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Summary Ultimate Physics Formula Book | All Important Formulas with Easy Explanations for Exam Success

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This Ultimate Physics Formula Book contains all the important formulas from key topics like Mechanics, Thermodynamics, Electromagnetism, Optics, Modern Physics, and more. Each formula is presented with easy explanations and practical examples to help students understand quickly. Perfect for exam preparation, last-minute revisions, and assignment support. Designed for college & university students, this formula book makes physics simple and accessible. Whether you're a beginner or need a quick reference, this guide is essential for success in physics courses.

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Uploaded on
May 13, 2025
Number of pages
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Written in
2024/2025
Type
Summary

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CLASS 12 : PHYSICS
FORMULA
BOOK
ELECTRIC CHARGES AND FIELDS 1 q
(ii) At very large distance i.e. r >> a E =
4 πε 0 r 2
k q1q2 1 q1q2
‰ Coulomb’s law : F = =
r 2 4 πε r 2 ‰ Torque on an electric dipole placed in a uniform
  
‰ Relative permittivity or dielectric constant : electric field : τ = p × E or τ = pE sin θ
ε ‰ Potential energy of an electric dipole in a
i.e., ε r or K =
ε0 uniform electric field is U = –pE(cosq2 – cosq1)
‰ Electric field intensity at a point distant r from where q1 & q1 are initial angle and final angle
1 q
a point charge q is E = . between
4 πε 0 r 2
 
‰ Electric dipole momentm, ‰ Electric flux φ = E ⋅ dS

‰ Electric field intensity on axial line (end on ‰ Gauss’s law :
position) of the electric dipole
‰ Electric field due to thin infinitely long straight
(i) At the point r from the centre of the electric
wire of uniform linear charge density l
1 2 pr
dipole, E = . λ
4 πε 0 (r 2 − a 2 )2 E= ,
2 πε 0r
(ii) At very large distance i.e., (r > > a), (i) At a point outside the shell i.e., r > R
2p
E= 1 q
4 πε 0r 3 E=
4 πε 0 r 2
‰ Electric field intensity on equatorial line (board (ii) At a point on the shell i.e., r = R
on position) of electric dipole
1 q
E=
(i) At the point at a distance r from the centre 4 πε 0 R 2
1 p (iii) At a point inside the shell i.e., r < R
of electric dipole, E = .
4 πε 0 (r 2 + a 2 )
E=0
(ii) At very large distance i.e., r > > a, ‰ Electric field due to a non conducting solid
1 p
sphere of uniform volume charge density r
E= . and radius R at a point distant r from the centre
4 πε 0 r 3
of the sphere is given as follows :
‰ Electric field intensity at any point due to an (i) At a point outside the sphere i.e., r > R
1 p 1 q
electric dipole E = 1 + 3 cos 2 θ E= ·
4 πε 0 r 3 4 πε 0 r 2
‰ Electric field intensity due to a charged ring (ii) At a point on the surface of the sphere
(i) At a point on its axis at distance r from its i.e., r = R
1 q
1 qr E= ·
centre, E = 4 πε 0 R 2
4 πε 0 (r + a 2 )
2



Physics 1

, (iii) At a point inside the sphere i.e., r < R  
‰ Relationship between E and V
ρr 1 q r  
E= = · , for r < R E = −∇V
3ε 0 4 πε 0 R 3
‰ Electric field due to a thin non conducting where
infinite sheet of charge with uniformly charge
surface density s is E =
σ ‰ Electric potential energy of a system of two
2ε0 1 q1q2
point charges is U =
‰ Electric field between two infinite thin plane 4 πε 0 r12
parallel sheets of uniform surface charge ‰ Capacitance of a spherical conductor of radius
density s and – s is E = s/e0. R is C = 4pe0R

ELECTROSTATIC POTENTIAL AND ‰ Capacitance of an air filled parallel plate
CAPACITANCE capacitor
W Capacitance of an air filled spherical capacitor
‰ Electric potential V = ‰
q
ab
‰ Electric potential at a point distant r from a C = 4 πε 0
b−a
point charge q is V = q
4 πε 0r
‰ Capacitance of an air filled cylindrical capacitor
‰ The electric potential at point due to an electric 2 πε 0 L
C=
dipole  b
ln  
1 p cos θ  a
V=
4 πε 0 r 2 ‰ Capacitance of a parallel plate capacitor
‰ Electric potential due to a uniformly charged with a dielectric slab of dielectric constant K,
spherical shell of uniform surface charge completely filled between the plates of the
density s and radius R at a distance r from the
capacitor, is given by
centre the shell is given as follows :
(i) At a point outside the shell i.e., r > R ‰ When a dielectric slab of thickness t and
1 q dielectric constant K is introduced between the
V=
4 πε 0 r plates, then the capacitance of a parallel plate
(ii) At a point on the shell i.e., r = R ε0 A
1 q capacitor is given by C =
V=  1
4 πε 0 R d − t  1 − 
K
(iii) At a point inside the shell i.e., r > R
1 q ‰ When a metallic conductor of thickness t is
V= introduced between the plates, then capacitance
4 πε 0 R
‰ Electric potential due to a non-conducting solid of a parallel plate capacitor is given by
sphere of uniform volume charge density r and
radius R distant r from the sphere is given as
follows : ‰ Energy stored in a capacitor :
(i) At a point outside the sphere i.e. r > R 1 1 1 Q2
1 q U= CV 2 = QV =
V= 2 2 2 C
4 πε0 r 1
‰ Energy density : u = ε 0E 2
(ii) At a point on the sphere i.e., r = R 2
1 q
V= 1 1 1 1
4 πε 0 R ‰ Capacitors in series : = + + .... +
CS C1 C2 Cn
(iii) At a point inside the sphere i.e., r < R
1 q( 3R 2 − r 2 ) ‰ Capacitors in parallel : CP = C1 + C2 + .... + Cn
V=
4 πε 0 2R3



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