Brae Exam 3 Questions well answered (verified) already passed

Brae Exam 3 Questions well answered (verified)
already passed
1. Soil AWHC = 1.0 in/ft. Crop
63%
RZ
With perfect timing, AE = DU * (1-PI losses)
= 3 ft. MAD = 49%. ETc
0.21
in/day. DU = 0.70. PI
Losses = 10%. What is the
Application Ef- ficiency (%)
with perfect tim- ing?
83%
2. Same facts as above. AE = DU * (1-losses)
Improv- ing the DU to
0.86 and reduc- ing the PI
losses to 4% would
2.59 inches
improve the AE (%) to
what? RZ AWHC (in) = AWHC (in/ft) * RZ (ft)
Max allowed SMD (in) = RZ AWHC * MAD/100
3. Soil AWHC = 1.5 in/ft. Crop
RZ
= 2 ft. MAD = 54%. ETc =
0.25
in/day. DU = 0.77. PI Losses
= 4%. (Ignore salinity, i.e.,
LR =
0). What is Dmax for the irriga- With perfect timing, Dmin = SMDmax at the time
of irrigation
tion? in/day. DU = 0.76. PI Losses = 9%.
(Ignore salinity, i.e., LR =
4. Soil AWHC = 1.2 in/ft. Crop
RZ
= 3 ft. MAD = 46%. ETc =
0.26
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, Brae Exam 3 Questions well answered (verified)
already passed
Dave = Dmin ÷ DU
Dmax =Dave + (Dave- - Dmin ) RZ AWHC (in) = AWHC (in/ft) * RZ (ft)
Max allowed SMD (in) = RZ AWHC * MAD/100
0.22 inch
0). What are the pre-infiltration With perfect timing, Dmin = SMDmax at the time
of irrigation.
losses in inches? Assume This is the requirement.
per- fect timing. Dave (in) = Dmin (in) ÷
DU
Gross depth (in) = Dave ÷ (1- PI losses)
Pre-Infiltration losses (in) = Gross depth (in) * PI losses

5. Given: An irrigation system de- 7.05 days
signed to apply water with aTime since last irrigation (days) = Current SMD (in) ÷ ET
DU = 0.74. ETc = 0.22 rate (in/day)
in/day.




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