Solution Manual for Applied Strength of Materials, 7th Edition by Robert L. Mott and Joseph A. Untener All Chapters 1-14 Covered with questions and answers.

Solution Manual for Applied Strength of Materials, 7th Edition by Robert
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. Mott and Joseph A. Untener All Chapters 1-
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14 Fully Covered With Questions And Correct Guided Answers
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SOLUTIONS MANUAL FOR APPLIED STRENGTH
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bdbd OF MATERIALS bd




7th Edition bd




Complete Chapter Solutions Manua
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l are included (Ch 1 to 14)
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by

Robert L. Mott Jos bd bd bd




eph A. Untener bd bd




** Immediate Download
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** Swift Response
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** All Chapters included
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,1. Basic Concepts in Strength of Materials
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2. Design Properties of Materials
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3. Direct Stress, Deformation, and Design
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4. Design for Direct Shear, Torsional Shear, and Torsional Deform
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ion
5. Shearing Forces and Bending Moments in Beams
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6. Centroids and Moments of Inertia of Areas
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7. Stress due to Bending
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8. Shearing Stresses in Beams
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9. Deflection of Beams
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10. Combined Stresses
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11. Columns
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12. Pressure Vessels
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13. Connections
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14. Thermal Effects and Elements of More than One Material
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Chapterbd1 BasicbdConceptsbdinbdStrengthbdofbdMaterials
1.1bdtobd1.11bdAnswersbdinbdtext.
1.12 𝑊bd=bd𝑚bd∙bd𝑔bd=bd1400bdkgbd∙bd9.81bdm/s2bd=bd13bd734bd(kgbd∙bdm)/s2bd=bd14bd×bd103bdN
𝑾bd=bd𝟏3.bd𝟕bd𝐤𝐍
1.13 TotalbdWeightbd=bd𝑚𝑔bd=bd3500bdkgbd∙bd9.81bdm/s2bd=bd34.34bdkN
1
EachbdFrontbdWheel:bd𝐹𝐹b d 2=bd ( )bd(0.40)(34.34bdkN)bd=bd6.87bd𝐤𝐍
1
EachbdRearbdWheel:bd𝐹𝑅b d 2=b d ( )bd(0.60)(34.34bdkN)bd=bd𝟏0.32bd𝐤𝐍

1.14 Loadingbd=bdTotalbdForcebd/bdArea
TotalbdForcebd=bd𝑚𝑔bd=bd5900bdkgbd∙bd9.81bdm/s2bd=bd57
.9bdkNbdAreabd=bd(4.5bdm)(3.5bdm)bd=bd15.8bdm2
Loadingbd=bd57.9bdkN⁄15.8bdm2bd=bd3.66bdkN⁄m2bd=bd𝟑.66bd𝐤𝐏𝐚
1.15 Forceb d = 𝑚bd𝑔bd=bd35bdkgbd∙bd9.81bdm/s2bd=bd343bdN
Kb d =b d Springb d Scaleb d =4800bdN⁄mbd=bd𝐹/Δ𝐿
Δ𝐿bd= 𝐹bd=bd34 =bd0.0715bdmbd=bd71.5bd×bd mbd=bd71.bd𝟓bd𝐦𝐦
3bdN 10−3

, 𝐾 4800bd N/m




𝑤b d lb∙ =bd101bd𝐬𝐥𝐮𝐠𝐬
1.16 𝑚b d =b d =3250bdl s2 bd101bd
=
b
𝑔 32.2bd(ft/s2) ft

𝑤b d 11 lb∙ =bd𝟑60bd𝐬𝐥𝐮𝐠𝐬
1.17 𝑚 bd =
bd600 bdbd
lb =b d s2 bd360bd
=
𝑔 32.2bd(ft/s2) ft

1.19 𝑝bd=bd1700bdpsibd∙bd6.895bd(kPa⁄psi)bd=bd11bd722bd𝐤𝐏𝐚
1.20 𝜎b d =bd 24bd300bdpsibd∙bd6.895bd(kPa⁄psi)bd =b d 167bd549bdkPab d =bd 𝟏68b d 𝐌𝐏𝐚

