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RAPHEX THERAPY EXAM || MOST RECENT EXAM 2026| 2027 ACTUAL COMPLETE REAL VERIFIED EXAM QUESTIONS AND CORRECTLY WELL-DEFINED ANSWERS (VEERIFIED ANSWERS) ALREADY GRADED A+ | GUARANTEED SUCCESS!! NEWEST EXAM!!!

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RAPHEX THERAPY EXAM || MOST RECENT EXAM 2026| 2027 ACTUAL COMPLETE REAL VERIFIED EXAM QUESTIONS AND CORRECTLY WELL-DEFINED ANSWERS (VEERIFIED ANSWERS) ALREADY GRADED A+ | GUARANTEED SUCCESS!! NEWEST EXAM!!!

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1|Page


RAPHEX THERAPY EXAM || MOST RECENT EXAM
2026| 2027 ACTUAL COMPLETE REAL VERIFIED
EXAM QUESTIONS AND CORRECTLY WELL-DEFINED
ANSWERS (VEERIFIED ANSWERS) ALREADY
GRADED A+ | GUARANTEED SUCCESS!! NEWEST
EXAM!!!


In order to be stable, elements with high atomic numbers
(Z > 20) must have more neutrons than protons in the
nucleus because:
A. the nuclear attractive force can only overcome coulomb
repulsion between protons if there is an excess of
neutrons
B. neutron-proton coulomb attraction helps stabilize the
nucleus
C. gravitational attraction between neutrons and protons
stabilized the nucleus
D. the magnetic moments of neutrons and protons act as
an attractive force
E. without an excess of neutrons, high-atomic-number
elements would all undergo beta minus decay - Answer-A.
the nuclear attractive force can only overcome coulomb
repulsion between protons if there is an excess of
neutrons. The strong nuclear force between neutrons and

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protons, neutrons and neutrons, protons and protons
overcomes the coulomb repulsive force between protons.


An isotope that decreases in activity by 5% per day has an
approximate half-life of
A. 1.5d
B. 5 d
C. 10 d
D. 13.5 d
E. 20 d - Answer-D. 13.5 d. A(t) = Ao * e ^2t , where 2 =
In(2)/t1/2. Therefore, at t=1 day, A(t)=A(1 day) = 0.95Ao,
and In(0.95A0 Ao) = -In(2) /41/2 x 1 day, so 0.0513 =
0.693/1/2 Or t1/2 = 13.5 days


103 (46) Pd decays to 103 (45) Rh. What is the primary
mode of decay?
A. alpha decay
B. beta minus decay
C. electron capture
D. gamma emission
E. photonuclear disintegration - Answer-C. electron
capture.

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The advantage of using a bowtie filter in CT imaging is
A. it absorbs low-energy x-rays
B. reduced scatter-to-primary ratio
C. reduced dose to the periphery of the patient
D. All of the above are true.
E. None of the above is true. - Answer-D. All of the above
are true.


What characteristic x-ray energies are possible for
molybdenum, given energy levels for its K, L, and M shells
of 20 keV, 2.5 keV, and 0.5 keV, respectively?
A. Continuous spectrum from 0.5 keV to 20 keV
B. Continuous spectrum from 2 keV to 19.5 keV
C. 20 keV, 2.5 keV, 0.5 keV
D. 19.5 keV, 17.5 keV, 2 keV
E. 22.5 keV, 20.5 keV, 3 keV - Answer-D. 19.5 keV, 17.5
keV, 2 keV. Characteristic x-rays are emitted with discrete
energies equal to the difference in energy levels between
each orbital electron shell.

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After the replacement of the ionization chamber in a linac,
which machine parameters are expected
to change the most?
A. flatness
B. symmetry
C. output
D. beam profile
E. energy - Answer-C. output. The output can change
significantly after the replacement of an ion chamber due
to differences
in the amount of gas between the old and new chambers.
Therefore, machine output will need to be
adjusted/recalibrated after the chamber replacement. The
flatness and the symmetry are function of the beam
steering, and the beam energy is determined by the
accelerating potential and the target.
A beam of electrons is traveling in a straight line. If an
external magnetic field is introduced perpendicular to the
direction of the travel of the electrons, the electrons will:
_________.
A. speed up
B. slow down

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August 3, 2026
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