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FIN 9762: Exam Version Eta Complete Solutions | 2026 Update - Baruch College, CUNY

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FIN 9762: Exam Version Eta Complete Solutions | 2026 Update - Baruch College, CUNY

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Fin 9762
Final Exam
Prof. Piskula
2025-12-17

Write your commitment to academic honesty. In your own words, include a commitment to
submit only your own work and to not supply others with help. (1 point deducted if missing.)

___________________________________________________________________________

___________________________________________________________________________

___________________________________________________________________________

___________________________________________________________________________

___________________________________________________________________________


Signed ______________________________________ Date __________

Print Name___________________________________


Do NOT begin until instructed to do so.
Version η
No one will be permitted to leave the room and return to continue working on
their test.

There will either be assigned seats or some students may be randomly moved
to different seats before the test.

No electronic devices are permitted for this test. All watches must be
removed.

Be sure to indicate your answers clearly, or you will not receive credit.

Penmanship, grammar and neatness will affect the grade.

There is a penalty of two points for any students that separates the pages of
the test, including separating the tables from the rest of the test.

,Fin 9762 Name:____________________________________
Final Exam, Prof. Piskula

All questions are one point unless otherwise noted. There are 25 points in total.

S&W Chapter 2 – Review of Probability

SW 2-1. (2 points) (instructor created) Calculate the marginal distributions of X and Y below.
Calculate E(X) and E(Y). Calculate the conditional probabilities and enter them in the spaces
provided. Demonstrate that X and Y below are independent or are not independent (so have a
conditional relationship).

E(X) = 0.3 E(Y) = 0.6

Y
0 1
0 0.2 0.5
X
1 0.2 0.1




P(X=1|Y=0) = __0.5__ P(X=1|Y=1) = _1/6__

P(X=0|Y=0) = __0.5__ P(X=0|Y=1) = 5/6___

P(Y=0|X=1) = _2/3___ P(Y=1|X=1) = _1/3__

P(Y=0|X=0) = _2/7___ P(Y=1|X=0) = 5/7___

Are the variables independent or conditional? Why?

Conditional because joints are not products of their marginals, and because marginal
probabilities do not equal the conditional probabilities.

, SW 2-2. (2 points) (instructor created) Recreate the grid of formulas for mean/expected value,
variance, covariance, and correlation. Arrange the formulas in four columns: theory (expected
value format), when you have the probabilities, when you have all the observations, and when
you have a sample. Consider using a landscape orientation.

See posted sheet.

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