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MCAT 2026 EXAM| BIOLOGICAL AND BIOCHEMICAL FOUNDATIONS OF LIVING SYSTEMS/ ACTUAL EXAM QUESTIONS AND CORRECT ANSWERS WITH RATIONALES GRADED A+ LATEST

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MCAT 2026 EXAM| BIOLOGICAL AND BIOCHEMICAL FOUNDATIONS OF LIVING SYSTEMS/ ACTUAL EXAM QUESTIONS AND CORRECT ANSWERS WITH RATIONALES GRADED A+ LATEST

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MCAT 2026 EXAM| BIOLOGICAL AND BIOCHEMICAL
FOUNDATIONS OF LIVING SYSTEMS/ ACTUAL EXAM
QUESTIONS AND CORRECT ANSWERS WITH
RATIONALES GRADED A+ LATEST


Question 1
Which statement best explains why oxygen consumption increases when
compound X is added?
A. Compound X directly donates electrons to oxygen, increasing consumption.
B. Compound X increases proton motive force, stimulating ATP synthase and
raising respiration.
C. Compound X dissipates the proton gradient so the electron transport chain
operates faster to re-establish it.
D. Compound X inhibits the electron transport chain, causing cells to consume
more oxygen to compensate.
Answer: C.
Rationale: An uncoupler increases proton leak across the inner mitochondrial
membrane, reducing the proton motive force. The ETC responds by pumping more
protons (i.e., increasing electron flow and oxygen consumption) to try to re-
establish the gradient. Option B is wrong — uncouplers lower the gradient, not
increase it. A is incorrect — uncouplers don't donate electrons. D is wrong —
inhibition would decrease electron flow and oxygen consumption.


Question 2
Given the oxygen consumption numbers, what does the relative increase in oxygen
consumption with pyruvate/malate vs succinate after uncoupler indicate about
upstream NADH vs FADH2 electron input?
A. NADH-linked respiration (Complex I entry) can produce a larger maximal
electron flux than Complex II under these conditions.

,B. FADH2 provides more electrons per substrate oxidation than NADH, so
succinate supports higher rates.
C. Complex II is inhibited by uncoupling agents, causing a smaller increase with
succinate.
D. Succinate-driven respiration is more efficient and therefore shows less change
with uncoupling.
Answer: A.
Rationale: Pyruvate/malate generates NADH that feeds electrons into Complex I;
succinate generates FADH2 feeding into Complex II. The larger jump with
pyruvate/malate (from 100 to 160) vs succinate (70 to 140) suggests the
NADH/Complex I pathway supports a larger maximal flux under uncoupled
conditions. B is false (both donate 2 electrons but enter at different complexes). C
has no basis here. D confuses efficiency with flux — uncoupling increases flux but
decreases coupling efficiency.


Question 3
If the researcher had added oligomycin (an ATP synthase inhibitor) before adding
compound X, what would you expect for oxygen consumption after adding the
uncoupler?
A. Oxygen consumption would remain low after oligomycin and not increase with
the uncoupler.
B. Oxygen consumption would still increase after uncoupler despite oligomycin,
because the uncoupler bypasses ATP synthase.
C. Oxygen consumption would equal zero because both ATP synthase and proton
gradient are blocked.
D. Oxygen consumption would be higher than with uncoupler alone.
Answer: B.
Rationale: Oligomycin blocks proton flow through ATP synthase, lowering
respiration because pmf isn't used to make ATP and backpressure reduces ETC
flux. Adding an uncoupler creates new proton leak pathways independent of ATP

,synthase, dissipating the gradient and driving ETC activity again — so oxygen
consumption rises even with oligomycin present. Thus B is correct.


Question 4
Which of the following best describes the effect of an increased proton leak on
ATP yield per oxygen consumed (P/O ratio)?
A. Proton leak increases the P/O ratio.
B. Proton leak does not change the P/O ratio.
C. Proton leak decreases the P/O ratio.
D. Proton leak initially increases then decreases the P/O ratio.
Answer: C.
Rationale: Proton leak causes protons to re-enter the matrix without passing
through ATP synthase, so fewer ATP molecules are generated per oxygen
consumed (lower P/O). Therefore ATP yield per oxygen decreases.


Discrete conceptual questions
Question 5
Which amino acid residue is most likely to act as a general base in an enzyme
active site (i.e., accept a proton during catalysis) at physiological pH?
A. Lysine
B. Aspartate
C. Phenylalanine
D. Tyrosine
Answer: B.
Rationale: Aspartate has a carboxylate side chain (pKa ~3.9) and is deprotonated
at physiological pH, allowing it to accept a proton transiently (act as a base).
Lysine is protonated at physiologic pH (pKa ~10.5) and usually acts as an acid or
electrostatic residue. Phenylalanine is nonpolar. Tyrosine has a pKa ~10 and is
mostly uncharged at pH 7.4.

, Question 6
A mutation changes a codon from UAU (tyrosine) to UAA (stop). What type of
mutation is this and what is the most likely immediate effect?
A. Missense mutation — single amino acid substituted, likely mild effect.
B. Nonsense mutation — premature termination leading to truncated protein.
C. Silent mutation — no change in amino acid or function.
D. Frameshift mutation — altered reading frame downstream.
Answer: B.
Rationale: UAA is a stop codon; changing a tyrosine codon (UAU) to UAA
introduces a premature termination codon — a nonsense mutation — resulting in a
truncated protein, likely loss of function or nonsense-mediated decay.


Question 7
Which bond in DNA is most directly broken by DNase I?
A. Phosphodiester backbone between nucleotides
B. Glycosidic bond between base and sugar
C. Hydrogen bonds between base pairs
D. Disulfide bonds in associated proteins
Answer: A.
Rationale: DNase I is an endonuclease that cleaves phosphodiester bonds within
the DNA backbone. It does not cleave glycosidic bonds, hydrogen bonds
(noncovalent), or protein disulfide bonds.


Question 8
During pulse-chase labeling with [35S]-methionine to study a secreted protein,
radioactivity first appears in the rough ER, then Golgi, then extracellular medium.
Which cellular process is this experiment is demonstrating?

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