PORTAGE LEARNING CHEMISTRY 103 MODULE 1 EXAM STUDY GUIDE QUESTION… EXAM
P R O F E S S I O N A L P R A C T I C E M AT E R I A L S
Portage Learning Chemistry
103 Module 1 Exam Study
Guide Questions & Answers
2026-2027 (Rationales)
Verified Answers Exam Ready With Rationales
169 QUESTIONS
DOCUMENT OVERVIEW
This document contains 169 verified questions with correct answers and detailed rationales focused on
foundational chemistry concepts. It serves as a comprehensive resource for students to study and reinforce
their understanding of chemistry principles. This study guide is ideal for exam preparation, course review,
and certification readiness.
CONTENTS
01 • Exponential Numbers 02 • Metric System 03
• Temperature Conversions
04 • Density 05 • Significant Figures 06 • Elements
07 • Mixtures and Solutions 08 09 • Thermochemistry
Page 1
, • Physical and Chemical Changes
10 • Atomic Structure 11 • Chemical Names 12 • Molecular Compounds
13 • Non-binary Compounds 14 • Acids and Formulas
E XA M Q U EST I O N S
Q1 QUESTION 1 OF 169
1 EXPONENTIAL NUMBERS
CORRECT ANSWER
The speed of light is 186,000 miles per second. This is 1.86 x 105 (in exponential form)
The diameter of an E. coli cell is 0.00000080 meters = 8.0 x 10-7 (in exponential form)
4950000000. A number larger than one will have a positive exponent. Move the decimal point nine places to
the left to give 4.95 x 109
0.00000000000056 A number smaller than one will have a negative exponent. Move the decimal point 13
places to the right to give 5.6 x 10-13
1.) 0.00000456 = smaller than 1 = negative exponent, move decimal 6 places = 4.56 x 10-6
2.) 2.63 x 107 = positive exponent = larger than 1, move decimal 7 places = 26300000.
3.) 7800000. = larger than 1 = positive exponent, move decimal 6 places = 7.8 x 106
4.) 8.26 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0.0000826
5.) 5.38 x 10-3 = negative exponent = smaller than 1, move decimal 3 places = 0.00538
6.) 0.000673 = smaller than 1 = negative exponent, move decimal 4 places = 6.73 x 10-4
7.) 3.82 x 104 = positive exponent = larger than 1, move decimal 4 places = 38200.
8.) 623000000. = larger than 1 = positive exponent, move decimal 8 places = 6.23 X 108
RATIONALE
Exponential notation effectively communicates large or small quantities by representing them as a product of a
coefficient and a power of ten, where a positive exponent indicates a number greater than one and a negative
exponent denotes a number less than one. This understanding is crucial for accurately converting standard form to
scientific notation and vice versa, reinforcing the concept of magnitude in numerical representation.
Q2 QUESTION 2 OF 169
) V = M/D = 1000 g / 13.6 g/ml =
CORRECT ANSWER
73.5 ml (division, density contains only 3 sig figs)
Page 2
, RATIONALE
5 ml, adhering to significant figure rules by limiting the answer to three significant figures. This principle ensures that
the precision of the measurement is maintained throughout the calculation.
Q3 QUESTION 3 OF 169
2: METRIC SYSTEM - UNIT CONVERSIONS
CORRECT ANSWER
1 foot (ft)=12 inches (in)
1 kilogram (kg)=1000 grams (g)
1 pound (lb)=16 ounces (oz)
1 gallon (gal)=4 quarts (qt)
1000 milliliters (ml)=1 liter (L)
100 centigrams (cg)=1 gram (g)
10 decimeters (dm)=1 meter (m)
RATIONALE
Understanding metric and imperial unit conversions is fundamental for precise measurement in scientific and
everyday contexts, ensuring accuracy in calculations and communication. Mastery of these conversions, such as
knowing that 1 kilogram equals 1000 grams, facilitates effective data interpretation and application across various
disciplines.
