Notes
, Chapter 1- Structure and Bonding
·
Octect rule is ESSENTIAL to understanding bonding 3 molecules
-Group number informs you about the bonding capacity = now much covalent bonds can be formed
↳ 4 bonds (Tetravelent) ,
3 bonds (trivalent) ,
2 bonds (divalent) , I bond (monovalent)
·
Hydrocarbons-made from CBH-carbon bond to another carbon forms carbon chains
FUNCTIONAL GROUPS Constitutional isomer (Structural isomer) -
Alkane all single bonds c -
c -
C compounds w/ the same formula but dif. Structure
Alkene one or more double bond C= c -
C
Alkyne one or more triple bond C= C -
C When figuring out the dif . Isomer start w the
bond at the end of the chain
your way down
Alcohol OH C-C-OH longest chain work
Ether 0 the middle of the chain c- c C Make sure you don't repeat any (symmetrical
-
in
-
-
.
Aldenyde O double bond at the end of the chain C -
c -
C -
H chains)
G
Ketone O double bond i n the middle of the c- Try dif. functional (alcohol Bester ,
c
groups
-
-
chain aldenyde Ketones)
Alkyl halide Any halogen bond to the carbon chain C -
c -
C
-
Y
Arene Carbon circle , with 3 double 33
single bonds C formal charges
11
Esters carbon double bond to an oxygen c
-
c -
o -
C formal charge = valence e-dots-lines
single bond to an o in the middle -
Number assign to an atom to reflect the
⑮
Carboxylic carbon double bond to an0 3 C -
C -
OH number of valence electron
acid single bond to of lat the end) If
you take away a H the formal charge becomes
Amine carbon bond to any N C -
C -
Ny negative
Amide Carbon double bond to an bond C -
- NHe
C If you add the
a formal charge become positive
to NHZ Carbocation -
Carbon with a positive formal charge
Carbanion-Carbon with a negative formal charge
Molecular Representation
Full-write out all the , H
C , est with bond lines Bond-line Structure
partial condensed -
wo need to show bond lines w/H make sure that is goes with the molecular
Bond line- Each angle is one carbon ,
don't write H
geometry
but write out all dif .
atoms eX . Hz) =
CHCHz((CH3) 3
eX .
Full or
- only way to draw because its
In
-
H etrahedral (can't
+ have both
condensed branches pointing down
CH3COzCH3 ex .
CH3C = CCHzCH3
Bond line
i Try to make the its linear so theres no
- angles 1200 angle from carbon 1- 4
Electronegativity EN Difference
the relative ability to attract shared e 4 EN <O . S nonpolar covalent bund
EN : F > 0xC1 > N > Br > S > . . . ) H >>> metals -EN o S-1
.
. 7
polar covalent bund
Atom w/ the stronger EN gets 5- and the DEN) 1 7
.
IOniC bond
weaker gets St in a
polar covalent bond
-
label the atom w/ a + or-based on the
Non polar covalent -
equal En con sign
lonic bond-an atom lose an e ibond between metal nonmetal
,eX . Molecular Polarity Polar v .
Nonpolar solvents
A molecule will be nonpolar Dielectric constant (5) the
-
-
1) When a molecule has no polar bonds polarity per unt volume (size)
2) When a molecule has polar bond , but it is The smaller the molecule , the
symmetrical dipoles cancel out more powerful the polar group
ex-
so the
-
-
Polar solvents-water , acetone
-11)
H eX 0 = c = 0 Medium Polar solvents -
H H
.
nonpolar polar ethyl acetate , acetic acid
Hydrocarbons are usually nonpolar Nonpolar solvent-diethyl ether ,
nexane
Dissolving compounds in a solvent
Dissolving NaCl in water
Na has a positive charge so attracted to the 8 8
3
it
-
is on
6 molecules usually surround the o n
-
CI has a
negative charge so it is attracted to the Ston H
-
the bond between them is on-dipole interactions
H -
o. HH ci----
*
molecules surround
Dissolving NaOCH3 In acetone
08
CHzCOCH3
#
H20 the lons
+
- I
"H
* "
5
Na ---- St
>
Na + 0
- -
-
H
they disappear a
o
CH3
-
until -
* 'd
o !--- -
O
o
Na---
=0
%g
, Chapter 2- Molecular
How
Representation
Valence
1
do atoms form
covalent
Bond
bond
Theory
a covalent bond
is formed when
?
two half
Hybridization
ex .
CH4-shape
Sp3
is tetrahedral DC USEPR
filled orbitals overlap unhybridized C Hybridized C
2 . The greater the overlap , the stronger F
1 1
I
Energy levels is between
more stable the bond
Sp
PX Py P2 HV
+
-
O bond : head to head relatively stronger
No place 1
-
it bond : side to side
for 4H + O
Sp3 Sp3 Sp3 Sp3
Doesn't explain molecular geometry , bonding pattern 2S gs
same energy Shape
-
It CH4-carbon doesn't have 4 half filled for 4
space
.
& has H
orbitals there would be an H bonded to 25
B3 bonded to 2p Sp3
ex .
H20- >
sp3 hybridized
Hybridization sp2
molecular geometry : Trigonal planar unhybridized o Hybridized O
>
ex .
C2H
-
Two lone HL
pairs
E -1177
unhybridized C Hybridized C Hybridized C -
These make a it bond PX Py P2 1uju
1v 15
1
Sp3 Sp3
11 H H
1 HL HV Sp3 Sp3
+
1
I
PX Py P2 1v1 -
7 P2
11 HV
Sp2 Sp2 Spz Sp2 Spa
Sp2
11 1V
2S T 1V
11
O
V
~ These two 11
ja
Orbitals bond H
3) make o bond
1 -
i bond
H11 Hybridization sp
H
C
C
H1)
H ex-C2Hz-molecular geometry : linear
o bond
unhybridized C
E1
11
PX Py PL
characteristic of sp , Sp
>
&Sp3
11
2S
S orbital = short 3 fat Hybridized C Hybridized C
porbital =
long & thin
1 1
11 11
PY P2 H Py
H P2
S +
p
=
Sp (50 % S) closes to nucleus
14 1
spa (33 % 5)
P
+ =
S p
+
p
Sp Sp
s
+
p +
p +
p
=
sp3(25y S) .
farthest to nucleus
single bond-longest bond length weakest , -bond/ V
triple bond-shortest bond length , strongest
H C 11 C 11 H
L
n
. abond
1 ↓