Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12) complete newest version

SOLUTION MANUA
Finite Mathematics & Its Application
13th Edition by Larry J. Goldstein
Chapters 1 - 12, Complete

, Contents
Chapter 1: Linear Equations and Straight Lines
dl dl dl dl dl 1–1
Chapter 2: Matrices
dl 2–1

Chapter 3: Linear Programming, A Geometric Approach
dl dl dl dl dl 3–1

Chapter 4: The Simplex Method
dl dl dl 4–1

Chapter 5: Sets and Counting
dl dl dl 5–1

Chapter 6: Probability
dl 6–1

Chapter 7: Probability and Statistics
dl dl dl 7–1

Chapter 8: Markov Processes
dl dl 8–1

Chapter 9: The Theory of Games
dl dl dl dl 9–1

Chapter 10: The Mathematics of Finance
dl dl dl dl 10–1

Chapter 11: Logic
dl 11–1

Chapter 12: Difference Equations and Mathematical Models
dl dl dl dl dl 12–1

, Chapter 1
dl




Exercises 1.1 5
dl

6. Left 1, down
d l dl dl d l




2
1. Right 2, up 3 dl dl dl
y
y


(2, 3)
dl



x
x
( –1, – 52 dl dl )
dl




7. Left 20, up 40
d l dl dl dl


2. Left 1, up 4
dl dl dl
y
y

(–20, 40) dl

(–1, 4) dl




x
x




8. Right 25, up 30
d l dl dl dl


3. Down 2
d l dl
y
y


(25, 30) dl




x
x
(0, –2) dl




9. Point Q is 2 units to the left and 2 units up or
dl dl dl dl dl dl dl dl dl dl dl dl


4. Right 2 dl



y (—2,2). dl




10. Point P is 3 units to the right and 2 units down or
dl dl dl dl dl dl dl dl dl dl dl dl




(3,—2).
x
(2, 0)
dl
1 dl



11. —2(1) + (3) =—2+1= —1so yes the point isdl dl dl dl dl dl dl dl dl dl dl




3
on the line. dl dl




5. Left 2, up 1 1 dl




12. —2(2) + (6) = —1is false, so no the point is not
dl dl dl
dl dl dl dl dl dl dl dl dl dl dl dl

y
3
on the line dl dl




(–2, 1) dl

x



Copyright © 2023 Pearson Education, Inc.
dl dl dl dl dl 1-1

, Chapter 1: Linear Equations and Straight Lines
dl dl dl dl dl dl ISM: Finite Math
dl dl




1 d l
24. 0 = 5
d l dl dl




13 —2x + y = —1 Substitute the x and y dl dl dl dl d l dl dl dl dl
no solution dl


3
. x-
coordinates of the point into the equation: dl dl dl dl dl dl



f 1 hı f h intercept: none
' ,3 →—2 ' 1 ı +1(3)=—1→—1+1=—1 is
dl dl
d
l
dl d
l


When x = 0, y = 5y
y' ı ' ı
d
l d
l d
l d
l d
l d
l d
l d
l d
l d l
dl dl dl dl dl dl d
l


d l

-intercept: (0, 5) dl dl



2 J y2J 3 dldld l d
l




a false statement. So no the point is not on the
dl dl dl dl dl dl dl dl dl dl d
l 25. When y = 0, x = 7x-
dl dl dl dl dl dl dl d
l




line. intercept: (7, 0)0 dl dl d
l dl




f 1h f1h =7 dl




14 —2 ' ı + ' ı (—1) =—1 is true so yes the point is no solution
.
dl d
l d l dl dl dl dl dl dl dl




'y3 ıJ 'y3 ıJ y-intercept: none dl

dldldl




on the line. dl dl
26. 0 = –8x
d l dl dl




15. m = 5, b = 8
d l dl dl dl dl dl
x=0 dl dl




x-intercept: (0, 0) dl dl




16. m = –2 and b = –6
d l dl dl dl dl dl dl
y = –8(0)
dl dl




y=0 dl dl




17. y = 0x + 3; m = 0, b = 3
d l dl dl dl dl dl dl dl dl dl dl
y-intercept: (0, 0) dl dl




2 2 1 dl




y = x+0; m = , b =0
dl dl

27 0 = x –1
dl dl dl dl


18 dl dl ld d
l dl dl dl dl dl dl

3
3 3 .
. x=3 dl dl




19. 14x+7y =21
d l dl d
l d
l dl dl
x-intercept: (3, 0) dl dl




1 dl



7y =—14x +21
dl dl dl dl dl
y = (0) –1
dl dl dl dl




3
y =—2x +3
y = –1
dl dl dl dl

dl dl




y-intercept: (0, –1) dl dl


20 x— y =3
ld dl dl dl
y
. —y =—x +3 dl dl dl dl




y = x —3 dl dl ld dl




(3, 0) dl
x
21. 3x =5
dldld l dl d
l




5 (0, –1) dl


x= dl dl




3
1 2
28. When x = 0, y = 0.
– x+ y =1 0
dl dl dl dl dl dl



22 2
dl


3
dl dl


When x = 1, y = 2.
. dl dl dl dl dl dl




2 d l 1 dl
y
y = x +10
dl dl dl




3 2
3 dl


y = x +15
dl dl dl
(1, 2) dl


4 x
(0, 0) dl




23. 0 =—4x +8 dl dl dl dl




4x = 8 dl dl




x =2 dl dl




x-intercept: (2, 0) dl dl




y = –4(0) + 8
dl dl dl dl




y=8 dl dl




y-intercept: (0, 8) dl dl




1-2 Copyright © 2023 Pearson Education, Inc. dl dl dl dl dl