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CHEM 103 Module 3 Exam Questions with Answers | Portage Learning 2023/2024

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Show the calculation of the amount of heat involved if 35.6 g of H2S is reacted with excess O2 to yield sulfur dioxide and water by the following reaction equation. Report your answer to 4 significant figures. 2 H2S (g) + 3 O2 (g) → 2 SO2 (g) + 2 H2O (g) ΔH = - 1124 kJ Your Answer: 1) 1 mol H2S = 34.1 g of H2S = 603.2 KJ (35.6 g / 34.1 g) * -603.2 KJ = (1.0439) * (-603.2 KJ) = -629.7 2H2S (g) + 3 O2 (g) -- 2 SO2 (g) + 2 H2O (g) H = -1124 KJ reaction uses 35.6 g of H2S = 35.6 / 34.086 = 1.044 mole of H2S q = H * new moles / original moles q = -1124 KJ * 1.044 moles of H2S / 2 mole H2S = 586.7 given off 2 H2S (g) + 3 O

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CHEM 103 Module 3 Exam Portage Learning 2023 M3: Exam - Requires Respondus LockDown Browser + Webcam
Due No due date Points 100 Questions 10 Time Limit 120 Minutes Requires Respondus LockDown Browser
Instructions
Please read the following before beginning the exam:
You must show your work for calculations or give an explanation for short answer questions in order to receive credit.
You may only use the methods and explanations provided by this course for your answers. The use of a method or explanation that was not taught in this course is a violation of the Academic Integrity Policy. You MUST only use the Periodic Table provided within the exam.
You MUST only use the equation bank that is provided within the exam.

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