9/11/24, 10:06 PM Southern New Hampshire University - 1-4 Module One Problem Set
[PRINT]
MAT-142-13507-M01 Precalculus with Limits 2024 C-5 (Sep - Oct) : MAT-142 : 1703404, 1-4 Module One Problem Set
Robert Rodriguez, 9/8/24 at 3:29:33 AM EDT
Question1: Score 2/2
Solve the compound inequality: 4 ≤ 2 x − 8 < 14 .
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
[6,11) [6, 11)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
Write two separate inequalities: 4 ≤ 2 x − 8 and 2 x − 8 < 14. We solve them independently.
4 ≤2x−8 and 2x − 8 < 14
12 ≤ 2 x 2x < 22
6 ≤x x < 11
Therefore, the solution set is 6 ≤ x < 11, or in interval notation, [6, 11).
Question2: Score 8/8
Solve the inequality involving absolute value.
|x − 3| + 4 ≥ 13
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-infinity,-6]U[12,infinity) (-infinity, -6] U [12, infinity)
Auto graded Grade: 25/25.0
Show your work and explain, in your own words, how you arrived at your answers.
|x-3|+4>=13
|x-3|>=9
+3 +3
X>=12
[12,infinity)
|x-3|<=-9
+3 +3
x<= -6
(-infinity,-6)
Ungraded Grade: 0/100.0
Total grade: 1.0×25/125 + 0.0×100/125 = 20% + 0%
Feedback:
|x − 3| + 4 ≥ 13
|x − 3| ≥ 9
https://snhu-mat142.mobius.cloud/modules/gradeProctoredTest.Login 1/14
, 9/11/24, 10:06 PM Southern New Hampshire University - 1-4 Module One Problem Set
x − 3 ≤ −9 x−3 ≥9
x ≤ −6 x ≥ 12
Express the inequality in interval notation.
(−∞, −6] ∪ [12, ∞)
Comments:
Question3: Score 2/2
Solve the inequality involving absolute value.
∣ x−3 ∣ < 3
∣ 5 ∣
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-12,18) (-12, 18)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
∣ x−3 ∣ < 3
∣ 5 ∣
−3 < x−3 < 3
5
−15 < x − 3 < 15
−12 < x < 18
Express the inequality in interval notation.
(−12, 18)
Question4: Score 2/2
Describe all the x -values at a distance of 16 or less from the number 5.
Enter your answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
[-11,21] [-11, 21]
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
We want the distance between x and 5 to be less than or equal to 16 . We can draw a number line, such as in the figure below, to represent the condition to be
satisfied.
16 16
https://snhu-mat142.mobius.cloud/modules/gradeProctoredTest.Login 2/14
[PRINT]
MAT-142-13507-M01 Precalculus with Limits 2024 C-5 (Sep - Oct) : MAT-142 : 1703404, 1-4 Module One Problem Set
Robert Rodriguez, 9/8/24 at 3:29:33 AM EDT
Question1: Score 2/2
Solve the compound inequality: 4 ≤ 2 x − 8 < 14 .
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
[6,11) [6, 11)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
Write two separate inequalities: 4 ≤ 2 x − 8 and 2 x − 8 < 14. We solve them independently.
4 ≤2x−8 and 2x − 8 < 14
12 ≤ 2 x 2x < 22
6 ≤x x < 11
Therefore, the solution set is 6 ≤ x < 11, or in interval notation, [6, 11).
Question2: Score 8/8
Solve the inequality involving absolute value.
|x − 3| + 4 ≥ 13
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-infinity,-6]U[12,infinity) (-infinity, -6] U [12, infinity)
Auto graded Grade: 25/25.0
Show your work and explain, in your own words, how you arrived at your answers.
|x-3|+4>=13
|x-3|>=9
+3 +3
X>=12
[12,infinity)
|x-3|<=-9
+3 +3
x<= -6
(-infinity,-6)
Ungraded Grade: 0/100.0
Total grade: 1.0×25/125 + 0.0×100/125 = 20% + 0%
Feedback:
|x − 3| + 4 ≥ 13
|x − 3| ≥ 9
https://snhu-mat142.mobius.cloud/modules/gradeProctoredTest.Login 1/14
, 9/11/24, 10:06 PM Southern New Hampshire University - 1-4 Module One Problem Set
x − 3 ≤ −9 x−3 ≥9
x ≤ −6 x ≥ 12
Express the inequality in interval notation.
(−∞, −6] ∪ [12, ∞)
Comments:
Question3: Score 2/2
Solve the inequality involving absolute value.
∣ x−3 ∣ < 3
∣ 5 ∣
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
(-12,18) (-12, 18)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
∣ x−3 ∣ < 3
∣ 5 ∣
−3 < x−3 < 3
5
−15 < x − 3 < 15
−12 < x < 18
Express the inequality in interval notation.
(−12, 18)
Question4: Score 2/2
Describe all the x -values at a distance of 16 or less from the number 5.
Enter your answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U.
Your response Correct response
[-11,21] [-11, 21]
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
We want the distance between x and 5 to be less than or equal to 16 . We can draw a number line, such as in the figure below, to represent the condition to be
satisfied.
16 16
https://snhu-mat142.mobius.cloud/modules/gradeProctoredTest.Login 2/14
