MODULES 1-6
MODULE 1 – EXAM
Question 1 – Section 1.1
pts
Complete the two problems below:
1. Convert 1005.3 to exponential form and explain your answer.
2. Convert 4.87 x 10-6 to ordinary form and explain your answer.
Your Answer:
1.) Convert 1005.3 to exponential form and explain your answer:
All number values must be between 1-10. Because this value is greater than 1, the exponent remains positive.
In order for this to happen, we have to move the decimal three places to the LEFT thus, the exponential form of 1005.3 is: 1.0053 X 103
2.) Convert 4.87 x 10-6 to ordinary form and explain your answer.
All number values must be between 1-10. Because this value has a negative exponent, the final answer will be less than 1.
In order for this to happen, we have to move the decimal six places to the LEFT thus:
0.00000487
Question 2
pts
Complete the two problems below:
Using the following information, do the conversions shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10)
1. 3.6 pounds = ? oz
2. 2680 ml = ? liters
Your Answer:
1.) 3.6 pounds = 57.6 oz
1lb = 16oz
3.6(16) / 1 =57.6 oz
2.) 2680 ml = 2.68 liters
New/Old
https://www.stuvia.com/user/Mboffin
, Liters/Milliliters
https://www.stuvia.com/user/Mboffin
, 1L = 1,000mL
2,680/1,000
=2.68
Question 3
pts
Do the conversions shown below, showing all work:
1. 78oC = ? oK
2. 248oF = ? oC
3. 427oK = ? oF
Your Answer:
Kelvin is the larger
Fahrenheit is the middle
Celcius is the smaller
1.) 78oC = 351 oK
Add:
273+78 = 351K
2.) 248oF = 120 oC
Subtract 32 then divide by 1.8
248-32= 216
Now divide 216/1.8
=120
3.) 427oK = 309.2 oF
Kelvin to Fahrenheit needs to convert K to C then continue equation.
427-273 = 154oC
Celsius to Fahrenheit needs to multiply first then add 32
154 x 1.8 = 277.2
add 32
= 309.2
Question 4
pts
https://www.stuvia.com/user/Mboffin
EXAM] 2025|26 LATEST UPDATE
MODULES 1-6
MODULE 1 – EXAM
Question 1 – Section 1.1
pts
Complete the two problems below:
1. Convert 1005.3 to exponential form and explain your answer.
2. Convert 4.87 x 10-6 to ordinary form and explain your answer.
Your Answer:
1.) Convert 1005.3 to exponential form and explain your answer:
All number values must be between 1-10. Because this value is greater than 1, the exponent remains positive.
In order for this to happen, we have to move the decimal three places to the LEFT thus, the exponential form of 1005.3 is: 1.0053 X 103
2.) Convert 4.87 x 10-6 to ordinary form and explain your answer.
All number values must be between 1-10. Because this value has a negative exponent, the final answer will be less than 1.
In order for this to happen, we have to move the decimal six places to the LEFT thus:
0.00000487
Question 2
pts
Complete the two problems below:
Using the following information, do the conversions shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10)
1. 3.6 pounds = ? oz
2. 2680 ml = ? liters
Your Answer:
1.) 3.6 pounds = 57.6 oz
1lb = 16oz
3.6(16) / 1 =57.6 oz
2.) 2680 ml = 2.68 liters
New/Old
https://www.stuvia.com/user/Mboffin
, Liters/Milliliters
https://www.stuvia.com/user/Mboffin
, 1L = 1,000mL
2,680/1,000
=2.68
Question 3
pts
Do the conversions shown below, showing all work:
1. 78oC = ? oK
2. 248oF = ? oC
3. 427oK = ? oF
Your Answer:
Kelvin is the larger
Fahrenheit is the middle
Celcius is the smaller
1.) 78oC = 351 oK
Add:
273+78 = 351K
2.) 248oF = 120 oC
Subtract 32 then divide by 1.8
248-32= 216
Now divide 216/1.8
=120
3.) 427oK = 309.2 oF
Kelvin to Fahrenheit needs to convert K to C then continue equation.
427-273 = 154oC
Celsius to Fahrenheit needs to multiply first then add 32
154 x 1.8 = 277.2
add 32
= 309.2
Question 4
pts
https://www.stuvia.com/user/Mboffin
