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Optimisation
Demand: y = 800 - 5x
Maximise z = (x - 40)y --> objective
Subject to y + 5x = 800 --> constraint


Demand model
Inputs
Max deman 800
Slope -5
Unit cost R 40


Decision
Price R100
Demand 300

Constraint Y+5X
Demand R800 <= 800

Outcome
Profit R18,000

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