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BIO 121 Past Exam and Practice UPDATED ACTUAL Exam Questions and CORRECT Answers

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BIO 121 Past Exam and Practice UPDATED ACTUAL Exam Questions and CORRECT Answers Eukaryotes employ several forms of sexual reproduction A. Vegetative reproduction that involves mitosis B. Parthenogenesis that is the production of an organism from an unfertilized egg C. Hermaphroditism that involves both gametes from a single parent D. Two of the above E. All of the above - CORRECT ANSWER - C Hermaphroditism is most common among species that: - CORRECT ANSWER sessile (organisms fixed in place) - Ar

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BIO 121 Past Exam and Practice UPDATED
ACTUAL Exam Questions and CORRECT
Answers
Eukaryotes employ several forms of sexual reproduction
A. Vegetative reproduction that involves mitosis
B. Parthenogenesis that is the production of an organism from an unfertilized egg
C. Hermaphroditism that involves both gametes from a single parent
D. Two of the above

E. All of the above - CORRECT ANSWER -C



Hermaphroditism is most common among species that: - CORRECT ANSWER - Are
sessile (organisms fixed in place)


A cell has a diploid chromosome number of 2n = 4. We will designate these four as
chromosomes "A", "B", "C", and "D". If meiosis occurred WITH the formation of homologous
pairs "AC" and "BD", and the chromosomes were then distributed randomly between the
resulting cells, how many gametes could be formed? - CORRECT ANSWER - 4 (AB, AD,
BC, CD)


In wonderland, the red queen said to alice, "You have to run faster than that just to stay in place."
According to the material in the course, the biological hypothesis that corresponds to this idea is:
- CORRECT ANSWER - Genetic variability is needed to keep up with new adaptations of
potential predators and parasites


When Chlamydomonas utilizes sexual reproduction:
A. Adults use mitosis to produce haploid gametes which are morphologically indistinguishable
B. Stressful environmental conditions such as nutrient shortages appear to trigger the onset of
this reproductive mode
C. Syngamy and then meiosis combine to produce haploid adults
D. More than one of the above

,E. All of the above - CORRECT ANSWER - E. All of the above


Some cells do not divide (muscle/nerve cells). This means that during the cell cycle, they remain
in:
A. G0 phase
B. Gi phase
C. Interphase
D. Two of the above

E. All of the above - CORRECT ANSWER - D. Two of the above


Pairs of homologous chromosomes _____
A. are exact copies of each other
B. Share a single centromere
C. Separate during anaphase II
D. Are present together in the cells produced at the end of meiosis

E. None of the above - CORRECT ANSWER - E. None of the Above


Cancer kills millions of people worldwide. Characteristics of cancer cells include:
A. Mutations that activate oncogenes so that there is a constant signal to divide
B. Enormous ability to replicate themselves and metastisize
C. Mutation that inactivate tumor suppressor genes that normally inhibit division
D. Two of the above

E. All of the above - CORRECT ANSWER - E. All of the above


Following meiosis II, an organism's gametes contain 7 chromosomes. In prophase I, this dividing
cell contained ___ chromosomes with __ chromatids each. - CORRECT ANSWER - 14, 2


The diploid chromosome number for a certain plant species is 10. In a section of tissue from the
plant you observe a dividing cell and notice its chromosomes are in two separate clusters. Closer

,examination reveals that each group contains 5 double stranded chromosomes. The cell is in: -
CORRECT ANSWER - Anaphase of meiosis I


Below is a graph of CO2 concentration in the northern (solid line) and southern hemisphere
(dashed kine). What is most likely driving these oscillations? - CORRECT ANSWER - In
the northern hemisphere, photosynthesis by plants in summer generates a CO2 decrease


During Pre-synthesis interphase before meiosis a cell has 1 g of DNA. Are each of the resulting
cells diploid or haploid and how many grams of DNA does each cell contain at the end of
meiosis 1 and meiosis 2? - CORRECT ANSWER - End of meiosis 1: Haploid with 1 g
DNA; End of meiosis @: Haploid with 0.5 g DNA


Genetic differences among siblings can be the results of:
A. Nondisjunction
B. Chromosomes from mom and dad lining up independently during telophase I
C. Crossing over (recombination)
D. Two of the above

E. all of the above - CORRECT ANSWER - C. Crossing Over


In terms of photosynthesis with which of the following would you agree?
A. the wavelengths of light that are absorbed by pigments are generally the ones that result in
high PHS activity
B. the source of carbon for the dark reaction is CO2
C. Oxygen produced during photosynthesis comes from the cleavage of H2O
D. two of the above

E. all of the above - CORRECT ANSWER - all of the above


CAM plants have evolved a particular adaptation that allows tham to inhabit hot, dry
environments and this adaptation involves: - CORRECT ANSWER - The utilization
production of PEP corboxylase

, In terms of reproduction with which of the following would you agree?
A. the random alignment of homologues in meiosis I can lead to genetic variation
B. babies conceived using IVF exhibit genetic variation among siblings
C. Sexual reproduction is not necessary for the evolution of all organisms
D. two of the above

E. all of the above - CORRECT ANSWER - E. all of the above


Imagine Photosystem I is broken but all other parts of photosynthesis function normally. What
molecules accumulate in the Calcin cycle and why? - CORRECT ANSWER - PGA
accumulates because there is not enough NADPre to supply electrons for the reaction


although c3 and c4 plants both perform the Calvin cycle, differences exist in which of the
following ways?
A. primary CO2 acceptor molecules; C3 plants use RuBp and C4 plants use PEP
B. C4 plants use more energy than C3 plants to get CO2 into the Calvin Cycle
C. The level of photorespiration can be extensive in C3 plants, but minimal in C4 plants
D. Two of the above

E. All of the above - CORRECT ANSWER - All of the above


If photosynthesizing green algae are provided with CO2 synthesized with heavy oxygen (18O),
later analysis will show which of the following compounds does not contain the 18O label -
CORRECT ANSWER - O2


Suppose that you are measuring CO2 exchange by a leaf. During the time period of your
measurement, 8 x 10^6 molecules of phosphoglyceraldehyde (PGAL) are made from CO2 in
photosynthesis and 6 x 10^6 molecules of pyruvate are used in cellular respiration. How many
net molecules of CO2 would you detect being taken up by the lead in your measurement? -
CORRECT ANSWER - 8 x 10^6 PGAL (3 Carbons) = 24 x 10^6
6 x 10^6 pyruvates (3 Carbons) = 18 x 10^6


Total = 24-18 = 6 x 10^6

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