2θ/2 +2 (rCos α)/2 (Y -D0/2) = ( )( )α θ rCos DY D 2/ 8/02
0 − + Y = D 0/2 + (D0/2) Sin α A = D o2 θ /8 + D o Sin α C os α Bo Y S Y 1 Bo Bo Chapter 1 2 (v) Standard horseshoe section: Length KB ( ) )3(258186.0)2()1( 58186.0
2218787811
2222
2
0 2
0____
22____ ____ ____
2_____
2_____
2____
22____
02
0_____
2_____
2_____0 0____0_____02
0 2
02_____2_____ _____0__________ _____ _____
−−−−−−−−
− − =
− − = − =−−−−−−
− − = − =−−−−−−− =
− ==
− =
− =
−
==− =
KBdd KCKB OB OC OK FC KCKBd d KF FC KCd d OCd MCddd GM CG MCd OMOM MC OM ( )
( )
)
2Sin sin -1(8D
BA D 2sin D)2 2 ( cosr 2 cosr 2 B )sin 1(4θDrθ P2πθ0 θsinθ8DA2αsin ) (2α sin θsin and π 2α θ But 2αsinθ8Dcosα sinα4D 8θDA
ooo2
o2
o2
o2
o
θθ θθ π θαθθπ
− = == − = =− = =≤≤ − =−= + =+ =+ = + = θ θ Y D0 B Chapter 1 3 ( )
0 00 02
02
0 02
0_____
20 00____
0____2____ ____
02
0 2
0____
2____
02
02
02____
0 2
02_____
02
0
59.48 295.2424114377.02822875.0 04114377169281.0 088562.0411438.0 088562.02088562.0438856.0 2233856.0 )3( )2(
= = == == − − == − = =
− + − = − + −
− − =
− −
LL LSind CC d KCd d d d KCd ddOK d KBKB KBddd KB KBd d dKBdd KB d d and
θθ θ The standard horse sho e section is divided into three sectio ns, i.e., upper section, middle section and lower section. (a) Upper section π ≤ θ
u ≤ 2 π Flow area, A = ( )8 82
02
0 DSinD
u uπθ θ − − Wetted perimeter, P = 20θD Hydraulic radius, R = A/P =
−θθSin D140 Top water surface, B = D 0 Sin (θ/2) Hydraulic depth, D = A/B =
−
)2/( 80
θθ θ
SinSin D (b) Lower section 0 ≤ θ
L ≤ 48.590 Flow area, A = ( ) ( )θ θ θ θ SindSinD
L L − = −2 82
02
0 Wetted perimeter, P = 00
2dDθθ=