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Exam (elaborations)

SOLUTION MANUAL Finite Mathematics & Its Applications 13th Edition by Larry J. Goldstein, Chapters 1 - 12, Complete

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Contents Chapter 1: Linear Equations and Straight Lines 1–1 Chapter 2: Matrices 2–1 Chapter 3: Linear Programming, A Geometric Approach 3–1 Chapter 4: The Simplex Method 4–1 Chapter 5: Sets and Counting 5–1 Chapter 6: Probability 6–1 Chapter 7: Probability and Statistics 7–1 Chapter 8: Markov Processes 8–1 Chapter 9: The Theory of Games 9–1 Chapter 10: The Mathematics of Finance 10–1 Chapter 11: Logic 11–1 Chapter 12: Difference Equations and Mathematical Models 12–1 Exercises 1.1 Chapter 1 6. Left 1, down 5 1. Right 2, up 3 y 2 y x x 2. Left 1, up 4 y 7. Left 20, up 40 y x x 3. Down 2 y 8. Right 25, up 30 y x x 4. Right 2 y x 9. Point Q is 2 units to the left and 2 units up or (—2, 2). 10. Point P is 3 units to the right and 2 units down or (3,—2). 5. Left 2, up 1 y 11. 12. —2(1) + 1 (3) = —2 +1 = —1so yes the point is 3 on the line. —2(2) + 1 (6) = —1 is false, so no the point is not 3 on the line x 13. —2x + 1 y = —1 Substitute the x and y 3 coordinates of the point into the equation: 'f1 , 3ıh → —2'f1ıh+ 1 (3) = —1 → —1+1 = —1 is y 24. 0 = 5 no solution x-intercept: none When x = 0, y = 5 y-intercept: (0, 5) 2 J y 2J 3 14. a false statement. So no the point is not on the line. —2f'1ıh+'f1ıh(—1) = —1 is true so yes the point is 25. When y = 0, x = 7 x-intercept: (7, 0) 0 = 7 no solution 'y3ıJ 'y3ıJ on the line. 15. m = 5, b = 8 16. m = –2 and b = –6 17. y = 0x + 3; m = 0, b = 3 y-intercept: none 26. 0 = –8x x = 0 x-intercept: (0, 0) y = –8(0) y = 0 y-intercept: (0, 0) 18. y = 2 x + 0; m = 2 , b = 0 3 3 27. 0 = 1 x – 1 3 x = 3 19. 14x + 7 y = 21 7 y = —14x + 21 y = —2x + 3 x-intercept: (3, 0) y = 1 (0) – 1 3 y = –1 20. x — y = 3 —y = —x + 3 y = x — 3 y-intercept: (0, –1) y 21. 3x = 5 x = 5 3 1 2 x 28. When x = 0, y = 0. 22. – x + y = 10 2 3 2 y = 1 x +10 3 2 y = 3 x +15 4 When x = 1, y = 2. y x 23. 0 = —4x + 8 4x = 8 x = 2 x-intercept: (2, 0) y = –4(0) + 8 y = 8 y-intercept: (0, 8) 29. 0 = 5 2 no solution x-intercept: none 32. x + 0 = 3 x = 3 x-intercept: (3, 0) 0 + y = 3 When x = 0, y = 5 2 y = 3 y-intercept: (0, 3) y-intercept: f'0, 5ıh y y' 2ıJ y x x 30. The line coincides with the y-axis. y 33. 5 x =— 2 x 31. 3x + 4(0) = 24 x = 8 x-intercept: (8, 0) 3(0) + 4 y = 24 y = 6 y-intercept: (0, 6)

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Institution
Finite Mathematics & Its Applications 13th Edition
Course
Finite Mathematics & Its Applications 13th Edition











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Institution
Finite Mathematics & Its Applications 13th Edition
Course
Finite Mathematics & Its Applications 13th Edition

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Uploaded on
March 8, 2025
Number of pages
477
Written in
2024/2025
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

  • 9781292229102

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SOLUTION MANUAL
Finite Mathematics & Its Applications
13th Edition by Goldstein Chapters 1 - 12

