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QMI1500 EXAM PACK ANSWERS ()

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QMI1500 EXAM PACK ANSWERS () QUESTION 01

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QMI1500
EXAM PACK
ANSWERS
(2014 - 2021)

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QMI1500 OCT/NOV 2019
QUESTION 01

𝑎5 𝑏𝑐 3
𝑎2 𝑏3 𝑐 2
3 1 2
Since a = 2 , b = 2, c = 3

3 1 2
( )5 ( )( )3
= 3
2
1
2
2
3
=9
( ) 2 ( ) 3 ( )2
2 2 3


OPTION [1]



QUESTION 02
4−5𝑥 13 1−3𝑥
6
− 45
= 4
multiply everything by the highest denominator

4 − 5𝑥 13 1 − 3𝑥
45( ) − 45( ) = 45( )
6 45 4
1 1
72 (4 − 5𝑥) – 13 = 114(1 – 3x) get rid of the brackets

1 1 3
30 - 372 𝑥 – 13 = 114 - 334x collect like terms

1 3 1
30 – 13 - 114 = - 334x + 372 𝑥

3 3 3
54 = 34 𝑥 divide both sides by 34

8
115 = x

OPTION [4]




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QUESTION 3

Pule Lerato
Wind chimes(x) 4 2
Birdhouses(y) 3 4
More than 38 Less than 48
≤≥

4x + 3y ≥ 38

2x + 4y ≤ 48

OPTION [4]



QUESTION 4

COMBINATION

OPTION [1]



QUESTION 5

PERMUTATION

8 actors for 3 roles

Main role options x second role options x third role options

= 8 x 7 x 6 = 336

OR

Px = 8P3 = 336
n



OPTION [1]




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QUESTION 6

Scale 1:250

Dimensions 10mm by 20mm change the dimensions to meters

0.01m by 0.02m take into account the scale | multiply dimensions by 250

2.5m by 5m

Area of a rectangle = L x W = 2.5 x 5 = 12.5

OPTION [3]



QUESTION 7

JUST USE YOU CALCULATOR
1 2 3 1
5 2 - 13 – 14 = 212

OPTION [1]



QUESTION 8

Start by identifying what changes and what does not in the expression
2
𝑥𝑐ℎ𝑎𝑛𝑔𝑖𝑛𝑔 f(𝑥𝑐ℎ𝑎𝑛𝑔𝑖𝑛𝑔 ) replace changing with I to represent the different x values

𝑥𝑖2 f(𝑥𝑖 )

Since there is summation

∑ 𝑥𝑖2 𝑓(𝑥𝑖 )

First x = 1, Last x = 5, therefore,
5

∑ 𝑥𝑖2 𝑓(𝑥𝑖 )
𝑖=1

OPTION [1]




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Josef de Beer Becoming a teacher
Publisher: 2020 ISBN: 9781928523352 Edition: Unknown

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