MARK SCHEME – GCSE MATHEMATICS – 8300/1H – JUNE 2019

MARK SCHEME – GCSE MATHEMATICS – 8300/1H – JUNE 2019 5 Question Answer Mark Comments 1 9 B1 2 9 7 2 B1 3 6π B1 4 8 37 B1 5(a) 9.7 × 10–4 B1 Additional Guidance Condone 9.7 . 10–4 or 9.7 · 10–4 B1 Ignore zeroes before the ‘9’ eg 00009.7 × 10–4 B1 9.7 × 104– B0 MARK SCHEME – GCSE MATHEMATICS – 8300/1H – JUNE 2019 6 Question Answer Mark Comments 5(b) 300 000 and 4000 or (105 ÷ 103 =) 102 or (105 ÷ 103 =) 100 or 7.5 × 10(1) or 75 × 100 or 4 3 102  or 4 300 M1 75 A1 Additional Guidance If the answer is given in standard form and as 75 the student must indicate that 75 is their chosen answer or it must be the final answer given eg1 7.5 × 10(1) = 75 on the answer line eg2 75 = 7.5 × 10(1) on the answer line M1A1 M1A0 4 300 or 75 from incorrect working scores zero eg1 3 × 105 = 30000 and 4 × 103 = 400 and 30000 ÷ 400 = 4 300 = 75 eg2 400 30000 = 75 M0A0 M0A0 For the method mark, ignore incorrect work from a correct expression eg 0.75 × 102 = 7.5 × 103 M1A0 If the student attempts two methods (simplifying the powers and attempting to convert to ordinary numbers) mark both methods and award the higher mark MARK SCHEME – GCSE MATHEMATICS – 8300/1H – JUNE 2019 7 Question Answer Mark Comments 6(a) 6 1 on ‘1’ and 3 1 or 6 2 on ‘2 or 3’ and 2 1 on each of ‘Odd’ and ‘Even’ B2 oe fraction, decimal or percentage B1 6 1 on ‘1’ and 3 1 or 6 2 on ‘2 or 3’ or 2 1 on each of ‘Odd’ and ‘Even’ or all correct unsimplified probabilities with one or more simplification errors eg 6 3 on ‘Odd’ simplified to 3 1 Additional Guidance Accept decimals or percentages rounded or truncated correctly to at least 2 significant figures Only withhold a mark for simplification errors if B2 would otherwise be awarded Ignore extra branches added Ignore attempts to work out combined probabilities to the right of the tree diagram If an answer line is blank, the student may have written their answer elsewhere on the branch MARK SCHEME – GCSE MATHEMATICS – 8300/1H – JUNE 2019 8 Question Answer Mark Comments 6(b) Alternative method 1: P(1) + P(4, 5 or 6) × P(Odd) 2 1 × their 2 1 or 4 1 M1 oe their 4 1 + their 6 1 M1dep oe (P(win) =) 24 10 or 12 5 A1ft oe ft their tree diagram Lose (and P(Lose) = 24 14 or 12 7 oe) A1ft ft correct decision for their 12 5 (and their 12 7 ) with M2 scored Alternative method 2: 1 – P(2 or 3) – P(4, 5 or 6) × P(Even) 2 1 × their 2 1 or 4 1 M1 oe their 4 1 + their 3 1 or P(lose) = 12 7 M1dep oe ft their tree diagram (P(win) =) 24 10 or 12 5 A1ft oe ft their tree diagram Lose (and P(Lose) = 24 14 or 12 7 oe) A1ft ft correct decision for their 12 5 (and their 12 7 ) with M2 scored Additional Guidance is on the following pag