Solutions Manual for
Principles of Foundation
Engineering (SI) 10e By Braja M.
Das
(All Chapters 1-17, 100% Original
Verified, A+ Grade)
All Chapters Arranged Reverse: 17-1
This is the Original Solutions Manual
for (SI)10th Edition, All Other Files in
the Market are Wrong/Old Questions.
, Chapter 17
17.1 Eq. (17.8)
æ f¢ ö 2æ 35 ö
s a = 0.65g HK a = 0.65g H tan 2 ç 45 - ÷ = (0.65)(17)(6.5) tan ç 45 - ÷
è 2ø è 2ø
= 19.6 kN/m 2
19.46 kN/m2 19.46 kN/m2
1m 2m 2m 1.5 m
A B1 B2 C
SM B1 = 0
æ3ö
(19.46)(3) ç ÷
A= è 2 ø = 43.79 kN/m
2
B1 = (19.46)(3) - 43.79 = 14.59 kN/m
SM B2 = 0
æ 3.5 ö
(19.46)(3.5) ç ÷
è 2 ø
C= = 59.6 kN/m
2
B2 = (19.46)(3.5) - 59.6 = 8.51 kN/m
Strut load at A = (43.79)(spacing) = (43.79)(3) = 131.4 kN
Strut load at B = (B1 + B2)(spacing) = (14.59 + 8.51)(3) = 69.3 kN
Strut load at C = (59.6)(3) = 178.8 kN
151
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© 2024 Cengage Learning . All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible
website, in whole or in part.
,17.2 a. For the sheet pile, refer to shear force diagram.
24.33 kN
1m 0.75 m
A
B′ B1
1.25 m
19.46 kN 14.49 kN
1
MA = (1)(19.46) = 9.73kN × m/m
2
29.18 kN
8.51 kN
B′′ C
B2
0.437 m 1.563 m 1.5 m
30.42 kN
1
M B¢¢ = (0.437)(8.51) = 1.86 kN × m/m
2
1
M C = (1.5)(29.18) » 21.9 kN/m
2
21.9 kN × m/m
S= = 0.129×10-3 m 3 /m of wall
170 ´10 kN × m/m
3
Bs 2
b. For wales, M max = .
8
Bs 2 (69.38)(32 )
S= = = 0.459×10-3 m 3 /m
8s all (8)(170 ´10 )
3
152
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© 2024 Cengage Learning . All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible
website, in whole or in part.
, æ 40 ö
17.3 K a = ç 45 - ÷ = 0.217
è 2 ø
s a = 0.65g HK a = (0.65)(18)(6.5)(0.217) = 16.5 kN/m 2
SM B1 = 0
æ3ö
(16.5)(3) ç ÷
A= è 2 ø = 37.13 kN/m
2
16.5 kN/m2 16.5 kN/m2
1m 2m 2m 1.5 m
A B1 B2 C
B1 = (16.5)(3) - 37.13 = 12.37 kN/m
SM B2 = 0
æ 3.5 ö
(16.5)(3.5) ç ÷
C= è 2 ø = 50.53 kN/m
2
B2 = (16.5)(3.5) - 50.53 = 7.22 kN/m
Strut load at A = (37.13)(4) = 148.5 kN
Strut load at B = (12.37 + 7.22)(4) = 78.4 kN
Strut load at C = (50.53)(4) = 202.12 kN
153
®
© 2024 Cengage Learning . All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible
website, in whole or in part.
Principles of Foundation
Engineering (SI) 10e By Braja M.
Das
(All Chapters 1-17, 100% Original
Verified, A+ Grade)
All Chapters Arranged Reverse: 17-1
This is the Original Solutions Manual
for (SI)10th Edition, All Other Files in
the Market are Wrong/Old Questions.
, Chapter 17
17.1 Eq. (17.8)
æ f¢ ö 2æ 35 ö
s a = 0.65g HK a = 0.65g H tan 2 ç 45 - ÷ = (0.65)(17)(6.5) tan ç 45 - ÷
è 2ø è 2ø
= 19.6 kN/m 2
19.46 kN/m2 19.46 kN/m2
1m 2m 2m 1.5 m
A B1 B2 C
SM B1 = 0
æ3ö
(19.46)(3) ç ÷
A= è 2 ø = 43.79 kN/m
2
B1 = (19.46)(3) - 43.79 = 14.59 kN/m
SM B2 = 0
æ 3.5 ö
(19.46)(3.5) ç ÷
è 2 ø
C= = 59.6 kN/m
2
B2 = (19.46)(3.5) - 59.6 = 8.51 kN/m
Strut load at A = (43.79)(spacing) = (43.79)(3) = 131.4 kN
Strut load at B = (B1 + B2)(spacing) = (14.59 + 8.51)(3) = 69.3 kN
Strut load at C = (59.6)(3) = 178.8 kN
151
®
© 2024 Cengage Learning . All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible
website, in whole or in part.
,17.2 a. For the sheet pile, refer to shear force diagram.
24.33 kN
1m 0.75 m
A
B′ B1
1.25 m
19.46 kN 14.49 kN
1
MA = (1)(19.46) = 9.73kN × m/m
2
29.18 kN
8.51 kN
B′′ C
B2
0.437 m 1.563 m 1.5 m
30.42 kN
1
M B¢¢ = (0.437)(8.51) = 1.86 kN × m/m
2
1
M C = (1.5)(29.18) » 21.9 kN/m
2
21.9 kN × m/m
S= = 0.129×10-3 m 3 /m of wall
170 ´10 kN × m/m
3
Bs 2
b. For wales, M max = .
8
Bs 2 (69.38)(32 )
S= = = 0.459×10-3 m 3 /m
8s all (8)(170 ´10 )
3
152
®
© 2024 Cengage Learning . All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible
website, in whole or in part.
, æ 40 ö
17.3 K a = ç 45 - ÷ = 0.217
è 2 ø
s a = 0.65g HK a = (0.65)(18)(6.5)(0.217) = 16.5 kN/m 2
SM B1 = 0
æ3ö
(16.5)(3) ç ÷
A= è 2 ø = 37.13 kN/m
2
16.5 kN/m2 16.5 kN/m2
1m 2m 2m 1.5 m
A B1 B2 C
B1 = (16.5)(3) - 37.13 = 12.37 kN/m
SM B2 = 0
æ 3.5 ö
(16.5)(3.5) ç ÷
C= è 2 ø = 50.53 kN/m
2
B2 = (16.5)(3.5) - 50.53 = 7.22 kN/m
Strut load at A = (37.13)(4) = 148.5 kN
Strut load at B = (12.37 + 7.22)(4) = 78.4 kN
Strut load at C = (50.53)(4) = 202.12 kN
153
®
© 2024 Cengage Learning . All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible
website, in whole or in part.
