UNIVERSITY OF NEW ENGLAND CHEM 1011 GENERAL CHEMISTRY II FINAL EXAM QUESTI… EXAM
P R O F E S S I O N A L P R A C T I C E M AT E R I A L S
University of New England
CHEM 1011 General Chemistry
II Final Exam Questions &
Answers 2026-2027
(Rationales)
Verified Answers Exam Ready With Rationales
93 QUESTIONS
DOCUMENT OVERVIEW
This document contains 93 verified questions with correct answers and detailed rationales, covering the
subject of General Chemistry II. Each question is designed to enhance understanding of key concepts,
providing students with a comprehensive resource for study, review, and certification preparation. The
inclusion of diagrams and images further aids in grasping complex topics, ensuring thorough
comprehension for exam success.
CONTENTS
01 Solubility Products Q1–Q13
02 Thermodynamics and Kinetics Q14–Q25
03 Nuclear Chemistry Q26–Q37
04 Entropy and Molecular Structure Q38–Q49
Page 1
, 05 Electrochemistry Q50–Q61
06 Chemical Equilibrium Q62–Q73
07 Titration and Acid-Base Chemistry Q74–Q85
08 Isotopes and Stability Q86–Q93
E XA M Q U EST I O N S
Q1 QUESTION 1 OF 93
The solubility product expression for the dissolution of Ca3(PO4)2 is
CORRECT ANSWER
Ksp = [Ca2+]3[PO43-]2
RATIONALE
The solubility product constant (Ksp) quantifies the equilibrium between a solid and its ions in solution, represented by the
concentrations of the ions raised to the power of their stoichiometric coefficients. For calcium phosphate, the dissolution yields
three calcium ions and two phosphate ions, forming the expression Ksp = [Ca2+]^3[PO4^3-]^2.
Q2 QUESTION 2 OF 93
The solubility product expression for the dissolution of BaS is
CORRECT ANSWER
Ksp = [Ba2+][S2-]
RATIONALE
Dissolution of barium sulfide (BaS) into its constituent ions, barium (Ba²⁺) and sulfide (S²⁻), establishes a dynamic equilibrium
where the solubility product constant (Ksp) quantifies the product of the molar concentrations of these ions when the solution
is saturated. This relationship reflects the principle of chemical equilibrium in saturated solutions.
Q3 QUESTION 3 OF 93
Page 2
,The solubility product expression for the dissolution of BaF2 is
CORRECT ANSWER
Ksp = [Ba2+][F-]2
RATIONALE
Dissolution of BaF2 results in the formation of Ba²⁺ and 2F⁻ ions, which establishes the equilibrium represented by the solubility
product constant, Ksp. This expression quantitatively describes the relationship between the concentrations of the ions in a
saturated solution, emphasizing that solubility is dependent on the ionic strengths of the products.
Q4 QUESTION 4 OF 93
A saturated solution of MgF2 has a small amount of solid AgCl at the bottom of the container. What is the effect of
adding K(NO3)2(aq) to a saturated solution of MgF2?
CORRECT ANSWER
MgF2(s) will stay the same
RATIONALE
Adding K(NO3)2(aq) does not affect the solubility equilibrium of MgF2 since it does not alter the concentration of ions involved
in that equilibrium. The presence of AgCl, which is insoluble, remains unchanged and does not influence the saturation point of
MgF2.
Q5 QUESTION 5 OF 93
In the dissolution of
PbCl2PbCl2(s) ⇌ Pb2+(aq) + 2 Cl-(aq)
Which of the following is true?
CORRECT ANSWER
Adding Pb(NO3)2(aq) will cause PbCl2(s) to increase
RATIONALE
Adding Pb(NO3)2 increases the concentration of Pb2+ ions in solution, shifting the dissolution equilibrium of PbCl2 to the left
according to Le Chatelier's principle, thereby promoting the precipitation of solid PbCl2. This demonstrates the principle of
dynamic equilibrium where a change in concentration of a reactant or product affects the position of equilibrium.
Q6 QUESTION 6 OF 93
Page 3
, The valence electrons in a pure sample of solid carbon
CORRECT ANSWER
are typically localized in very large covalent crystalline structures
RATIONALE
Covalent bonding in solid carbon leads to the formation of extensive three-dimensional networks, where valence electrons are
shared among numerous atoms, resulting in strong interatomic interactions within the crystalline structure. This localization of
electrons in large covalent networks accounts for carbon's unique properties, such as high melting point and hardness.
Q7 QUESTION 7 OF 93
Ionizing radiation can damage biological tissue by
CORRECT ANSWER
Removing electrons from molecules, disrupting the structure and function of tissue molecules
RATIONALE
Ionizing radiation interacts with biological tissues by imparting sufficient energy to remove electrons from atoms, resulting in
ionization that disrupts molecular structures and alters cellular functions. This process can lead to significant biochemical
changes, including DNA damage, which may result in cellular dysfunction or apoptosis.
Q8 QUESTION 8 OF 93
The Ksp for CaF2 is 4.0 x 10-11. What is the molar solubility of CaF2?
CORRECT ANSWER
Ksp = (S)(2S)^2
Ca2+ = S
F2- = 2S
Ksp = (4S)^3
4.0 * 10^- = (4S)^
1.0 * 10^-11 = S^3
cube root (1.0 * 10 ^-11)
S = 2.2 * 10^-4
RATIONALE
The molar solubility of CaF2 is determined by its dissociation in solution, where the solubility product constant (Ksp) equation
reflects the relationship between the concentrations of the ions produced; solving for S establishes the concentration of
dissolved CaF2, demonstrating the stoichiometric coefficients' influence on solubility. This calculation exemplifies the
application of chemical equilibrium principles in determining solubility from Ksp values.
