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Solution Manual for Data Structures and Algorithms in Java 6th edition by Michael T. Goodrich || A+ GRADED

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Solution Manual for Data Structures and Algorithms in Java 6th edition by Michael T. Goodrich || A+ Chapter 1 Java Primer Hints and Solutions Reinforcement R-1.1) Hint Use the code templates provided in the Simple Input and Output section. R-1.2) Hint You may read about cloning in Section 3.6. R-1.2) Solution Since, after the clone, A[4] and B[4] are both pointing to the same GameEntry object, B[4].score is now 550. R-1.3) Hint The modulus operator could be useful here. R-1.3) Solution public boolean isMultiple(long n, long m) { return (n%m == 0); } R-1.4) Hint Use bit operations. R-1.4) Solution public boolean isEven(int i) { return (i & 1 == 0); } R-1.5) Hint The easy solution uses a loop, but there is also a formula for this, which is discussed in Chapter 4. R-1.5) Solution public int sumToN(int n) { int total = 0; for (int j=1; j <= n; j++) total += j; return total; R-1.6) Hint The easy thing to do is to write a loop. R-1.6) Solution public int sumOdd(int n) { int total = 0; for (int j=1; j <= n; j += 2) total += j; return total; } R-1.7) Hint The easy thing to do is to write a loop. R-1.7) Solution public int sumSquares(int n) { int total = 0; for (int j=1; j <= n; j++) total += j∗j; return total; } R-1.8) Hint You might use a switch statement. R-1.8) Solution public int numVowels(String text) { int total = 0; for (int j=0; j < h( ); j++) { switch (At(j)) { case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U': total += 1; } } return total; } R-1.9) Hint Consider each character one at a time.

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Solution Manual for Data Structures and Algorithms
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Solution Manual for Data Structures and Algorithms

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Uploaded on
October 18, 2024
Number of pages
128
Written in
2024/2025
Type
Exam (elaborations)
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Solutions Manual for
Data Structures and
Algorithms in Java, 6e
Michael Goodrich,
Roberto Tamassia (All
Chapters)

, Chapter


1 Java Primer
J




Hints and Solutions
J J




Reinforcement
R-
1.1)J HintJUseJ theJ codeJ templatesJ providedJ inJ theJ SimpleJ InputJ andJOut
putJsection.
R-1.2)JHintJYouJmayJreadJaboutJcloningJinJSectionJ3.6.
R-
1.2)JSolutionJSince,JafterJtheJclone,JA[4]JandJB[4]JareJbothJpointingJtoJtheJs
ameJGameEntryJobject,JB[4].scoreJisJnowJ550.
R-1.3)JHintJTheJmodulusJoperatorJcouldJbeJusefulJhere.
R-1.3)JSolution
publicJbooleanJisMultiple(longJn,JlongJm)J{
returnJ(n%mJ==J0);
}
R-1.4)JHintJUseJbitJoperations.
R-1.4)JSolution
publicJbooleanJisEven(intJi)J{
returnJ (iJ &J 1J ==J 0);
}
R-
1.5)JHintJTheJeasyJsolutionJusesJaJloop,JbutJthereJisJalsoJaJformulaJforJthis,J
whichJisJdiscussedJinJChapterJ4.
R-1.5)JSolution
publicJintJsumToN(intJn)J{
intJ totalJ=J 0;
forJ(intJj=1;JjJ<=Jn;Jj++)JtotalJ
+=Jj;
returnJ total;
}

,2 ChapterJ1.J JavaJPrimer
R-1.6)JHintJTheJeasyJthingJtoJdoJisJtoJwriteJaJloop.
R-1.6)JSolution
publicJintJsumOdd(intJn)J{
intJ totalJ=J 0;
forJ(intJj=1;JjJ<=Jn;JjJ+=J2)Jto
talJ+=Jj;
returnJ total;
}
R-1.7)JHintJTheJeasyJthingJtoJdoJisJtoJwriteJaJloop.
R-1.7)JSolution
publicJintJsumSquares(intJn)J{
intJ totalJ=J 0;
forJ(intJj=1;JjJ<=Jn;Jj++)Jtotal
J+=Jj∗j;

returnJ total;
}
R-1.8)JHintJYouJmightJuseJaJswitchJstatement.
R-1.8)JSolution
publicJintJnumVowels(StringJtext)J{
intJ totalJ=J 0;
forJ(intJj=0;JjJ<Jtext.length();Jj++)J{
switchJ(text.charAt(j))J{
caseJ'a':
caseJ'A':
caseJ'e':
caseJ'E':
caseJ'i':
caseJ'I':
caseJ'o':
caseJ'O':
caseJ'u':
caseJ'U':Jtota
lJ+=J1;
}
}
returnJ total;
}
R-1.9)JHintJConsiderJeachJcharacterJoneJatJaJtime.

, 3
R-1.10)JHintJConsiderJusingJgetJandJsetJmethodsJforJaccessingJandJmod-
JifyingJtheJvalues.


R-
1.11)J HintJTheJtraditionalJ wayJ toJ doJ thisJ isJ toJuseJ setFooJ methods,Jwher
eJFooJisJtheJvalueJtoJbeJmodified.
R-1.11)JSolution
publicJvoidJsetLimit(intJlim)J{
limitJ=J lim;
}
R-1.12)JHintJUseJaJconditionalJstatement.
R-1.12)JSolution
publicJvoidJmakePayment(doubleJamount)J{
ifJ(amountJ>J0)Jbalance
J− =Jamount;

}
R-1.13)JHintJTryJtoJmakeJwallet[1]JgoJoverJitsJlimit.
R-1.13)JSolution

forJ(intJval=1;JvalJ<=J58;Jval++)J{Jwallet[0].
charge(3∗val);Jwallet[1].charge(2∗val);Jwa
llet[2].charge(val);
}
ThisJchangeJwillJcauseJwallet[1]JtoJattemptJtoJgoJoverJitsJlimit.


Creativity
C-1.14)JHintJTheJJavaJmethodJdoesJnotJneedJtoJbeJpassedJtheJvalueJofJn
asJanJargument.
C-1.15)JHintJNoteJthatJtheJJavaJprogramJhasJaJlotJmoreJsyntaxJrequire-
Jments.


C-
1.16)JHintJCreateJanJenumJtypeJofJallJoperators,JincludingJ=,JandJuseJanJar
rayJofJtheseJtypesJinJaJswitchJstatementJnestedJinsideJfor-
loopsJtoJtryJallJpossibilities.
C-
1.17)JHintJNoteJthatJatJleastJoneJofJtheJnumbersJinJtheJpairJmustJbeJeven.
C-1.17)JSolution

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