WGU C960 – Discrete Mathematics II Objective Assessment Review Full Questions, Correct Answers, and Worked Solutions | 2026 Update | 100% Correct

What is the final value of abs after the following pseudocode is run? text x := 2 If (x 0) abs := x Else abs := -x End-if A) -2 B) 0 C) 2 D) 4 Answer: C Rationale: The condition (x 0) evaluates to true because x = 2. The line abs := x is executed, assigning the value 2 to abs. The Else branch is skipped entirely . Question 2 What is the final value of abs after the following pseudocode is run? text x := -2 If (x 0) abs := x Else abs := -x End-if A) -2 B) 0 C) 2 D) 4 Answer: C Rationale: The condition (x 0) evaluates to false because x = -2. The Else branch executes, setting abs := -x = -(-2) = 2 . Question 3 What is the final value of product after the following pseudocode runs? text product := 1 count := 5 While (count 0) product := product * count count := count - 2 End-while A) 3 B) 5 C) 15 D) 30 Answer: C Rationale: • Iteration 1: count = 5, product = 1 × 5 = 5, count becomes 3 • Iteration 2: count = 3, product = 5 × 3 = 15, count becomes 1 • The loop would execute a third iteration (count = 1), but the condition is checked at the start. Wait, let me recalculate: Actually, the loop executes while count 0: • Iteration 1: count=5 → product=5, count=3 • Iteration 2: count=3 → product=15, count=1 • Iteration 3: count=1 → product=15, count=-1 • Loop ends (count = -1) Final product = 15 Question 4 How many iterations will the loop in Question 3 execute? A) 1 B) 2 C) 3 D) 4 Answer: C Rationale: count values: 5, 3, 1. Each time count 0, the loop executes. When count becomes -1, the condition count 0 is false. The loop executes 3 iterations . Question 5 Consider the following pseudocode that merges two lists: text Merge0(List1, List2) Set OUTlist to empty While List1 is not empty OR List2 is not empty If one list is empty and the other is not, Remove the first number from the non-empty list and add it to OUTlist If both lists are non-empty, Remove the first number from List1 and add it to OUTlist Remove the first number from List2 and add it to OUTlist Return OUTlist If ListA = [1, 3, 5] and ListB = [2, 4, 6], what is the result of Merge0(ListA, Merge0(ListB, ListA))? A) [1, 2, 3, 4, 5, 6] B) [1, 2, 3, 1, 5, 4, 3, 6, 5] C) [2, 1, 4, 3, 6, 5] D) [2, 4, 6, 1, 3, 5] Answer: B Rationale: First compute the inner call: Merge0([2,4,6], [1,3,5]) produces [2,1,4,3,6,5]. Then the outer call: Merge0([1,3,5], [2,1,4,3,6,5]) produces [1,2,3,1,5,4,3,6,5] . Question 6 Given the following pseudocode, what is S at the end? text S = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20} x = 2 While(x 11): For i in S: If 0 ≡ i mod x and i ≠ x: delete i from S end-If end-For x = x + 1 end-While A) {2, 3, 5, 7, 9, 11, 13, 17, 19} B) {2, 3, 5, 7, 11, 13, 17, 19} C) {1, 2, 3, 5, 7, 11, 13, 17, 19} D) All numbers remain Answer: B Rationale: This is the Sieve of Eratosthenes algorithm. Starting with x=2, it removes all multiples of each number. After removing all composites, only primes remain: {2, 3, 5, 7, 11, 13, 17, 19} .