Q4 QUESTION 4 OF 169
The prefixes kilo (= 1000), milli (= 1/1000), centi (= 1/100), and deci (= 1/10)
CORRECT ANSWER
are used with any metric unit, such as grams (weight), liters (volume), and meters (distance).
RATIONALE
Metric prefixes like kilo, milli, centi, and deci denote specific powers of ten, allowing for standardized communication
of measurements across various units such as grams, liters, and meters. This system enhances precision and clarity in
scientific and mathematical contexts.
Q5 QUESTION 5 OF 169
Page 3
, The original quantity and unit (to be converted) are multiplied by a conversion factor (which is a fraction made
up as follows):
New unit (on top) / Old unit (on bottom)
CORRECT ANSWER
48 ounces = ? pounds
48 o z × 1 p o u n d / 16 o z = 3 p o u n d s
4 kilograms = ? grams
4 Kg X 1000 grams/1kg = 4000 grams
1.) 656 cm x 1 m / 100 cm = 6.56 m
2.) 20 gal x 4 qt / 1 gal = 80 qts
3.) 7820 ml x 1 liter / 1000 ml = 7.82 liters
4.) 36 g x 1000 mg / 1 g = 36000 mg
5.) 25.3 g x 10 dc / 1 g = 253 dg
6.) 6.2 m x 1000 mm / 1 m = 6200 mm
7.) 725 l x 1000 ml / 1 liter = 725,000 ml
8.) 56 ft x 12 in / 1 ft = 672 in
RATIONALE
Multiplying by a conversion factor, which is structured as a fraction with the desired unit in the numerator and the
original unit in the denominator, allows for the systematic cancellation of units, ensuring accurate conversion to the
new measurement. This principle illustrates dimensional analysis, a fundamental concept in ensuring that calculations
maintain consistency across different units of measure.
Q6 QUESTION 6 OF 169
) D = M/V = 155 g / 50 ml =
CORRECT ANSWER
3.1 g/ml (division, volume contains only 2 sig figs)
RATIONALE
1 g/ml. This illustrates the importance of significant figures in scientific calculations to ensure accuracy and reliability
of results.
Q7 QUESTION 7 OF 169
Page 4
P R O F E S S I O N A L P R A C T I C E M AT E R I A L S
Portage Learning Chemistry
103 Module 1 Exam Study
Guide Questions & Answers
2026-2027 (Rationales)
Verified Answers Exam Ready With Rationales
169 QUESTIONS
DOCUMENT OVERVIEW
This document contains 169 verified questions with correct answers and detailed rationales focused on
foundational chemistry concepts. It serves as a comprehensive resource for students to study and reinforce
their understanding of chemistry principles. This study guide is ideal for exam preparation, course review,
and certification readiness.
CONTENTS
01 • Exponential Numbers 02 • Metric System 03
• Temperature Conversions
04 • Density 05 • Significant Figures 06 • Elements
07 • Mixtures and Solutions 08 09 • Thermochemistry
Page 1
, • Physical and Chemical Changes
10 • Atomic Structure 11 • Chemical Names 12 • Molecular Compounds
13 • Non-binary Compounds 14 • Acids and Formulas
E XA M Q U EST I O N S
Q1 QUESTION 1 OF 169
1 EXPONENTIAL NUMBERS
CORRECT ANSWER
The speed of light is 186,000 miles per second. This is 1.86 x 105 (in exponential form)
The diameter of an E. coli cell is 0.00000080 meters = 8.0 x 10-7 (in exponential form)
4950000000. A number larger than one will have a positive exponent. Move the decimal point nine places to
the left to give 4.95 x 109
0.00000000000056 A number smaller than one will have a negative exponent. Move the decimal point 13
places to the right to give 5.6 x 10-13
1.) 0.00000456 = smaller than 1 = negative exponent, move decimal 6 places = 4.56 x 10-6
2.) 2.63 x 107 = positive exponent = larger than 1, move decimal 7 places = 26300000.
