OPERATOR GRADE V COMPLETE QUESTIONS
AND DETAILED SOLUTIONS LATEST
UPDATE
DOMAIN 1: ADVANCED ACTIVATED SLUDGE PROCESS CONTROL
1. In an activated sludge system, the primary purpose of returning activated
sludge (RAS) is to:
A) Increase oxygen transfer
B) Maintain microorganisms in the aeration tank
C) Remove nutrients from the effluent
D) Increase chlorine demand
Answer: B. Returning activated sludge keeps a high concentration of
microorganisms in the aeration tank so they can continue breaking down
organic waste.
2. Which of the following is the primary purpose of activated sludge in
wastewater treatment?
A) To filter out solids
B) To biologically remove organic matter
C) To disinfect the effluent
D) To increase pH
,Answer: B. Activated sludge uses microorganisms to consume and break
down organic pollutants, reducing BOD and improving water quality.
3. Which factor most significantly affects the growth rate of microorganisms in
an aeration tank?
A) Temperature
B) pH
C) Dissolved oxygen
D) All of the above
Answer: D. Microbial growth depends on temperature, pH, dissolved oxygen,
and nutrient availability; all these factors must be optimized for effective
treatment.
4. A superintendent notices a consistent increase in effluent turbidity and a
rising sludge volume index (SVI). Which operational adjustment is most
appropriate as a first corrective action?
A) Increase chlorine dosage in the final effluent
B) Reduce RAS rate to decrease sludge age
C) Adjust wasting rate to reduce solids retention time imbalance
D) Shut down aeration tanks for cleaning
Answer: C. A rising SVI combined with poor effluent clarity often indicates
sludge bulking or poor settleability linked to an imbalanced solids retention
time. Adjusting the wasting rate helps restore proper biomass concentration
and process stability.
,5. Which of the following is a potential cause of bulking in an activated sludge
system?
A) Low BOD
B) Filamentous bacteria overgrowth
C) High chlorine residual
D) Excess phosphorus
Answer: B. Filamentous bacteria overgrowth interferes with sludge settling,
leading to bulking conditions in the activated sludge system.
6. At a Grade V facility, which of the following is the MOST CRITICAL factor in
determining the wasting rate for activated sludge when the plant is
approaching its permitted solids loading capacity?
A) Dissolved oxygen concentration in the aeration basin
B) Food to Microorganism (F:M) ratio
C) Mixed Liquor Suspended Solids (MLSS) concentration in the aeration basin
D) Effluent biochemical oxygen demand (BOD)
Answer: B. The F:M ratio is the most critical control parameter for
determining wasting rates when approaching solids loading capacity, as it
directly influences biological activity and sludge production.
7. In an activated sludge system, a decreasing sludge volume index (SVI) over
several days typically indicates:
A) Sludge bulking is developing
B) The sludge is settling more rapidly
C) Nitrification is inhibited
, D) The F:M ratio is too high
Answer: B. A decreasing SVI indicates improved sludge settleability—the
sludge is settling more rapidly and compacting better.
8. The typical solids retention time (SRT) range for a conventional activated
sludge system designed for carbonaceous BOD removal only is:
A) 1–3 days
B) 5–15 days
C) 20–30 days
D) 35–50 days
Answer: B. Conventional activated sludge systems designed primarily for
carbonaceous BOD removal typically operate with an SRT of 5 to 15 days.
9. An operator observes pin floc in the clarifier effluent. This condition is most
likely caused by:
A) Excessive aeration
B) Insufficient aeration
C) High F:M ratio
D) Low waste activated sludge (WAS) rates
Answer: A. Pin floc (very small, light floc particles) is often caused by
excessive aeration or over-oxidation, which shears the floc and prevents good
settling.