Page 4
P R O F E S S I O N A L P R A C T I C E M AT E R I A L S
University of New England
CHEM 1011 General Chemistry
II Final Exam Questions &
Answers 2026-2027
(Rationales)
Verified Answers Exam Ready With Rationales
93 QUESTIONS
DOCUMENT OVERVIEW
This document contains 93 verified questions with correct answers and detailed rationales, covering the
subject of General Chemistry II. Each question is designed to enhance understanding of key concepts,
providing students with a comprehensive resource for study, review, and certification preparation. The
inclusion of diagrams and images further aids in grasping complex topics, ensuring thorough
comprehension for exam success.
CONTENTS
01 Solubility Products Q1–Q13
02 Thermodynamics and Kinetics Q14–Q25
03 Nuclear Chemistry Q26–Q37
04 Entropy and Molecular Structure Q38–Q49
Page 1
, 05 Electrochemistry Q50–Q61
06 Chemical Equilibrium Q62–Q73
07 Titration and Acid-Base Chemistry Q74–Q85
08 Isotopes and Stability Q86–Q93
E XA M Q U EST I O N S
Q1 QUESTION 1 OF 93
The solubility product expression for the dissolution of Ca3(PO4)2 is
CORRECT ANSWER
Ksp = [Ca2+]3[PO43-]2
RATIONALE
The solubility product constant (Ksp) quantifies the equilibrium between a solid and its ions in solution, represented by the
concentrations of the ions raised to the power of their stoichiometric coefficients. For calcium phosphate, the dissolution yields
three calcium ions and two phosphate ions, forming the expression Ksp = [Ca2+]^3[PO4^3-]^2.
Q2 QUESTION 2 OF 93
The solubility product expression for the dissolution of BaS is
CORRECT ANSWER
Ksp = [Ba2+][S2-]
RATIONALE
Dissolution of barium sulfide (BaS) into its constituent ions, barium (Ba²⁺) and sulfide (S²⁻), establishes a dynamic equilibrium
where the solubility product constant (Ksp) quantifies the product of the molar concentrations of these ions when the solution
is saturated. This relationship reflects the principle of chemical equilibrium in saturated solutions.
Q3 QUESTION 3 OF 93
Page 2
,The solubility product expression for the dissolution of BaF2 is
CORRECT ANSWER
Ksp = [Ba2+][F-]2
RATIONALE
Dissolution of BaF2 results in the formation of Ba²⁺ and 2F⁻ ions, which establishes the equilibrium represented by the solubility
product constant, Ksp. This expression quantitatively describes the relationship between the concentrations of the ions in a
saturated solution, emphasizing that solubility is dependent on the ionic strengths of the products.
Q4 QUESTION 4 OF 93
A saturated solution of MgF2 has a small amount of solid AgCl at the bottom of the container. What is the effect of
adding K(NO3)2(aq) to a saturated solution of MgF2?
CORRECT ANSWER
MgF2(s) will stay the same
RATIONALE
Adding K(NO3)2(aq) does not affect the solubility equilibrium of MgF2 since it does not alter the concentration of ions involved
in that equilibrium. The presence of AgCl, which is insoluble, remains unchanged and does not influence the saturation point of
MgF2.
Q5 QUESTION 5 OF 93
In the dissolution of
PbCl2PbCl2(s) ⇌ Pb2+(aq) + 2 Cl-(aq)
Which of the following is true?
CORRECT ANSWER
Adding Pb(NO3)2(aq) will cause PbCl2(s) to increase
RATIONALE
Adding Pb(NO3)2 increases the concentration of Pb2+ ions in solution, shifting the dissolution equilibrium of PbCl2 to the left
according to Le Chatelier's principle, thereby promoting the precipitation of solid PbCl2. This demonstrates the principle of
dynamic equilibrium where a change in concentration of a reactant or product affects the position of equilibrium.
Q6 QUESTION 6 OF 93
Page 3
, The valence electrons in a pure sample of solid carbon
CORRECT ANSWER
are typically localized in very large covalent crystalline structures
RATIONALE
Covalent bonding in solid carbon leads to the formation of extensive three-dimensional networks, where valence electrons are
shared among numerous atoms, resulting in strong interatomic interactions within the crystalline structure. This localization of
electrons in large covalent networks accounts for carbon's unique properties, such as high melting point and hardness.
Q7 QUESTION 7 OF 93
Ionizing radiation can damage biological tissue by
CORRECT ANSWER
Removing electrons from molecules, disrupting the structure and function of tissue molecules
RATIONALE
Ionizing radiation interacts with biological tissues by imparting sufficient energy to remove electrons from atoms, resulting in
ionization that disrupts molecular structures and alters cellular functions. This process can lead to significant biochemical
changes, including DNA damage, which may result in cellular dysfunction or apoptosis.
Q8 QUESTION 8 OF 93
The Ksp for CaF2 is 4.0 x 10-11. What is the molar solubility of CaF2?
CORRECT ANSWER
Ksp = (S)(2S)^2
Ca2+ = S
F2- = 2S
Ksp = (4S)^3
4.0 * 10^- = (4S)^
1.0 * 10^-11 = S^3
cube root (1.0 * 10 ^-11)
S = 2.2 * 10^-4
RATIONALE
The molar solubility of CaF2 is determined by its dissociation in solution, where the solubility product constant (Ksp) equation
reflects the relationship between the concentrations of the ions produced; solving for S establishes the concentration of
dissolved CaF2, demonstrating the stoichiometric coefficients' influence on solubility. This calculation exemplifies the
application of chemical equilibrium principles in determining solubility from Ksp values.
Page 4