3.) 7800000. = larger than 1 = positive exponent, move decimal 6 places = 7.8 x 106
4.) 8.26 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0.0000826
5.) 5.38 x 10-3 = negative exponent = smaller than 1, move decimal 3 places = 0.00538
6.) 0.000673 = smaller than 1 = negative exponent, move decimal 4 places = 6.73 x 10-4
7.) 3.82 x 104 = positive exponent = larger than 1, move decimal 4 places = 38200.
8.) 623000000. = larger than 1 = positive exponent, move decimal 8 places = 6.23 X 108
RATIONALE
Exponential notation effectively communicates large or small quantities by representing them as a product of a
coefficient and a power of ten, where a positive exponent indicates a number greater than one and a negative
exponent denotes a number less than one. This understanding is crucial for accurately converting standard form to
scientific notation and vice versa, reinforcing the concept of magnitude in numerical representation.
Q2 QUESTION 2 OF 169
) V = M/D = 1000 g / 13.6 g/ml =
CORRECT ANSWER
73.5 ml (division, density contains only 3 sig figs)
Page 2
, RATIONALE
5 ml, adhering to significant figure rules by limiting the answer to three significant figures. This principle ensures that
the precision of the measurement is maintained throughout the calculation.
Q3 QUESTION 3 OF 169
2: METRIC SYSTEM - UNIT CONVERSIONS
CORRECT ANSWER
1 foot (ft)=12 inches (in)
1 kilogram (kg)=1000 grams (g)
1 pound (lb)=16 ounces (oz)
1 gallon (gal)=4 quarts (qt)
1000 milliliters (ml)=1 liter (L)
100 centigrams (cg)=1 gram (g)
10 decimeters (dm)=1 meter (m)
RATIONALE
Understanding metric and imperial unit conversions is fundamental for precise measurement in scientific and
everyday contexts, ensuring accuracy in calculations and communication. Mastery of these conversions, such as
knowing that 1 kilogram equals 1000 grams, facilitates effective data interpretation and application across various
disciplines.
Q4 QUESTION 4 OF 169
The prefixes kilo (= 1000), milli (= 1/1000), centi (= 1/100), and deci (= 1/10)
CORRECT ANSWER
are used with any metric unit, such as grams (weight), liters (volume), and meters (distance).
RATIONALE
Metric prefixes like kilo, milli, centi, and deci denote specific powers of ten, allowing for standardized communication
of measurements across various units such as grams, liters, and meters. This system enhances precision and clarity in
scientific and mathematical contexts.
Q5 QUESTION 5 OF 169
Page 3
, The original quantity and unit (to be converted) are multiplied by a conversion factor (which is a fraction made
up as follows):
New unit (on top) / Old unit (on bottom)
CORRECT ANSWER
48 ounces = ? pounds
48 o z × 1 p o u n d / 16 o z = 3 p o u n d s
4 kilograms = ? grams
4 Kg X 1000 grams/1kg = 4000 grams
1.) 656 cm x 1 m / 100 cm = 6.56 m
2.) 20 gal x 4 qt / 1 gal = 80 qts
3.) 7820 ml x 1 liter / 1000 ml = 7.82 liters
4.) 36 g x 1000 mg / 1 g = 36000 mg
5.) 25.3 g x 10 dc / 1 g = 253 dg
6.) 6.2 m x 1000 mm / 1 m = 6200 mm
7.) 725 l x 1000 ml / 1 liter = 725,000 ml
8.) 56 ft x 12 in / 1 ft = 672 in
RATIONALE
Multiplying by a conversion factor, which is structured as a fraction with the desired unit in the numerator and the
original unit in the denominator, allows for the systematic cancellation of units, ensuring accurate conversion to the
new measurement. This principle illustrates dimensional analysis, a fundamental concept in ensuring that calculations
maintain consistency across different units of measure.
Q6 QUESTION 6 OF 169
) D = M/V = 155 g / 50 ml =
CORRECT ANSWER
3.1 g/ml (division, volume contains only 2 sig figs)
RATIONALE
1 g/ml. This illustrates the importance of significant figures in scientific calculations to ensure accuracy and reliability
of results.
Q7 QUESTION 7 OF 169
Page 4
