AAMC FL 5 C/P
*What quantity of Compound 1 need to be provided to put together a hundred.00 mL of answer
with a attention identical to Ki?
A. Forty eight.4 mg
B. 24.2 mg
C. Five.Sixty four mg
D. 2.92 mg
"Compound 1 (molar mass: 483.Five g/mol) has been shown to inhibit HIV-1 protease with Ki =
60.3 μM (Table 1). Ki is the dissociation steady for the enzyme-bound inhibitor, which is both EI
or ESI, depending on the sort of inhibitor." - ANSD
In one hundred.00 mL answer, 60.3 μM Compound 1 carries 6.03 μmol, which whilst
transformed to mol and accelerated with the aid of the molar mass, yields zero.00292 g or
2.Ninety two mg.
What functional organization transformation takes place within the manufactured from the
reaction catalyzed via Na+-NQR?
A. RC(=O)R → RCH(OH)R
B. ROPO32- → ROH + Pi
C. RC(=O)NHR'→ RCOOH + R'NH2
D. RC(=O)OR'→ RCOOH + R'OH
"The electron transport pathway in Na+-NQR consists of four flavins (FAD, FMNc, FMNb, and
riboflavin) and a [2Fe-2S] middle, with electrons flowing inside the course: NADH → FAD →
[2Fe-2S] → FMNc → FMNb → riboflavin → ubiquinone. Two electrons are transferred from
NADH to FAD within the first step of the cycle, however all subsequent steps are one-electron
transfers." - ANSA
This is -electron reduction of a ketone to an alcohol, that is the response catalyzed through
Na+-NQR.
Flavin - ANS
ubiquinone - ANScoenzymeQ
- Biologically active quinone (electron acceptor in photosynthesis and aerobic respiratory)
- Reduced to ubiquinol upon the recognition of electrons.
- Long alkyl chain = lipid soluble = act as an electron provider within the phospholipid bilayer.
What is the ratio of cation to enzyme within the spectroelectrochemical experiments defined
inside the passage?
, A. 1:2
B. 2:1
C. 20:1
D. 200:1
"...The researchers used spectroelectrochemistry to research the chemical modifications that
take location in the course of electron transfer and the way these modifications are impacted by
the presence of numerous cations. Na+-NQR become diluted to a very last concentration of
0.Seventy five mM in zero.A hundred and fifty M LiCl, NaCl, KCl, RbCl, or NH4Cl (each answer
also contained redox active mediators) and located in a pitcher tool cellular with CaF2 home
windows."
*ratio of diverse cations (zero.150 M) to Na+-NQR (zero.75mM) - ANSD
The ratio may be determined with the aid of noting that the enzyme awareness changed into
0.75 mM, whilst the concentration of cations turned into 0.150 M = one hundred fifty mM. The
ratio is consequently two hundred:1.
*devices!
Boyle's Law - ANSP1V1=P2V2; P is inversely proportional to V
Charles' Law - ANSV1/T1=V2/T2; T is immediately proportional to V for a great gas
What is the wide variety of neutrons inside the nucleus of the atom used to provide laser
radiations?
A. Forty eight
B. 49
C. 50
D. Fifty one
"Researchers achieved in situ laser-brought about fluorescence imaging and spectral analysis
of various pores and skin areas of sufferers with pimples vulgaris. They used the fluorescence
spectrometer depicted in Figure 2, which employs a 86Kr+ laser that concurrently emits
radiations of wavelengths 407 nm and 605 nm." - ANSC
The 86/36Kr atom consists of 36 electrons and 36 protons. Therefore, the number of protons is
identical to 86 - 36 = 50 neutrons.
*the question states atom (Kr), no longer the ion (Kr+) simply used in the test
pyrrole - ANSa five-membered aromatic heterocycle containing one nitrogen atom (C4H5N)
*What quantity of Compound 1 need to be provided to put together a hundred.00 mL of answer
with a attention identical to Ki?
A. Forty eight.4 mg
B. 24.2 mg
C. Five.Sixty four mg
D. 2.92 mg
"Compound 1 (molar mass: 483.Five g/mol) has been shown to inhibit HIV-1 protease with Ki =
60.3 μM (Table 1). Ki is the dissociation steady for the enzyme-bound inhibitor, which is both EI
or ESI, depending on the sort of inhibitor." - ANSD
In one hundred.00 mL answer, 60.3 μM Compound 1 carries 6.03 μmol, which whilst
transformed to mol and accelerated with the aid of the molar mass, yields zero.00292 g or
2.Ninety two mg.
What functional organization transformation takes place within the manufactured from the
reaction catalyzed via Na+-NQR?
A. RC(=O)R → RCH(OH)R
B. ROPO32- → ROH + Pi
C. RC(=O)NHR'→ RCOOH + R'NH2
D. RC(=O)OR'→ RCOOH + R'OH
"The electron transport pathway in Na+-NQR consists of four flavins (FAD, FMNc, FMNb, and
riboflavin) and a [2Fe-2S] middle, with electrons flowing inside the course: NADH → FAD →
[2Fe-2S] → FMNc → FMNb → riboflavin → ubiquinone. Two electrons are transferred from
NADH to FAD within the first step of the cycle, however all subsequent steps are one-electron
transfers." - ANSA
This is -electron reduction of a ketone to an alcohol, that is the response catalyzed through
Na+-NQR.
Flavin - ANS
ubiquinone - ANScoenzymeQ
- Biologically active quinone (electron acceptor in photosynthesis and aerobic respiratory)
- Reduced to ubiquinol upon the recognition of electrons.
- Long alkyl chain = lipid soluble = act as an electron provider within the phospholipid bilayer.
What is the ratio of cation to enzyme within the spectroelectrochemical experiments defined
inside the passage?
, A. 1:2
B. 2:1
C. 20:1
D. 200:1
"...The researchers used spectroelectrochemistry to research the chemical modifications that
take location in the course of electron transfer and the way these modifications are impacted by
the presence of numerous cations. Na+-NQR become diluted to a very last concentration of
0.Seventy five mM in zero.A hundred and fifty M LiCl, NaCl, KCl, RbCl, or NH4Cl (each answer
also contained redox active mediators) and located in a pitcher tool cellular with CaF2 home
windows."
*ratio of diverse cations (zero.150 M) to Na+-NQR (zero.75mM) - ANSD
The ratio may be determined with the aid of noting that the enzyme awareness changed into
0.75 mM, whilst the concentration of cations turned into 0.150 M = one hundred fifty mM. The
ratio is consequently two hundred:1.
*devices!
Boyle's Law - ANSP1V1=P2V2; P is inversely proportional to V
Charles' Law - ANSV1/T1=V2/T2; T is immediately proportional to V for a great gas
What is the wide variety of neutrons inside the nucleus of the atom used to provide laser
radiations?
A. Forty eight
B. 49
C. 50
D. Fifty one
"Researchers achieved in situ laser-brought about fluorescence imaging and spectral analysis
of various pores and skin areas of sufferers with pimples vulgaris. They used the fluorescence
spectrometer depicted in Figure 2, which employs a 86Kr+ laser that concurrently emits
radiations of wavelengths 407 nm and 605 nm." - ANSC
The 86/36Kr atom consists of 36 electrons and 36 protons. Therefore, the number of protons is
identical to 86 - 36 = 50 neutrons.
*the question states atom (Kr), no longer the ion (Kr+) simply used in the test
pyrrole - ANSa five-membered aromatic heterocycle containing one nitrogen atom (C4H5N)
