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CHEM 115 STUDY GUIDE EXAM 2026.pdf

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CHEM 115 STUDY GUIDE EXAM

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CHEM 115 STUDY GUIDE EXAM 2026/2027 QUESTIONS
AND SOLUTIONS RATED A+
✔✔Energy equation - ✔✔E=hv or E=hc/wavelength

✔✔1 Hz = - ✔✔1 wave per second

✔✔c= - ✔✔3.00 x 10^8 m/s

✔✔c= equation - ✔✔v*lamda (frequency * wavelength)

✔✔R= - ✔✔0.0821 L atm/mol K

✔✔(b) R= - ✔✔8.314 J/Kmol

✔✔1 J = - ✔✔1 kg m^2/s^2

✔✔1 amu= - ✔✔931.5 MeV

✔✔(b) 1 amu= - ✔✔1.66054 x 10^-27 kg

✔✔PV= - ✔✔nRT

✔✔ln(Nt/No)= - ✔✔-kt

✔✔Integrated Rate ln(No/Nt)= - ✔✔kt

✔✔t(1/2)= - ✔✔ln2/k=0.693/k

✔✔Nt/No= - ✔✔(1/2)^n (where n is number of half lives)

✔✔Rydberg Equation - ✔✔1/wavelength = R (1/n1^2 - 1/n2^2) for H atom, where n2>n1

✔✔R (Rydberg constant) - ✔✔(1.096776 x 10^7) /m

✔✔Bohr's Equation - ✔✔change in energy= -2.18x10^-18J(1/n2 final-1/n2 initial)

for H atom

✔✔En= - ✔✔-2.18 x10^-18 J (z^2/n^2)

✔✔Below band of stability - ✔✔Electron capture or positron emission, (proton becomes
a neutron) z reduced by 1

, ✔✔Above band of stability - ✔✔alpha decay,A reduces by 4 and Z reduces by 2

✔✔electron capture - ✔✔Z reduced by 1 and A unchanged

✔✔positron emission - ✔✔Z reduced by 1 A unchanged

✔✔Beta decay - ✔✔Z increases by 1 A unchanged

✔✔Gamma Emission decay - ✔✔no change in Z or A and accompanies Beta Decay
from excited nucleus , high energy

✔✔alpha decay - ✔✔Z decreases by 2 and A decreases by 4

✔✔conversion factor Angstrom to nm - ✔✔1 Angstrom = 0.1 nm

✔✔conversion factor MeV to J - ✔✔1 MeV = 1.602E-18 J

✔✔Quantum numbers: n - ✔✔principal quantum number, positive integer, the numbers
preceding electron configurations 1s^2, n=1, n determines the energy of the orbital thee
higher n is the higher the energy value

✔✔Quantum numbers: l - ✔✔angular momentum quantum number, integer 0 - (n-1),
value of l indicates shape of orbital

✔✔Quantum numbers: m1 - ✔✔magnetic quantum number, integer from -l to +l, the
value of m indicates spatial orientation of the orbital

✔✔Orbitals: s - ✔✔holds 2 electrons, sperical

✔✔Orbitals: p - ✔✔holds 6 electrons, l=1

✔✔Orbitals: d - ✔✔holds 10 electrons, l=2

✔✔percent error formula - ✔✔|accepted value-measured value| / accepted value x100

✔✔change in energy = - ✔✔change in nuclear binding energy

✔✔nuclear binding energy= - ✔✔1.68 E^-11 J / nuclide

✔✔1MeV/nuclide= - ✔✔1.6E^-13 J/nuclide

✔✔BE/nuclide - ✔✔NBE/mass number

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