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CHEM 103 Module 1 | Practice Q&A | 2026/2027 | Chemistry | Portage Learning | 100% PASS

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This document helps you master the CHEM 103 General Chemistry I with Lab Module 1 exam at Portage Learning via targeted Q&A with detailed rationales. It covers measurement and significant figures, dimensional analysis and unit conversions (metric and English systems), density calculations, temperature scale conversions (Celsius, Fahrenheit, Kelvin), atomic structure (protons, neutrons, electrons), isotopes and atomic mass, and periodic table organization with chemical symbols. Engineered to maximize retention and sharpen critical understanding, this test pack simplifies complex content, saving preparation time and helping you secure an A on your Module 1 Exam Assessment.

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,CHEM 103 Module 1 | Practice Q&A | 2026/2027 | Chemistry |
Portage Learning | 100% PASS

1. Which of the following is defined as anything that has mass and takes up
space?

A) Energy

B) Matter

C) Vacuum

D) Force



Correct Answer: Matter



Rationale: Matter is the physical substance of the universe that possesses
mass and occupies a physical volume, distinguishing it from forms of energy
such as light or heat. A vacuum contains no matter, and force is not a
substance.



2. Convert 845.3 to exponential (scientific notation) form.

A) 84.53 × 10¹

B) 8.453 × 10²

C) 0.8453 × 10³

D) 8453 × 10⁻¹



Correct Answer: 8.453 × 10²



Rationale: To convert to scientific notation, move the decimal point so there
is one non-zero digit to the left of the decimal. 845.3 → 8.453. The decimal
was moved 2 places to the left, so the exponent is +2.



3. Convert 0.0000726 to scientific notation.

,A) 7.26 × 10⁻⁵

B) 7.26 × 10⁵

C) 72.6 × 10⁻⁶

D) 0.726 × 10⁻⁴



Correct Answer: 7.26 × 10⁻⁵



Rationale: Move the decimal point 5 places to the right to get 7.26. Because
the original number is less than 1, the exponent must be negative, resulting
in 7.26 × 10⁻⁵.



4. Convert 3.21 × 10⁻⁵ to ordinary form.

A) 0.0000321

B) 0.000321

C) 321000

D) 0.00000321



Correct Answer: 0.0000321



Rationale: A negative exponent means the number is smaller than 1. Move
the decimal 5 places to the left: 3.21 × 10⁻⁵ = 0.0000321.



5. How many significant figures are in the number 0.01354?

A) 3

B) 4

C) 5

D) 6

, Correct Answer: 5



Rationale: All non-zero digits are significant. Zeros to the left of a decimal or
preceding other non-zero numbers are not significant. 0.01354 has 5
significant figures (1, 3, 5, 4 are all significant; leading zeros are not).



6. How many significant figures are in the number 1300?

A) 1

B) 2

C) 3

D) 4



Correct Answer: 2



Rationale: Without a decimal point, trailing zeros are not significant. 1300
has 2 significant figures (1 and 3). If written as 1300., it would have 4
significant figures.



7. How many significant figures are in the number 520.3?

A) 2

B) 3

C) 4

D) 5



Correct Answer: 4

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