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GCSE COMBINED SCIENCE PHYSICS PAPER 2 2025 AQA FU All the answers are shown in the explanation. Step-by-step explanation A 1.1) The velocity of the runner is increasing in the time interval 0 − 4 s and 7 s − 10 s . Hence the total time for which the velocity of the runner is increasing is given by T = 4 + 3 = 7 s A1.2) The runner is decelerating in the time period 14 s − 24 s . We know that the slope of the velocity-time graph gives the acceleration/deceleration. a = −(24−14)2 a = −0.2 m/s2 A1.3) If a person receives a call when running he does not need to physically take out the phone out of his pocket and bring close to his ears to take the call, he can just take the call via a Bluetooth device which he already had in his ear. A1.4) The required equation is given by λ = fc Here λ is the wavelength of the wave, c is the velocity of wave and f is the frequency of the wave. A1.5) The frequency of the wave, f = 24 × 108 Hz The velocity of the wave, c = 3 × 108 m/s The wavelength of the wave is given by λ = fc λ = 24×1083×108 λ = 0.125 m A1.6) a) The power consumed by the type 2 Bluetooth is 2.5 mW which is no
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