, Contents
Chapter 1:
d Linear Equations and Straight Lines
d d d d 1–1
Chapter 2:
d Matrices 2–1

Chapter 3:
d Linear Programming, A Geometric Approach
d d d d 3–1

Chapter 4:
d The Simplex Method
d d 4–1

Chapter 5:
d Sets and Counting
d d 5–1

Chapter 6:
d Probability 6–1

Chapter 7:
d Probability and Statistics
d d 7–1

Chapter 8:
d Markov Processesd 8–1

Chapter 9:
d The Theory of Games
d d d 9–1

Chapter 10: The Mathematics of Finance
d d d d 10–1

Chapter 11: Logic
d 11–1

Chapter 12: Difference Equations and Mathematical Models
d d d d d 12–1

, Chapter 1 d



Exercisesd1.1 5
6.d Leftd1,ddownd
2
1. Rightd2,dupd3 y
y


(2,d3)
x
x
(–1, – 52)
d d
d




7.d Leftd20,dupd40
2. Leftd1,dupd4 y
y

(–20,d40)
(–1,d4)
x
x




8.d Rightd25,dupd30
3.d Downd2 y
y


(25,d30)
x
x
(0,d–2)




9. PointdQdisd2dunitsdtodthedleftdandd2dunitsdupdor
4. Rightd2
y (—2,d2).

10. PointdPdisd3dunitsdtodthedrightdandd2dunitsddowndor
(3,—2).
x
(2,d0) 1d
11. —2(1)d+d (3)d=d—2d+1d=d—1sod yesd thed pointd is
3
ondthedline.

5. Leftd2,dupd1 1d
y 12. —2(2)d+d (6)d=d—1disd false,d sod nod thed pointd isd not
3
ondthedline

(–2,d1)
x




Copyrightd©d2023dPearsondEducation,dInc. 1-1

, Chapterd1:dLineardEquationsdanddStraightdLines ISM:dFinitedMath


1d 24.d 0d=d5
13. —2xd+d yd =d—1d Substituted thed xd andd y nodsolution
3 x-
coordinatesdofdthedpointdintodthedequation: intercept:dnonedWh
f 1d ıhd f h
' ,d3 →d—2 ' 1 ı +d1d(3)d=d—1d→d—1+1d=d—1d is endxd=d0,dyd=d5dy-
y' ı 'd ı intercept:d(0,d5)
2ddd J yd2J 3
adfalsedstatement.dSodnodthedpointdisdnotdondthedline. 25.dWhendyd=d0,dxd=d7dx-
f 1 h f1h intercept:d(7,d0)d0d=
—2 ' ı + ' ı(—1)d=d—1d isdtruedsodyesdthedpointdis d7

14. nodsolution
'y3 ıJddd'y3 ıJ y-intercept:dnone
ondthedline. 26.d 0d=d–8x
15.d md=d5,dbd=d8 xd=d0
x-intercept:d(0,d0)
16.d md=d–2danddbd=d–6 yd=d–8(0)
yd=d0
17.d yd=d0xd+d3;dmd=d0,dbd=d3 y-intercept:d(0,d0)

2d 2d 1d
18. yd=d xd+d0;d md=d ,d bd=d0 27. 0d=d xd–d1
3 3 3
xd=d3
19.d 14xd+d7dyd=d21 x-intercept:d(3,d0)
1d
7dyd=d—14xd+d21 yd =d (0)d–d1
3
yd =d—2xd+d3 yd=d–1
y-intercept:d(0,d–1)
20. xd—dyd =d3 y
—yd=d—xd+d3
yd=dxd—d3
(3,d0)
21.ddd 3xd=d5 x
5 (0,d–1)
xd=d
3
1 2 28. Whendxd=d0,dyd=d0.
22. – xd+ yd =d10
2 3 Whendxd=d1,dyd=d2.
2d 1d y
yd=d xd+10
3 2
3d
yd =d xd+15 (1,d2)
4 x
(0,d0)
23. 0d=d—4xd+d8
4xd =d8
xd=d2
x-intercept:d(2,d0)
yd=d–4(0)d+d8
yd=d8
y-intercept:d(0,d8)



1-2 Copyrightd©d2023dPearsondEducation,dInc.

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