, 1.21 𝑠𝑢b d =bd 14bd000bdpsibd∙bd6.895bd(kPa⁄psi)bd =b d 96bd500bdkPab d =bd 𝟗𝟔.bd𝟓bd𝐌𝐏𝐚
𝑠𝑢b d =bd 76bd000bdpsibd∙bd6.895bd(kPa⁄psi)bd =b d 524bd000bdkPab d =b d 𝟓𝟐𝟒bd𝐌𝐏𝐚
3600bdrevb 2πbdradb d 1bdminb d 𝐫𝐚𝐝
1.22 𝑛bd=bd min
d
×bd ×bd =bd377b d
rev 60s 𝐬
2
(25.4mm) bd
1.23 𝐴bd=bd26.1bdin2bd×bdi2n =bd16bd839bd𝐦𝐦𝟐
1.24 𝑦b d =b d 0.08bdinbd∙bd25.4bd(mm⁄in)bd =b d 𝟐.bd𝟎𝟑bd𝐦𝐦
1.25 Dimensions:bd18bdinb d ×b d 25.4bd(mm/in)bd =b d 457bdmm
12bdinb d ×b d 25.4bd(mm/in)bd=bd30
5bdmmbdAreabd=bd(18bdin)2bd=bd𝟑𝟐𝟒bd𝐢𝐧𝟐
Areabd=bd(457bdmm)2b d =bd𝟐.bd𝟎𝟗bd×bd𝟏𝟎𝟓bd𝐦𝐦𝟐
bd Volumebd=bd𝑉bd=bdAreabd×bdHeight
𝑉b d =b d 324bdin2bd ×bd12bdinb d =b d 𝟑𝟖𝟖𝟖bd𝐢𝐧𝟑
𝑉b d =b d (1.5bdft)2bd ×bd1.0bdftbd =b d 𝟐.bd𝟐𝟓bd𝐟𝐭𝟑
𝑉b d =b d (209bd×bd103b d mm2)bd×bd305bdmmb d =b d 𝟔.bd𝟑𝟕bd×bd𝟏𝟎𝟕bd 𝐦𝐦𝟑
𝑉b d =b d (0.457bdm)2b d ×b d 0.305bdmb d =b d 0.0637bdm3b d =b d 𝟔.bd𝟑𝟕bd×bd𝟏𝟎−𝟐bd 𝐦𝟑
1.26 𝐴bd=bd𝜋𝐷2⁄4bd=bd𝜋(0.505bdin)2⁄4bd=bd𝟎.bd𝟐𝟎𝟎bd𝐢𝐧𝟐
(25.4bd mm)2b d
𝐴b d =b d 0.200bdin2b d ×bd =b d 𝟏𝟐𝟗bd𝐦𝐦𝟐
in2
𝑃 2800bd N N
1.27 𝜎b d =b d= = =b d 35.7 =bd35.bd𝟕bd𝐌𝐏𝐚
2800bd [𝜋(10bdmm)2]⁄ mm2
4
N
𝐴 (𝜋𝐷2bd⁄4)
𝑃b d 3b d N N
1.28 𝜎b d =b d = 18×10 =bd 50.7 =bd50.bd𝟕bd𝐌𝐏𝐚
𝐴 (12)(30)bd mm2 mm2
𝑃b d 1150bdlbb d
1.29 𝜎b d =b d =b d b d =bd7188bd𝐩𝐬𝐢
𝐴 (0.40bd in)2
𝑃b d =b d 𝟏𝟔bd𝟕𝟓𝟎bd𝐩𝐬𝐢
1.30 𝜎b d =bd = 1850bdl
b
𝐴 [𝜋(0.375bdin)2]⁄4

1.31 LoadbdonbdShelfb d =bd𝑊bd=bd𝑚𝑔bd=bd1650bdkgbd∙bd9.81bdm⁄s2bd=bd16bd187bdN
𝑊/2bd=bd8093bdNbdOnbdeachbdside
∑bd𝑀𝐴bd=bd0bd=bd(8093bdN)(600bdmm)bd−bd𝐶𝑉(1200bdmm)
𝐶𝑉bd=bd4047bdN
𝐶bd=bd𝐶𝑉/bdsinbd30°bd=bd8093bdN
𝑃b d 𝐶 bdbd 9025bdN
𝜎bd=bd =bd
𝐴b d b d =𝐴 [𝜋(12bd mm)2]⁄4b d b d =bd 71.6bd 𝐌𝐏𝐚
𝑃 70000bdlbb d b d
1.32 𝜎bd=bd =b d b d =bd891bd𝐩𝐬𝐢
𝐴 [𝜋(10bdin)2]/4