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Solution Manual for Finite Mathematics And Its Applications 13th Edition by Larry J. Goldstein,

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Uploaded on
July 6, 2025
Number of pages
664
Written in
2024/2025
Type
Exam (elaborations)
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SOLUTION MANUAL
Finite Mathematics & Its Applications
13th Edition by Larry J. Goldstein,
Chapters 1 - 12, Complete

, Contents
Chapter 1: Linear Equations and Straight Lines
is is is is is 1–1

Chapter 2: Matrices
is 2–1

Chapter 3: Linear Programming, A Geometric Approach
is is is is is 3–1

Chapter 4: The Simplex Method
is is is 4–1

Chapter 5: Sets and Counting
is is is 5–1

Chapter 6: Probability
is 6–1

Chapter 7: Probability and Statistics
is is is 7–1

Chapter 8: Markov Processes
is is 8–1

Chapter 9: The Theory of Games
is is is is 9–1

Chapter 10: The Mathematics of Finance
is is is is 10–1

Chapter 11: Logic
is 11–1

Chapter 12: Difference Equations and Mathematical Models
is is is is is 12–1

, Chapter 1
is




Exercises 1.1 5
is
6. Left 1, down
i s is is i s


2
1. Right 2, up 3 is is is
y
y



(2, 3)
is


x
x
( –1,i s –is25is )


7. i s Left 20, up 40 is is is

2. Left 1, up 4
is is is
y
y

(–20, 40) is
(–1, 4) is




x
x




8. i s Right 25, up 30 is is is

3. Down 2
i s is
y
y


(25, 30) is




x
x
(0, –2) is




9. Point Q is 2 units to the left and 2 units up or
is is is is is is is is is is is is

4. Right 2 is


y (—2,2). is




10. Point P is 3 units to the right and 2 units down or
is is is is is is is is is is is is



(3,—2).
x
(2, 0)
is
1 is

11. —2(1) + (3) =—2 +1= —1so yes the point is
is is is is is is is is is is is


3
on the line. is is




5. Left 2, up 1 1 is


12. —2(2) + (6) = —1 is false, so no the point is not
is is is
is is is is is is is is is is is is
y
3
on the line is is




(–2, 1) is
x



Copyright © 2023 Pearson Education, Inc.
is is is is is 1-1

, Chapter 1: Linear Equations and Straight Lines
is is is is is is ISM: Finite Math
is is




1 is 24. 0 = 5
i s is is


13 —2x + y = —1 Substitute the x and y
is is is is i s is is is is
no solution is

3
. x-intercept: is

coordinates of the point into the equation: is is is is is is


f 1 hı f h none When x =
' ,3 →—2 ' 1 ı +1(3)=—1→—1+1=—1 is
is is is is
is is is

0, y = 5y-
y' ı '
is is is is is is is is is i s is is is is

is
intercept: (0, 5)
ı2 J
is is

y2J 3
is is i s is



a false statement. So no the point is not on
is is is is is is is is is is 25. When y = 0, x = 7
is is is is is is is is



theline. is x-intercept: (7, 0) is is is




f 1h f1 h 0=7 is is



14 —2 ' ı + ' ı (—1) =—1 is true so yes the point is is is i s is is is is is is no solution
. is




'y3 ıJ 'y3 Jı y-intercept: none is

is is is



on the line. is is
26. 0 = –8x
i s is is




15. m = 5, b = 8
i s is is is is is
x=0 is is


x-intercept: (0, 0) is is




16. m = –2 and b = –6
i s is is is is is is
y = –8(0)
is is



y=0 is is



17. i s y = 0x + 3; m = 0, b =
is is is is is is is is is is
y-intercept: (0, 0) is is



3

2 2 1 is


y=
is

x+0; m = , b =0
is
27 0= x –1
is is is is

18 is is is is is is is is is is

3
3 3 .
. x=3 is is




19. 14x+7y =21
i s is is is is is
x-intercept: (3, 0) is is


1 is

7y =—14x +21 is is is is is
y = (0) –1
is is is is


3
y =—2x +3
is is is is
y = –1
is is


y-intercept: (0, –1) is is

20 x— y =3
is is is is
y
. —y =—x +3 is is is is




y = x —3 is is is si




(3, 0) is

21. 3x =5
is is i s is is
x
5 (0, –1) is

x= is is


3
1 2
28. When x = 0, y = 0. is is is is is is

22 – x+ is y =10 is is


. 2 3 When x = 1, y = 2. is is is is is is


2 is 1 is y
y= is is x +10 is


3 2
3 is

y= is is x +15 is
(1, 2) is

4 x
(0, 0) is




23. 0 =—4x +8 is is is is




4x = 8 is is



x =2 is is


x-intercept: (2, 0) is is


y = –4(0) + 8
is is is is


y=8
is is




1-2 Copyright © 2023 Pearson Education, Inc. is is is is is
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